sum only different id's values with any aggreagte function in postgresql
I need your help. Let's assume that we have a table like below
+---------------+-------+--------+----------+
| barcode | shop | id | entrance |
+---------------+-------+--------+----------+
| 2014708941747 | shop1 | 3587 | 2 |
| 2014708941747 | shop2 | 3587 | 2 |
| 2014708941747 | shop3 | 3587 | 2 |
| 2014708941747 | shop4 | 3587 | 2 |
| 2014708941747 | shop5 | 3587 | 2 |
| 2014708941747 | shop6 | 3587 | 2 |
| 2014708941747 | shop7 | 3587 | 2 |
| 2014708941747 | shop1 | 44791 | 2 |
| 2014708941747 | shop8 | 65846 | 0 |
| 2014708941747 | shop9 | 83246 | 0 |
| 2014708941747 | shop3 | 92705 | 22 |
| 2014708941747 | shop4 | 98014 | 8 |
| 2014708941747 | shop2 | 103612 | 12 |
| 2014708941747 | shop5 | 109961 | 19 |
| 2014708941747 | shop6 | 115025 | 6 |
| 2014708941747 | shop7 | 126898 | 144 |
+---------------+-------+--------+----------+
Now I want to know how many quantities exist for the given barcode but id
must not be repeated. With the above example, our result must be like below
+---------------+----------+
| barcode | entrance |
+---------------+----------+
| 2014708941747 | 225 |
+---------------+----------+
If I do this with a traditional group by entrance=227
which is not correct. Is there any aggregate function to solve this kind of problem?
group-by aggregate postgresql-9.6 window-functions sum
New contributor
add a comment |
I need your help. Let's assume that we have a table like below
+---------------+-------+--------+----------+
| barcode | shop | id | entrance |
+---------------+-------+--------+----------+
| 2014708941747 | shop1 | 3587 | 2 |
| 2014708941747 | shop2 | 3587 | 2 |
| 2014708941747 | shop3 | 3587 | 2 |
| 2014708941747 | shop4 | 3587 | 2 |
| 2014708941747 | shop5 | 3587 | 2 |
| 2014708941747 | shop6 | 3587 | 2 |
| 2014708941747 | shop7 | 3587 | 2 |
| 2014708941747 | shop1 | 44791 | 2 |
| 2014708941747 | shop8 | 65846 | 0 |
| 2014708941747 | shop9 | 83246 | 0 |
| 2014708941747 | shop3 | 92705 | 22 |
| 2014708941747 | shop4 | 98014 | 8 |
| 2014708941747 | shop2 | 103612 | 12 |
| 2014708941747 | shop5 | 109961 | 19 |
| 2014708941747 | shop6 | 115025 | 6 |
| 2014708941747 | shop7 | 126898 | 144 |
+---------------+-------+--------+----------+
Now I want to know how many quantities exist for the given barcode but id
must not be repeated. With the above example, our result must be like below
+---------------+----------+
| barcode | entrance |
+---------------+----------+
| 2014708941747 | 225 |
+---------------+----------+
If I do this with a traditional group by entrance=227
which is not correct. Is there any aggregate function to solve this kind of problem?
group-by aggregate postgresql-9.6 window-functions sum
New contributor
What if there are different values for an ID?
– sticky bit
20 mins ago
@stickybit there is no such case
– sakit
16 mins ago
add a comment |
I need your help. Let's assume that we have a table like below
+---------------+-------+--------+----------+
| barcode | shop | id | entrance |
+---------------+-------+--------+----------+
| 2014708941747 | shop1 | 3587 | 2 |
| 2014708941747 | shop2 | 3587 | 2 |
| 2014708941747 | shop3 | 3587 | 2 |
| 2014708941747 | shop4 | 3587 | 2 |
| 2014708941747 | shop5 | 3587 | 2 |
| 2014708941747 | shop6 | 3587 | 2 |
| 2014708941747 | shop7 | 3587 | 2 |
| 2014708941747 | shop1 | 44791 | 2 |
| 2014708941747 | shop8 | 65846 | 0 |
| 2014708941747 | shop9 | 83246 | 0 |
| 2014708941747 | shop3 | 92705 | 22 |
| 2014708941747 | shop4 | 98014 | 8 |
| 2014708941747 | shop2 | 103612 | 12 |
| 2014708941747 | shop5 | 109961 | 19 |
| 2014708941747 | shop6 | 115025 | 6 |
| 2014708941747 | shop7 | 126898 | 144 |
+---------------+-------+--------+----------+
Now I want to know how many quantities exist for the given barcode but id
must not be repeated. With the above example, our result must be like below
+---------------+----------+
| barcode | entrance |
+---------------+----------+
| 2014708941747 | 225 |
+---------------+----------+
If I do this with a traditional group by entrance=227
which is not correct. Is there any aggregate function to solve this kind of problem?
