Sumarize leave time proportionally and correctly - mysql
In mysql database i created "leave" table:
CREATE TABLE `leave` (
`ID_LEAVE` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime DEFAULT NULL,
`END_DATE` datetime DEFAULT NULL
)
INSERT INTO `leave`
(`ID_LEAVE`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`) VALUES
(3, 26, '2019-03-20 07:00:00', '2019-03-21 15:00:00'),
(4, 22, '2019-03-20 07:00:00', '2019-03-20 15:00:00');
"Workers" table:
CREATE TABLE `workers` (
`ID_WORKER` int(11) NOT NULL,
`FNAME` varchar(20) NOT NULL,
`LNAME` varchar(20) NOT NULL
)
INSERT INTO `workers` (`ID_WORKER`, `FNAME`, `LNAME`) VALUES
(22, 'ALAN', 'FAST'),
(23, 'LEON', 'SPEED'),
(24, 'ADAM', 'GREEN'),
(25, 'DAVID', 'BUCS'),
(26, 'JACK', 'FAR'),
(27, 'ADAM', 'GAX'),
(28, 'ANDREW', 'WORM');
"Orders" table:
CREATE TABLE `orders` (
`ID_ORDER` int(11) NOT NULL,
`DESC_ORDER` varchar(50) NOT NULL,
`NUMBER_ORDER` varchar(30) NOT NULL
)
INSERT INTO `orders` (`ID_ORDER`, `DESC_ORDER`, `NUMBER_ORDER`) VALUES
(19, 'TEST', 'TEST'),
(20, 'TEST2', 'TEST2'),
(21, 'TEST3', 'TEST3'),
(22, 'TEST4', 'TEST4');
"Order_status" table (I'm sorry for that's not in order):
CREATE TABLE `order_status` (
`ID_STATUS` int(11) NOT NULL,
`ID_ORDER` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime NOT NULL,
`END_DATE` datetime NOT NULL,
`ORDER_DONE` tinyint(1) DEFAULT NULL
)
INSERT INTO `order_status` (`ID_STATUS`, `ID_ORDER`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`, `ORDER_DONE`) VALUES
(30, 19, 26, '2019-03-18 06:40:21', '2019-03-18 15:22:32', 'NO'),
(31, 19, 25, '2019-03-18 06:51:23', '2019-03-18 15:11:10', 'NO'),
(32, 19, 26, '2019-03-20 06:23:32', '2019-03-20 15:33:11', 'NO'),
(33, 19, 25, '2019-03-20 06:44:42', '2019-03-20 15:16:22', 'NO'),
(34, 19, 26, '2019-03-22 06:44:32', '2019-03-22 11:44:54', 'YES'),
(35, 19, 25, '2019-03-22 06:59:22', '2019-03-22 12:33:33', 'YES'),
(42, 20, 22, '2019-03-18 06:44:23', '2019-03-18 15:11:23', 'NO'),
(43, 20, 23, '2019-03-18 06:50:45', '2019-03-18 15:15:44', 'NO'),
(44, 20, 22, '2019-03-19 06:40:20', '2019-03-19 15:23:30', 'NO'),
(45, 20, 22, '2019-03-21 06:55:45', '2019-03-21 16:03:23', 'NO'),
(46, 20, 22, '2019-03-22 06:55:45', '2019-03-22 13:23:44', 'YES'),
(47, 20, 23, '2019-03-19 06:45:23', '2019-03-19 15:33:23', 'NO'),
(48, 20, 23, '2019-03-20 06:45:23', '2019-03-20 15:22:23', 'NO'),
(49, 20, 23, '2019-03-21 06:50:33', '2019-03-21 15:33:11', 'NO'),
(50, 20, 23, '2019-03-22 06:44:23', '2019-03-22 12:22:44', 'YES'),
(51, 21, 24, '2019-03-18 06:46:55', '2019-03-18 15:23:22', 'NO'),
(52, 21, 24, '2019-03-19 06:55:33', '2019-03-19 15:23:33', 'NO'),
(53, 21, 24, '2019-03-20 06:50:59', '2019-03-20 15:44:02', 'NO'),
(54, 21, 24, '2019-03-21 06:44:33', '2019-03-21 15:23:33', 'YES'),
(55, 21, 24, '2019-03-22 06:49:33', '2019-03-22 11:22:32', 'YES'),
(56, 22, 27, '2019-03-18 06:50:12', '2019-03-18 15:22:15', 'NO'),
(57, 22, 28, '2019-03-18 06:44:12', '2019-03-18 15:33:44', 'NO'),
(58, 22, 27, '2019-03-19 06:53:22', '2019-03-19 15:22:33', 'NO'),
(59, 22, 28, '2019-03-19 06:33:22', '2019-03-19 15:15:22', 'NO'),
(60, 22, 28, '2019-03-21 06:33:22', '2019-03-21 15:01:56', 'NO'),
