Query Error when trying to run query
Please bear with me as I am relatively new to SQL. I am using MySQL and trying to run a query against a DB with two tables ('Network', and 'Server'). When I trying a portion of the query it executes without fail, however, when I try and add to it, I receive nothing but errors ranging from 1046 to 1140 to 1241. I am sure it is a matter of syntax and formatting, but I cannot figure it out. Please help. Below is my query:
SELECT (SELECT CONCAT(ROUND(SUM(server.Tech=7)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=7)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS V,
(SELECT CONCAT(ROUND(SUM(server.Tech=2)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=2)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS J
(SELECT CONCAT(ROUND(SUM(server.Tech=4)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=4)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS K
mysql-5.7
asked 3 mins ago
user8846971user8846971
1
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Please bear with me as I am relatively new to SQL. I am using MySQL and trying to run a query against a DB with two tables ('Network', and 'Server'). When I trying a portion of the query it executes without fail, however, when I try and add to it, I receive nothing but errors ranging from 1046 to 1140 to 1241. I am sure it is a matter of syntax and formatting, but I cannot figure it out. Please help. Below is my query:
SELECT (SELECT CONCAT(ROUND(SUM(server.Tech=7)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=7)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS V,
(SELECT CONCAT(ROUND(SUM(server.Tech=2)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=2)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS J
(SELECT CONCAT(ROUND(SUM(server.Tech=4)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=4)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS K
mysql-5.7
asked 3 mins ago
user8846971user8846971
1
New contributor
user8846971 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
Please bear with me as I am relatively new to SQL. I am using MySQL and trying to run a query against a DB with two tables ('Network', and 'Server'). When I trying a portion of the query it executes without fail, however, when I try and add to it, I receive nothing but errors ranging from 1046 to 1140 to 1241. I am sure it is a matter of syntax and formatting, but I cannot figure it out. Please help. Below is my query:
SELECT (SELECT CONCAT(ROUND(SUM(server.Tech=7)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=7)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS V,
(SELECT CONCAT(ROUND(SUM(server.Tech=2)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=2)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS J
(SELECT CONCAT(ROUND(SUM(server.Tech=4)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=4)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS K
mysql-5.7
asked 3 mins ago
user8846971user8846971
1
New contributor
user8846971 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Please bear with me as I am relatively new to SQL. I am using MySQL and trying to run a query against a DB with two tables ('Network', and 'Server'). When I trying a portion of the query it executes without fail, however, when I try and add to it, I receive nothing but errors ranging from 1046 to 1140 to 1241. I am sure it is a matter of syntax and formatting, but I cannot figure it out. Please help. Below is my query:
SELECT (SELECT CONCAT(ROUND(SUM(server.Tech=7)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=7)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS V,
(SELECT CONCAT(ROUND(SUM(server.Tech=2)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=2)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS J
(SELECT CONCAT(ROUND(SUM(server.Tech=4)/COUNT(server.Tech) * 100,2), '%') AS Server,
CONCAT(ROUND(SUM(network.Tech=4)/COUNT(network.Tech) * 100,2), '%') AS Network
FROM network join server) AS K
mysql-5.7
mysql-5.7
asked 3 mins ago
user8846971user8846971
1
New contributor
user8846971 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 mins ago
user8846971user8846971
1
New contributor
user8846971 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 3 mins ago
user8846971user8846971
1
New contributor
user8846971 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 3 mins ago
user8846971user8846971
1
asked 3 mins ago
user8846971user8846971
1
1
New contributor
user8846971 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
user8846971 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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user8846971 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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