group-by aggregate postgresql-9.6 window-functions sum
New contributor
I need your help. Let's assume that we have a table like below
+---------------+-------+--------+----------+
| barcode | shop | id | entrance |
+---------------+-------+--------+----------+
| 2014708941747 | shop1 | 3587 | 2 |
| 2014708941747 | shop2 | 3587 | 2 |
| 2014708941747 | shop3 | 3587 | 2 |
| 2014708941747 | shop4 | 3587 | 2 |
| 2014708941747 | shop5 | 3587 | 2 |
| 2014708941747 | shop6 | 3587 | 2 |
| 2014708941747 | shop7 | 3587 | 2 |
| 2014708941747 | shop1 | 44791 | 2 |
| 2014708941747 | shop8 | 65846 | 0 |
| 2014708941747 | shop9 | 83246 | 0 |
| 2014708941747 | shop3 | 92705 | 22 |
| 2014708941747 | shop4 | 98014 | 8 |
| 2014708941747 | shop2 | 103612 | 12 |
| 2014708941747 | shop5 | 109961 | 19 |
| 2014708941747 | shop6 | 115025 | 6 |
| 2014708941747 | shop7 | 126898 | 144 |
+---------------+-------+--------+----------+
Now I want to know how many quantities exist for the given barcode but id
must not be repeated. With the above example, our result must be like below
+---------------+----------+
| barcode | entrance |
+---------------+----------+
| 2014708941747 | 225 |
+---------------+----------+
If I do this with a traditional group by entrance=227
which is not correct. Is there any aggregate function to solve this kind of problem?
group-by aggregate postgresql-9.6 window-functions sum
group-by aggregate postgresql-9.6 window-functions sum
New contributor
New contributor
edited 11 mins ago
sakit
New contributor
asked 30 mins ago
sakitsakit
11
11
New contributor
New contributor
What if there are different values for an ID?
– sticky bit
20 mins ago
@stickybit there is no such case
– sakit
16 mins ago
add a comment |
What if there are different values for an ID?
– sticky bit
20 mins ago
@stickybit there is no such case
– sakit
16 mins ago
What if there are different values for an ID?
– sticky bit
20 mins ago
What if there are different values for an ID?
– sticky bit
20 mins ago
@stickybit there is no such case
– sakit
16 mins ago
@stickybit there is no such case
– sakit
16 mins ago
add a comment |
1 Answer
1
active
oldest
votes
If entrance is always the same per barcode and ID you could first group by barcode and id taking the max entrance and then get the sum grouping by barcode.
SELECT x.barcode,
sum(x.entrance) entrance
FROM (SELECT t.barcode,
t.id,
max(t.entrance) entrance
FROM elbat t
GROUP BY t.barcode,
t.id) x
GROUP BY x.barcode;
thanks for your response. But I search that is there any predefined functions in Postgres like window functions.
– sakit
6 mins ago
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If entrance is always the same per barcode and ID you could first group by barcode and id taking the max entrance and then get the sum grouping by barcode.
SELECT x.barcode,
sum(x.entrance) entrance
FROM (SELECT t.barcode,
t.id,
max(t.entrance) entrance
FROM elbat t
GROUP BY t.barcode,
t.id) x
GROUP BY x.barcode;
thanks for your response. But I search that is there any predefined functions in Postgres like window functions.
– sakit
6 mins ago
add a comment |
If entrance is always the same per barcode and ID you could first group by barcode and id taking the max entrance and then get the sum grouping by barcode.
SELECT x.barcode,
sum(x.entrance) entrance
FROM (SELECT t.barcode,
t.id,
max(t.entrance) entrance
FROM elbat t
GROUP BY t.barcode,
t.id) x
GROUP BY x.barcode;
thanks for your response. But I search that is there any predefined functions in Postgres like window functions.
– sakit
6 mins ago
add a comment |
If entrance is always the same per barcode and ID you could first group by barcode and id taking the max entrance and then get the sum grouping by barcode.
SELECT x.barcode,
sum(x.entrance) entrance
FROM (SELECT t.barcode,
t.id,
max(t.entrance) entrance
FROM elbat t
GROUP BY t.barcode,
t.id) x
GROUP BY x.barcode;
If entrance is always the same per barcode and ID you could first group by barcode and id taking the max entrance and then get the sum grouping by barcode.
SELECT x.barcode,
sum(x.entrance) entrance
FROM (SELECT t.barcode,
t.id,
max(t.entrance) entrance
FROM elbat t
GROUP BY t.barcode,
t.id) x
GROUP BY x.barcode;
answered 11 mins ago
sticky bitsticky bit
1,713314
1,713314
thanks for your response. But I search that is there any predefined functions in Postgres like window functions.
– sakit
6 mins ago
add a comment |
thanks for your response. But I search that is there any predefined functions in Postgres like window functions.
– sakit
6 mins ago
thanks for your response. But I search that is there any predefined functions in Postgres like window functions.
– sakit
6 mins ago
thanks for your response. But I search that is there any predefined functions in Postgres like window functions.
– sakit
6 mins ago
add a comment |
sakit is a new contributor. Be nice, and check out our Code of Conduct.
sakit is a new contributor. Be nice, and check out our Code of Conduct.
sakit is a new contributor. Be nice, and check out our Code of Conduct.
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What if there are different values for an ID?
– sticky bit
20 mins ago
@stickybit there is no such case
– sakit
16 mins ago