(61, 22, 27, '2019-03-22 06:33:22', '2019-03-22 11:05:33', 'YES'),
(62, 22, 27, '2019-03-21 06:45:22', '2019-03-21 15:33:33', 'NO'),
(63, 22, 28, '2019-03-22 06:51:33', '2019-03-22 10:35:55', 'YES'),
(64, 19, 25, '2019-03-19 06:50:32', '2019-03-19 15:33:44', 'NO'),
(65, 19, 26, '2019-03-19 06:44:50', '2019-03-19 15:22:33', 'NO'),
(66, 19, 25, '2019-03-21 06:50:50', '2019-03-21 15:33:33', 'NO');
(67, 22, 27, '2019-03-20 06:51:32', '2019-03-20 15:20:33', 'NO');
What i've done:
I can to sumarize "Order time" of each other workers. I have selected workers (LNAME, FNAME) orders (DESC_ORDER and NUMBER_ORDER) and "TOTAL TIME" on order from each other workers correctly too. I wrote the mysql command in below:
SELECT workers.FNAME,
workers.LNAME,
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER,
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME'
FROM workers
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER,
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;
Then i get:
+---------+---------+---------------+------------+------------+
| FNAME | LNAME | NUMBER_ORDER | DESC_ORDER | ORDER TIME |
+---------+---------+---------------+------------+------------+
| DAVID | BUCS | TEST | TEST | 22:30:21 |
+---------+---------+---------------+------------+------------+
| JACK | FAR | TEST | TEST | 21:19:18 |
+---------+---------+---------------+------------+------------+
I've analyzed 2 days (20.03.2019 and 21.03.2019). Photos are in below:
Now i need mysql query that sumarize leave time correctly and PROPORTIONALLY to pattern described in below:
for example for leave time where ID_WORKER = 26 (he has order "TEST")
'08:31:40' '08:31:40'
(-------------------------------------------------) * 8:00:00 = (--------------) * 8:00:00 = 2:00:16
'08:31:40' + '08:37:00' + '08:53:03' + '08:29:01' '34:30:44'
What I've tried: I've tried sum leave time by mysql query in below:
SELECT workers.FNAME,
workers.LNAME,
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER,
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME',
IFNULL(SEC_TO_TIME(SUM(leaveAgg.ltime)),'00:00:00') AS 'LEAVE TIME'
FROM workers
LEFT JOIN (SELECT leave.ID_WORKER, SUM((datediff(leave.BEGIN_DATE, leave.END_DATE) + 1) * (time_to_sec(time(leave.END_DATE)) - time_to_sec(time(leave.BEGIN_DATE)))) AS ltime FROM leave
LEFT JOIN
(SELECT ID_WORKER, MIN(BEGIN_DATE) AS 'MIN_BEGIN_DATE', MAX(END_DATE) AS 'MAX_END_DATE'
FROM order_status GROUP BY ID_WORKER) ordstat ON
leave.ID_WORKER = ordstat.ID_WORKER
WHERE leave.END_DATE <= MAX_END_DATE AND leave.BEGIN_DATE >= MIN_BEGIN_DATE GROUP BY leave.ID_WORKER) leaveAgg
ON leaveAgg.ID_WORKER = workers.ID_WORKER
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER,
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;
But I'm afraid that isn't enough because it only adds for example:
22:30:21 + 8:00:00 = 30:30:21
I wanna get that result:
22:30:21 + 2:00:16 = 24:30:37
CAUTION! If someone get's 2 or more days of leaves i cannot do that like this:
'08:31:40'
(-------------------------------------------------) * 16:00:00
'08:31:40' + '08:37:00' + '08:53:03' + '08:29:01'
I have to analyze every day like that example where i explained.
I know that's more difficult question i cannot find any clue how to solve it. Can someone please what should i change or add. Thank you in advance for any help or advice.
mysql
New contributor
add a comment |
In mysql database i created "leave" table:
CREATE TABLE `leave` (
`ID_LEAVE` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime DEFAULT NULL,
`END_DATE` datetime DEFAULT NULL
)
INSERT INTO `leave`
(`ID_LEAVE`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`) VALUES
(3, 26, '2019-03-20 07:00:00', '2019-03-21 15:00:00'),
(4, 22, '2019-03-20 07:00:00', '2019-03-20 15:00:00');
"Workers" table:
CREATE TABLE `workers` (
`ID_WORKER` int(11) NOT NULL,
`FNAME` varchar(20) NOT NULL,
`LNAME` varchar(20) NOT NULL
)
INSERT INTO `workers` (`ID_WORKER`, `FNAME`, `LNAME`) VALUES
(22, 'ALAN', 'FAST'),
(23, 'LEON', 'SPEED'),
(24, 'ADAM', 'GREEN'),
(25, 'DAVID', 'BUCS'),
(26, 'JACK', 'FAR'),
(27, 'ADAM', 'GAX'),
(28, 'ANDREW', 'WORM');
"Orders" table:
CREATE TABLE `orders` (
`ID_ORDER` int(11) NOT NULL,
`DESC_ORDER` varchar(50) NOT NULL,
`NUMBER_ORDER` varchar(30) NOT NULL
)
INSERT INTO `orders` (`ID_ORDER`, `DESC_ORDER`, `NUMBER_ORDER`) VALUES
(19, 'TEST', 'TEST'),
(20, 'TEST2', 'TEST2'),
(21, 'TEST3', 'TEST3'),
(22, 'TEST4', 'TEST4');
"Order_status" table (I'm sorry for that's not in order):
CREATE TABLE `order_status` (
`ID_STATUS` int(11) NOT NULL,
`ID_ORDER` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime NOT NULL,
`END_DATE` datetime NOT NULL,
`ORDER_DONE` tinyint(1) DEFAULT NULL
)
INSERT INTO `order_status` (`ID_STATUS`, `ID_ORDER`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`, `ORDER_DONE`) VALUES
(30, 19, 26, '2019-03-18 06:40:21', '2019-03-18 15:22:32', 'NO'),
(31, 19, 25, '2019-03-18 06:51:23', '2019-03-18 15:11:10', 'NO'),
(32, 19, 26, '2019-03-20 06:23:32', '2019-03-20 15:33:11', 'NO'),
(33, 19, 25, '2019-03-20 06:44:42', '2019-03-20 15:16:22', 'NO'),
(34, 19, 26, '2019-03-22 06:44:32', '2019-03-22 11:44:54', 'YES'),
(35, 19, 25, '2019-03-22 06:59:22', '2019-03-22 12:33:33', 'YES'),
(42, 20, 22, '2019-03-18 06:44:23', '2019-03-18 15:11:23', 'NO'),
(43, 20, 23, '2019-03-18 06:50:45', '2019-03-18 15:15:44', 'NO'),
(44, 20, 22, '2019-03-19 06:40:20', '2019-03-19 15:23:30', 'NO'),
(45, 20, 22, '2019-03-21 06:55:45', '2019-03-21 16:03:23', 'NO'),
(46, 20, 22, '2019-03-22 06:55:45', '2019-03-22 13:23:44', 'YES'),
(47, 20, 23, '2019-03-19 06:45:23', '2019-03-19 15:33:23', 'NO'),
(48, 20, 23, '2019-03-20 06:45:23', '2019-03-20 15:22:23', 'NO'),
(49, 20, 23, '2019-03-21 06:50:33', '2019-03-21 15:33:11', 'NO'),
(50, 20, 23, '2019-03-22 06:44:23', '2019-03-22 12:22:44', 'YES'),
(51, 21, 24, '2019-03-18 06:46:55', '2019-03-18 15:23:22', 'NO'),
(52, 21, 24, '2019-03-19 06:55:33', '2019-03-19 15:23:33', 'NO'),
(53, 21, 24, '2019-03-20 06:50:59', '2019-03-20 15:44:02', 'NO'),
(54, 21, 24, '2019-03-21 06:44:33', '2019-03-21 15:23:33', 'YES'),
(55, 21, 24, '2019-03-22 06:49:33', '2019-03-22 11:22:32', 'YES'),
(56, 22, 27, '2019-03-18 06:50:12', '2019-03-18 15:22:15', 'NO'),
(57, 22, 28, '2019-03-18 06:44:12', '2019-03-18 15:33:44', 'NO'),
(58, 22, 27, '2019-03-19 06:53:22', '2019-03-19 15:22:33', 'NO'),
(59, 22, 28, '2019-03-19 06:33:22', '2019-03-19 15:15:22', 'NO'),
(60, 22, 28, '2019-03-21 06:33:22', '2019-03-21 15:01:56', 'NO'),
(61, 22, 27, '2019-03-22 06:33:22', '2019-03-22 11:05:33', 'YES'),
(62, 22, 27, '2019-03-21 06:45:22', '2019-03-21 15:33:33', 'NO'),
(63, 22, 28, '2019-03-22 06:51:33', '2019-03-22 10:35:55', 'YES'),
(64, 19, 25, '2019-03-19 06:50:32', '2019-03-19 15:33:44', 'NO'),
(65, 19, 26, '2019-03-19 06:44:50', '2019-03-19 15:22:33', 'NO'),
(66, 19, 25, '2019-03-21 06:50:50', '2019-03-21 15:33:33', 'NO');
(67, 22, 27, '2019-03-20 06:51:32', '2019-03-20 15:20:33', 'NO');
What i've done:
I can to sumarize "Order time" of each other workers. I have selected workers (LNAME, FNAME) orders (DESC_ORDER and NUMBER_ORDER) and "TOTAL TIME" on order from each other workers correctly too. I wrote the mysql command in below:
SELECT workers.FNAME,
workers.LNAME,
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER,
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME'
FROM workers
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER,
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;
Then i get:
+---------+---------+---------------+------------+------------+
| FNAME | LNAME | NUMBER_ORDER | DESC_ORDER | ORDER TIME |
+---------+---------+---------------+------------+------------+
| DAVID | BUCS | TEST | TEST | 22:30:21 |
+---------+---------+---------------+------------+------------+
| JACK | FAR | TEST | TEST | 21:19:18 |
+---------+---------+---------------+------------+------------+
I've analyzed 2 days (20.03.2019 and 21.03.2019). Photos are in below:
Now i need mysql query that sumarize leave time correctly and PROPORTIONALLY to pattern described in below:
for example for leave time where ID_WORKER = 26 (he has order "TEST")
'08:31:40' '08:31:40'
(-------------------------------------------------) * 8:00:00 = (--------------) * 8:00:00 = 2:00:16
'08:31:40' + '08:37:00' + '08:53:03' + '08:29:01' '34:30:44'
What I've tried: I've tried sum leave time by mysql query in below:
SELECT workers.FNAME,
workers.LNAME,
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER,
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME',
IFNULL(SEC_TO_TIME(SUM(leaveAgg.ltime)),'00:00:00') AS 'LEAVE TIME'
FROM workers
LEFT JOIN (SELECT leave.ID_WORKER, SUM((datediff(leave.BEGIN_DATE, leave.END_DATE) + 1) * (time_to_sec(time(leave.END_DATE)) - time_to_sec(time(leave.BEGIN_DATE)))) AS ltime FROM leave
LEFT JOIN
(SELECT ID_WORKER, MIN(BEGIN_DATE) AS 'MIN_BEGIN_DATE', MAX(END_DATE) AS 'MAX_END_DATE'
FROM order_status GROUP BY ID_WORKER) ordstat ON
leave.ID_WORKER = ordstat.ID_WORKER
WHERE leave.END_DATE <= MAX_END_DATE AND leave.BEGIN_DATE >= MIN_BEGIN_DATE GROUP BY leave.ID_WORKER) leaveAgg
ON leaveAgg.ID_WORKER = workers.ID_WORKER
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER,
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;
But I'm afraid that isn't enough because it only adds for example:
22:30:21 + 8:00:00 = 30:30:21
I wanna get that result:
22:30:21 + 2:00:16 = 24:30:37
CAUTION! If someone get's 2 or more days of leaves i cannot do that like this:
'08:31:40'
(-------------------------------------------------) * 16:00:00
'08:31:40' + '08:37:00' + '08:53:03' + '08:29:01'
I have to analyze every day like that example where i explained.
I know that's more difficult question i cannot find any clue how to solve it. Can someone please what should i change or add. Thank you in advance for any help or advice.
mysql
New contributor
add a comment |
In mysql database i created "leave" table:
CREATE TABLE `leave` (
`ID_LEAVE` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime DEFAULT NULL,
`END_DATE` datetime DEFAULT NULL
)
INSERT INTO `leave`
(`ID_LEAVE`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`) VALUES
(3, 26, '2019-03-20 07:00:00', '2019-03-21 15:00:00'),
(4, 22, '2019-03-20 07:00:00', '2019-03-20 15:00:00');
"Workers" table:
CREATE TABLE `workers` (
`ID_WORKER` int(11) NOT NULL,
`FNAME` varchar(20) NOT NULL,
`LNAME` varchar(20) NOT NULL
)
INSERT INTO `workers` (`ID_WORKER`, `FNAME`, `LNAME`) VALUES
(22, 'ALAN', 'FAST'),
(23, 'LEON', 'SPEED'),
(24, 'ADAM', 'GREEN'),
(25, 'DAVID', 'BUCS'),
(26, 'JACK', 'FAR'),
(27, 'ADAM', 'GAX'),
(28, 'ANDREW', 'WORM');
"Orders" table:
CREATE TABLE `orders` (
`ID_ORDER` int(11) NOT NULL,
`DESC_ORDER` varchar(50) NOT NULL,
`NUMBER_ORDER` varchar(30) NOT NULL
)
INSERT INTO `orders` (`ID_ORDER`, `DESC_ORDER`, `NUMBER_ORDER`) VALUES
(19, 'TEST', 'TEST'),
(20, 'TEST2', 'TEST2'),
(21, 'TEST3', 'TEST3'),
(22, 'TEST4', 'TEST4');
"Order_status" table (I'm sorry for that's not in order):
CREATE TABLE `order_status` (
`ID_STATUS` int(11) NOT NULL,
`ID_ORDER` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime NOT NULL,
`END_DATE` datetime NOT NULL,
`ORDER_DONE` tinyint(1) DEFAULT NULL
)
INSERT INTO `order_status` (`ID_STATUS`, `ID_ORDER`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`, `ORDER_DONE`) VALUES
(30, 19, 26, '2019-03-18 06:40:21', '2019-03-18 15:22:32', 'NO'),
(31, 19, 25, '2019-03-18 06:51:23', '2019-03-18 15:11:10', 'NO'),
(32, 19, 26, '2019-03-20 06:23:32', '2019-03-20 15:33:11', 'NO'),
(33, 19, 25, '2019-03-20 06:44:42', '2019-03-20 15:16:22', 'NO'),
(34, 19, 26, '2019-03-22 06:44:32', '2019-03-22 11:44:54', 'YES'),
(35, 19, 25, '2019-03-22 06:59:22', '2019-03-22 12:33:33', 'YES'),
(42, 20, 22, '2019-03-18 06:44:23', '2019-03-18 15:11:23', 'NO'),
(43, 20, 23, '2019-03-18 06:50:45', '2019-03-18 15:15:44', 'NO'),
(44, 20, 22, '2019-03-19 06:40:20', '2019-03-19 15:23:30', 'NO'),
(45, 20, 22, '2019-03-21 06:55:45', '2019-03-21 16:03:23', 'NO'),
(46, 20, 22, '2019-03-22 06:55:45', '2019-03-22 13:23:44', 'YES'),
(47, 20, 23, '2019-03-19 06:45:23', '2019-03-19 15:33:23', 'NO'),
(48, 20, 23, '2019-03-20 06:45:23', '2019-03-20 15:22:23', 'NO'),
(49, 20, 23, '2019-03-21 06:50:33', '2019-03-21 15:33:11', 'NO'),
(50, 20, 23, '2019-03-22 06:44:23', '2019-03-22 12:22:44', 'YES'),
(51, 21, 24, '2019-03-18 06:46:55', '2019-03-18 15:23:22', 'NO'),
(52, 21, 24, '2019-03-19 06:55:33', '2019-03-19 15:23:33', 'NO'),
(53, 21, 24, '2019-03-20 06:50:59', '2019-03-20 15:44:02', 'NO'),
(54, 21, 24, '2019-03-21 06:44:33', '2019-03-21 15:23:33', 'YES'),
(55, 21, 24, '2019-03-22 06:49:33', '2019-03-22 11:22:32', 'YES'),
(56, 22, 27, '2019-03-18 06:50:12', '2019-03-18 15:22:15', 'NO'),
(57, 22, 28, '2019-03-18 06:44:12', '2019-03-18 15:33:44', 'NO'),
(58, 22, 27, '2019-03-19 06:53:22', '2019-03-19 15:22:33', 'NO'),
(59, 22, 28, '2019-03-19 06:33:22', '2019-03-19 15:15:22', 'NO'),
(60, 22, 28, '2019-03-21 06:33:22', '2019-03-21 15:01:56', 'NO'),
(61, 22, 27, '2019-03-22 06:33:22', '2019-03-22 11:05:33', 'YES'),
(62, 22, 27, '2019-03-21 06:45:22', '2019-03-21 15:33:33', 'NO'),
(63, 22, 28, '2019-03-22 06:51:33', '2019-03-22 10:35:55', 'YES'),
(64, 19, 25, '2019-03-19 06:50:32', '2019-03-19 15:33:44', 'NO'),
(65, 19, 26, '2019-03-19 06:44:50', '2019-03-19 15:22:33', 'NO'),
(66, 19, 25, '2019-03-21 06:50:50', '2019-03-21 15:33:33', 'NO');
(67, 22, 27, '2019-03-20 06:51:32', '2019-03-20 15:20:33', 'NO');
What i've done:
I can to sumarize "Order time" of each other workers. I have selected workers (LNAME, FNAME) orders (DESC_ORDER and NUMBER_ORDER) and "TOTAL TIME" on order from each other workers correctly too. I wrote the mysql command in below:
SELECT workers.FNAME,
workers.LNAME,
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER,
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME'
FROM workers
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER,
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;
Then i get:
+---------+---------+---------------+------------+------------+
| FNAME | LNAME | NUMBER_ORDER | DESC_ORDER | ORDER TIME |
+---------+---------+---------------+------------+------------+
| DAVID | BUCS | TEST | TEST | 22:30:21 |
+---------+---------+---------------+------------+------------+
| JACK | FAR | TEST | TEST | 21:19:18 |
+---------+---------+---------------+------------+------------+
I've analyzed 2 days (20.03.2019 and 21.03.2019). Photos are in below:
Now i need mysql query that sumarize leave time correctly and PROPORTIONALLY to pattern described in below:
for example for leave time where ID_WORKER = 26 (he has order "TEST")
'08:31:40' '08:31:40'
(-------------------------------------------------) * 8:00:00 = (--------------) * 8:00:00 = 2:00:16
'08:31:40' + '08:37:00' + '08:53:03' + '08:29:01' '34:30:44'
What I've tried: I've tried sum leave time by mysql query in below:
SELECT workers.FNAME,
workers.LNAME,
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER,
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME',
IFNULL(SEC_TO_TIME(SUM(leaveAgg.ltime)),'00:00:00') AS 'LEAVE TIME'
FROM workers
LEFT JOIN (SELECT leave.ID_WORKER, SUM((datediff(leave.BEGIN_DATE, leave.END_DATE) + 1) * (time_to_sec(time(leave.END_DATE)) - time_to_sec(time(leave.BEGIN_DATE)))) AS ltime FROM leave
LEFT JOIN
(SELECT ID_WORKER, MIN(BEGIN_DATE) AS 'MIN_BEGIN_DATE', MAX(END_DATE) AS 'MAX_END_DATE'
FROM order_status GROUP BY ID_WORKER) ordstat ON
leave.ID_WORKER = ordstat.ID_WORKER
WHERE leave.END_DATE <= MAX_END_DATE AND leave.BEGIN_DATE >= MIN_BEGIN_DATE GROUP BY leave.ID_WORKER) leaveAgg
ON leaveAgg.ID_WORKER = workers.ID_WORKER
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER,
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;
But I'm afraid that isn't enough because it only adds for example:
22:30:21 + 8:00:00 = 30:30:21
I wanna get that result:
22:30:21 + 2:00:16 = 24:30:37
CAUTION! If someone get's 2 or more days of leaves i cannot do that like this:
'08:31:40'
(-------------------------------------------------) * 16:00:00
'08:31:40' + '08:37:00' + '08:53:03' + '08:29:01'
I have to analyze every day like that example where i explained.
I know that's more difficult question i cannot find any clue how to solve it. Can someone please what should i change or add. Thank you in advance for any help or advice.
mysql
New contributor
In mysql database i created "leave" table:
CREATE TABLE `leave` (
`ID_LEAVE` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime DEFAULT NULL,
`END_DATE` datetime DEFAULT NULL
)
INSERT INTO `leave`
(`ID_LEAVE`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`) VALUES
(3, 26, '2019-03-20 07:00:00', '2019-03-21 15:00:00'),
(4, 22, '2019-03-20 07:00:00', '2019-03-20 15:00:00');
"Workers" table:
CREATE TABLE `workers` (
`ID_WORKER` int(11) NOT NULL,
`FNAME` varchar(20) NOT NULL,
`LNAME` varchar(20) NOT NULL
)
INSERT INTO `workers` (`ID_WORKER`, `FNAME`, `LNAME`) VALUES
(22, 'ALAN', 'FAST'),
(23, 'LEON', 'SPEED'),
(24, 'ADAM', 'GREEN'),
(25, 'DAVID', 'BUCS'),
(26, 'JACK', 'FAR'),
(27, 'ADAM', 'GAX'),
(28, 'ANDREW', 'WORM');
"Orders" table:
CREATE TABLE `orders` (
`ID_ORDER` int(11) NOT NULL,
`DESC_ORDER` varchar(50) NOT NULL,
`NUMBER_ORDER` varchar(30) NOT NULL
)
INSERT INTO `orders` (`ID_ORDER`, `DESC_ORDER`, `NUMBER_ORDER`) VALUES
(19, 'TEST', 'TEST'),
(20, 'TEST2', 'TEST2'),
(21, 'TEST3', 'TEST3'),
(22, 'TEST4', 'TEST4');
"Order_status" table (I'm sorry for that's not in order):
CREATE TABLE `order_status` (
`ID_STATUS` int(11) NOT NULL,
`ID_ORDER` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime NOT NULL,
`END_DATE` datetime NOT NULL,
`ORDER_DONE` tinyint(1) DEFAULT NULL
)
INSERT INTO `order_status` (`ID_STATUS`, `ID_ORDER`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`, `ORDER_DONE`) VALUES
(30, 19, 26, '2019-03-18 06:40:21', '2019-03-18 15:22:32', 'NO'),
(31, 19, 25, '2019-03-18 06:51:23', '2019-03-18 15:11:10', 'NO'),
(32, 19, 26, '2019-03-20 06:23:32', '2019-03-20 15:33:11', 'NO'),
(33, 19, 25, '2019-03-20 06:44:42', '2019-03-20 15:16:22', 'NO'),
(34, 19, 26, '2019-03-22 06:44:32', '2019-03-22 11:44:54', 'YES'),
(35, 19, 25, '2019-03-22 06:59:22', '2019-03-22 12:33:33', 'YES'),
(42, 20, 22, '2019-03-18 06:44:23', '2019-03-18 15:11:23', 'NO'),
(43, 20, 23, '2019-03-18 06:50:45', '2019-03-18 15:15:44', 'NO'),
(44, 20, 22, '2019-03-19 06:40:20', '2019-03-19 15:23:30', 'NO'),
(45, 20, 22, '2019-03-21 06:55:45', '2019-03-21 16:03:23', 'NO'),
(46, 20, 22, '2019-03-22 06:55:45', '2019-03-22 13:23:44', 'YES'),
(47, 20, 23, '2019-03-19 06:45:23', '2019-03-19 15:33:23', 'NO'),
(48, 20, 23, '2019-03-20 06:45:23', '2019-03-20 15:22:23', 'NO'),
(49, 20, 23, '2019-03-21 06:50:33', '2019-03-21 15:33:11', 'NO'),
(50, 20, 23, '2019-03-22 06:44:23', '2019-03-22 12:22:44', 'YES'),
(51, 21, 24, '2019-03-18 06:46:55', '2019-03-18 15:23:22', 'NO'),
(52, 21, 24, '2019-03-19 06:55:33', '2019-03-19 15:23:33', 'NO'),
(53, 21, 24, '2019-03-20 06:50:59', '2019-03-20 15:44:02', 'NO'),
(54, 21, 24, '2019-03-21 06:44:33', '2019-03-21 15:23:33', 'YES'),
(55, 21, 24, '2019-03-22 06:49:33', '2019-03-22 11:22:32', 'YES'),
(56, 22, 27, '2019-03-18 06:50:12', '2019-03-18 15:22:15', 'NO'),
(57, 22, 28, '2019-03-18 06:44:12', '2019-03-18 15:33:44', 'NO'),
(58, 22, 27, '2019-03-19 06:53:22', '2019-03-19 15:22:33', 'NO'),
(59, 22, 28, '2019-03-19 06:33:22', '2019-03-19 15:15:22', 'NO'),
(60, 22, 28, '2019-03-21 06:33:22', '2019-03-21 15:01:56', 'NO'),
(61, 22, 27, '2019-03-22 06:33:22', '2019-03-22 11:05:33', 'YES'),
(62, 22, 27, '2019-03-21 06:45:22', '2019-03-21 15:33:33', 'NO'),
(63, 22, 28, '2019-03-22 06:51:33', '2019-03-22 10:35:55', 'YES'),
(64, 19, 25, '2019-03-19 06:50:32', '2019-03-19 15:33:44', 'NO'),
(65, 19, 26, '2019-03-19 06:44:50', '2019-03-19 15:22:33', 'NO'),
(66, 19, 25, '2019-03-21 06:50:50', '2019-03-21 15:33:33', 'NO');
(67, 22, 27, '2019-03-20 06:51:32', '2019-03-20 15:20:33', 'NO');
What i've done:
I can to sumarize "Order time" of each other workers. I have selected workers (LNAME, FNAME) orders (DESC_ORDER and NUMBER_ORDER) and "TOTAL TIME" on order from each other workers correctly too. I wrote the mysql command in below:
SELECT workers.FNAME,
workers.LNAME,
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER,
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME'
FROM workers
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER,
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;
Then i get:
+---------+---------+---------------+------------+------------+
| FNAME | LNAME | NUMBER_ORDER | DESC_ORDER | ORDER TIME |
+---------+---------+---------------+------------+------------+
| DAVID | BUCS | TEST | TEST | 22:30:21 |
+---------+---------+---------------+------------+------------+
| JACK | FAR | TEST | TEST | 21:19:18 |
+---------+---------+---------------+------------+------------+
I've analyzed 2 days (20.03.2019 and 21.03.2019). Photos are in below:
Now i need mysql query that sumarize leave time correctly and PROPORTIONALLY to pattern described in below:
for example for leave time where ID_WORKER = 26 (he has order "TEST")
'08:31:40' '08:31:40'
(-------------------------------------------------) * 8:00:00 = (--------------) * 8:00:00 = 2:00:16
'08:31:40' + '08:37:00' + '08:53:03' + '08:29:01' '34:30:44'
What I've tried: I've tried sum leave time by mysql query in below:
SELECT workers.FNAME,
workers.LNAME,
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER,
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME',
IFNULL(SEC_TO_TIME(SUM(leaveAgg.ltime)),'00:00:00') AS 'LEAVE TIME'
FROM workers
LEFT JOIN (SELECT leave.ID_WORKER, SUM((datediff(leave.BEGIN_DATE, leave.END_DATE) + 1) * (time_to_sec(time(leave.END_DATE)) - time_to_sec(time(leave.BEGIN_DATE)))) AS ltime FROM leave
LEFT JOIN
(SELECT ID_WORKER, MIN(BEGIN_DATE) AS 'MIN_BEGIN_DATE', MAX(END_DATE) AS 'MAX_END_DATE'
FROM order_status GROUP BY ID_WORKER) ordstat ON
leave.ID_WORKER = ordstat.ID_WORKER
WHERE leave.END_DATE <= MAX_END_DATE AND leave.BEGIN_DATE >= MIN_BEGIN_DATE GROUP BY leave.ID_WORKER) leaveAgg
ON leaveAgg.ID_WORKER = workers.ID_WORKER
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER,
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;
But I'm afraid that isn't enough because it only adds for example:
22:30:21 + 8:00:00 = 30:30:21
I wanna get that result:
22:30:21 + 2:00:16 = 24:30:37
CAUTION! If someone get's 2 or more days of leaves i cannot do that like this:
'08:31:40'
(-------------------------------------------------) * 16:00:00
'08:31:40' + '08:37:00' + '08:53:03' + '08:29:01'
I have to analyze every day like that example where i explained.
I know that's more difficult question i cannot find any clue how to solve it. Can someone please what should i change or add. Thank you in advance for any help or advice.
mysql
mysql
New contributor
New contributor
New contributor
asked 2 mins ago
Prochu1991Prochu1991
1
1
New contributor
New contributor
add a comment |
add a comment |
0
active
oldest
votes
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "182"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Prochu1991 is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f233711%2fsumarize-leave-time-proportionally-and-correctly-mysql%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Prochu1991 is a new contributor. Be nice, and check out our Code of Conduct.
Prochu1991 is a new contributor. Be nice, and check out our Code of Conduct.
Prochu1991 is a new contributor. Be nice, and check out our Code of Conduct.
Prochu1991 is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Database Administrators Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f233711%2fsumarize-leave-time-proportionally-and-correctly-mysql%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown