What is the purpose of finding Area between Curves?












6














I've seen many explanations on how to find it; however, I can't seem to find what the purpose is of calculating the area between curves.










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  • 22




    You might as well ask what the point of computing areas is whatsoever
    – Wojowu
    15 hours ago






  • 1




    Maybe it's just a neat example of a kind of geometry problem that can be solved using calculus. If you're wondering why integration is useful (who cares about areas, anyway?) one major reason is that integration can be used to find the total change in a quantity if we know the instantaneous rate of change of that quantity. For example, knowing an object's velocity, you can figure out its position.
    – littleO
    15 hours ago








  • 1




    If we take a look back at history, a problem that seventeenth century mathematicians were very much interested in solving was the volume of the earth. Because the earth isn't an exact sphere, simple geometry wasn't going to cut it
    – WaveX
    15 hours ago












  • Um, because the question comes up? Frequently.
    – fleablood
    14 hours ago










  • Imho you're asking the wrong kind of question. For most common, elementary math concepts you should not worry about the applications, things will come together once you have a broader understanding of mathematics. It's not reasonable to assume that any isolated math concept will have tons of applications that appear in practice , but that doesn't mean that knowing about it isnt useful. You might as well ask what the purpose of learning about division is or, for an analogy outside of mathematics, why you should learn a specific word.
    – user159517
    11 hours ago


















6














I've seen many explanations on how to find it; however, I can't seem to find what the purpose is of calculating the area between curves.










share|cite|improve this question









New contributor




EpicNicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • 22




    You might as well ask what the point of computing areas is whatsoever
    – Wojowu
    15 hours ago






  • 1




    Maybe it's just a neat example of a kind of geometry problem that can be solved using calculus. If you're wondering why integration is useful (who cares about areas, anyway?) one major reason is that integration can be used to find the total change in a quantity if we know the instantaneous rate of change of that quantity. For example, knowing an object's velocity, you can figure out its position.
    – littleO
    15 hours ago








  • 1




    If we take a look back at history, a problem that seventeenth century mathematicians were very much interested in solving was the volume of the earth. Because the earth isn't an exact sphere, simple geometry wasn't going to cut it
    – WaveX
    15 hours ago












  • Um, because the question comes up? Frequently.
    – fleablood
    14 hours ago










  • Imho you're asking the wrong kind of question. For most common, elementary math concepts you should not worry about the applications, things will come together once you have a broader understanding of mathematics. It's not reasonable to assume that any isolated math concept will have tons of applications that appear in practice , but that doesn't mean that knowing about it isnt useful. You might as well ask what the purpose of learning about division is or, for an analogy outside of mathematics, why you should learn a specific word.
    – user159517
    11 hours ago
















6












6








6







I've seen many explanations on how to find it; however, I can't seem to find what the purpose is of calculating the area between curves.










share|cite|improve this question









New contributor




EpicNicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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I've seen many explanations on how to find it; however, I can't seem to find what the purpose is of calculating the area between curves.







calculus soft-question area






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edited 15 hours ago









Mutantoe

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asked 15 hours ago









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  • 22




    You might as well ask what the point of computing areas is whatsoever
    – Wojowu
    15 hours ago






  • 1




    Maybe it's just a neat example of a kind of geometry problem that can be solved using calculus. If you're wondering why integration is useful (who cares about areas, anyway?) one major reason is that integration can be used to find the total change in a quantity if we know the instantaneous rate of change of that quantity. For example, knowing an object's velocity, you can figure out its position.
    – littleO
    15 hours ago








  • 1




    If we take a look back at history, a problem that seventeenth century mathematicians were very much interested in solving was the volume of the earth. Because the earth isn't an exact sphere, simple geometry wasn't going to cut it
    – WaveX
    15 hours ago












  • Um, because the question comes up? Frequently.
    – fleablood
    14 hours ago










  • Imho you're asking the wrong kind of question. For most common, elementary math concepts you should not worry about the applications, things will come together once you have a broader understanding of mathematics. It's not reasonable to assume that any isolated math concept will have tons of applications that appear in practice , but that doesn't mean that knowing about it isnt useful. You might as well ask what the purpose of learning about division is or, for an analogy outside of mathematics, why you should learn a specific word.
    – user159517
    11 hours ago
















  • 22




    You might as well ask what the point of computing areas is whatsoever
    – Wojowu
    15 hours ago






  • 1




    Maybe it's just a neat example of a kind of geometry problem that can be solved using calculus. If you're wondering why integration is useful (who cares about areas, anyway?) one major reason is that integration can be used to find the total change in a quantity if we know the instantaneous rate of change of that quantity. For example, knowing an object's velocity, you can figure out its position.
    – littleO
    15 hours ago








  • 1




    If we take a look back at history, a problem that seventeenth century mathematicians were very much interested in solving was the volume of the earth. Because the earth isn't an exact sphere, simple geometry wasn't going to cut it
    – WaveX
    15 hours ago












  • Um, because the question comes up? Frequently.
    – fleablood
    14 hours ago










  • Imho you're asking the wrong kind of question. For most common, elementary math concepts you should not worry about the applications, things will come together once you have a broader understanding of mathematics. It's not reasonable to assume that any isolated math concept will have tons of applications that appear in practice , but that doesn't mean that knowing about it isnt useful. You might as well ask what the purpose of learning about division is or, for an analogy outside of mathematics, why you should learn a specific word.
    – user159517
    11 hours ago










22




22




You might as well ask what the point of computing areas is whatsoever
– Wojowu
15 hours ago




You might as well ask what the point of computing areas is whatsoever
– Wojowu
15 hours ago




1




1




Maybe it's just a neat example of a kind of geometry problem that can be solved using calculus. If you're wondering why integration is useful (who cares about areas, anyway?) one major reason is that integration can be used to find the total change in a quantity if we know the instantaneous rate of change of that quantity. For example, knowing an object's velocity, you can figure out its position.
– littleO
15 hours ago






Maybe it's just a neat example of a kind of geometry problem that can be solved using calculus. If you're wondering why integration is useful (who cares about areas, anyway?) one major reason is that integration can be used to find the total change in a quantity if we know the instantaneous rate of change of that quantity. For example, knowing an object's velocity, you can figure out its position.
– littleO
15 hours ago






1




1




If we take a look back at history, a problem that seventeenth century mathematicians were very much interested in solving was the volume of the earth. Because the earth isn't an exact sphere, simple geometry wasn't going to cut it
– WaveX
15 hours ago






If we take a look back at history, a problem that seventeenth century mathematicians were very much interested in solving was the volume of the earth. Because the earth isn't an exact sphere, simple geometry wasn't going to cut it
– WaveX
15 hours ago














Um, because the question comes up? Frequently.
– fleablood
14 hours ago




Um, because the question comes up? Frequently.
– fleablood
14 hours ago












Imho you're asking the wrong kind of question. For most common, elementary math concepts you should not worry about the applications, things will come together once you have a broader understanding of mathematics. It's not reasonable to assume that any isolated math concept will have tons of applications that appear in practice , but that doesn't mean that knowing about it isnt useful. You might as well ask what the purpose of learning about division is or, for an analogy outside of mathematics, why you should learn a specific word.
– user159517
11 hours ago






Imho you're asking the wrong kind of question. For most common, elementary math concepts you should not worry about the applications, things will come together once you have a broader understanding of mathematics. It's not reasonable to assume that any isolated math concept will have tons of applications that appear in practice , but that doesn't mean that knowing about it isnt useful. You might as well ask what the purpose of learning about division is or, for an analogy outside of mathematics, why you should learn a specific word.
– user159517
11 hours ago












7 Answers
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13














The best application that comes to mind is computing the center of mass of an object.



Let $f(x)geq g(x)$ on $(a,b),$ then the center of mass of the area bound by the curves $f$ and $g$ is given by the coordinates



$$bar{x}=dfrac{int_a^bf(x)^2-g(x)^2dx}{2int_a^b f(x)-g(x)dx}$$
and
$$bar{y}=dfrac{int_a^bx(f(x)-g(x))dx}{int_a^b f(x)-g(x)dx}.$$



So the center of mass is $(bar{x},bar{y}).$



Now, you might wonder "why is that useful?" That's a good question.



Imagine you have designed a flat, or approximately flat object, which you'd like to move using a single suction cup/suction cup like device. For example, the glass which forms the screen of a modern smart phone. To reduce stress on the glass when picking it up and moving it around, you can pick it up by its center of mass, and distribute the stress uniformly.






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    12














    There are many applications for the area between curves. For example if the curves represent the speeds,then the area is the difference between the total distance traveled.



    Another application is for two investments with different interest rates and the area represents the difference between the total interest gained by accounts.






    share|cite|improve this answer































      5














      For instance, computing that area of the disk$${(x,y)inmathbb{R}^2,|,x^2+y^2leqslant r^2}$$ is the same thing as computing the areas between the curves$$begin{array}{ccc}[-r,r]&longrightarrow&mathbb{R}^2\x&mapsto&sqrt{r^2-x^2}end{array}$$and$$begin{array}{ccc}[-r,r]&longrightarrow&mathbb{R}^2\x&mapsto&-sqrt{r^2-x^2}end{array}.$$So, unless you find the problem of computing the area of a disk beneath you, you can see that it is as interesting as the problem of finding the area between two specific curves.






      share|cite|improve this answer





























        4














        There are loads of examples in the real world outside of pure mathematics.



        In terms of materials, finding the area under the stress-strain curve tells that material's toughness - how much abuse (energy) it can take (absorb) before it begins to fracture. If you take the difference between two materials' toughness, you can see which one is tougher, which is something that's not always apparent at just looking at their graphs.



        Example: Say we have materials A and B, each with stress-strain curves given by $sigma(epsilon)$.



        begin{cases}
        begin{align}
        sigma_A(epsilon) &= 5 epsilon, &epsilon in (0,1)\
        sigma_B(epsilon) &= tanhepsilon, &epsilon in (0,3)
        end{align}
        end{cases}



        These functions, by the way, are wildly unrealistic in most occurrences, but the concept is still relevant.



        $hskip 1 in$ Plotting material A and material B



        It's not exactly clear which material has the higher toughness. Material A's looks like a lot more, but maybe the longevity of material B makes up for its low yield. We could find the area under each and see which is higher but we could assume material A is tougher and find the area between A and B.



        $$Delta U = int_0^3 Big( 5epsilon big(1 - h(epsilon - 1)big) - tanh epsilon Big) , depsilon =frac{5}{2} - logcosh3approx 0.19.$$



        So material A is actually hardly more tough than material B.





        In terms of systems, you can design an integral-feedback control system that reduces the error in the output from the desired output. In practice, these are PID controllers (Proportional, Integral, Derivative), all 3 of which are focused on changing the actual output to what it should be based on the desired output. The goal is for the error to be zero, i.e. in the integral controller, you're looking for the area between the desired output and actual output to be exactly zero.



        For instance, suppose you're driving and you click on the cruise control. You've just told the car you want it to keep going the speed that you are going right this moment. Now the road starts leading you uphill. The car is going to slow down initially, but it is also going to do everything it can to keep you going how fast you told it to go. That is, going uphill, it has encountered some error between the actual speed and desired speed and it wants to bring that error back to zero. The same applies for going downhill as well.



        Another example could be controlling the temperature inside an oven, perhaps an expensive one with variable heating elements using a similarly styled controller.



        These are just a few examples; there's really no shortage of applications.






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          2














          Another aspect worth pointing out is that definite integrals solve many problems other than finding the area between curves- e.g. finding total net change in some system given the instantaneous rates of change. Finding the area between curves is an application that happens to be particularly easy to visualize.






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            0














            Given two interest rate functions of time (the instantaneous rates of change of the values of two investments), the integral of the difference between them with respect to time is the difference in the returns of the two investments they represent over the interval of integration.



            Chromatographic peak assignment associates mass with the area between a sensor response curve and the baseline curve. A few examples are shown here. (The Wikipedia has this



            enter image description here



            although the baseline is not explicitly shown. That determining the baseline between, say, 20 and 25 minutes doesn't yield something simple should be easy to see.)






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              0














              Integration is the art of adding together very many, very small things. There are many things other than areas which can be added together this way, but areas are nice to represent visually, and relatively easy to intuit about (as long as your examples aren't too pathological). So that's the analogy most authors and lecturers go for when they introduce integration.



              Note that once the things you add become something different than real numbers (like vectors, or complex numbers), then the area analogy breaks down (it even struggles somewhat for negative numbers). For someone who cannot think of integration as anything other than finding areas, that's going to be a difficult transition. So I definitely would advise you to think about integration in other terms as well.



              One standard example would be if you had velocity as a function of time. You could draw the graph of that function and say that the area under the graph represents distance travelled. But this becomes very difficult to generalize once, say, you add direction of travel into the mix (i.e. you're traveling in a plane rather than on a line). You can somewhat still recover the intuition for total distance travelled, but for net distance (i.e. the straight line distance from starting point to end point) it becomes a hassle.



              On the other hand, one could forgo the area analogy completely and just say that for a very small time interval, you travelled a very small distance, and then add all those small distances together to find the total distance travelled. This is much easier to intuitively generalize from travel along a line to travel in a plane (especially if you're interested in net distance travelled), and on to higher dimensions.






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                7 Answers
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                7 Answers
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                13














                The best application that comes to mind is computing the center of mass of an object.



                Let $f(x)geq g(x)$ on $(a,b),$ then the center of mass of the area bound by the curves $f$ and $g$ is given by the coordinates



                $$bar{x}=dfrac{int_a^bf(x)^2-g(x)^2dx}{2int_a^b f(x)-g(x)dx}$$
                and
                $$bar{y}=dfrac{int_a^bx(f(x)-g(x))dx}{int_a^b f(x)-g(x)dx}.$$



                So the center of mass is $(bar{x},bar{y}).$



                Now, you might wonder "why is that useful?" That's a good question.



                Imagine you have designed a flat, or approximately flat object, which you'd like to move using a single suction cup/suction cup like device. For example, the glass which forms the screen of a modern smart phone. To reduce stress on the glass when picking it up and moving it around, you can pick it up by its center of mass, and distribute the stress uniformly.






                share|cite|improve this answer


























                  13














                  The best application that comes to mind is computing the center of mass of an object.



                  Let $f(x)geq g(x)$ on $(a,b),$ then the center of mass of the area bound by the curves $f$ and $g$ is given by the coordinates



                  $$bar{x}=dfrac{int_a^bf(x)^2-g(x)^2dx}{2int_a^b f(x)-g(x)dx}$$
                  and
                  $$bar{y}=dfrac{int_a^bx(f(x)-g(x))dx}{int_a^b f(x)-g(x)dx}.$$



                  So the center of mass is $(bar{x},bar{y}).$



                  Now, you might wonder "why is that useful?" That's a good question.



                  Imagine you have designed a flat, or approximately flat object, which you'd like to move using a single suction cup/suction cup like device. For example, the glass which forms the screen of a modern smart phone. To reduce stress on the glass when picking it up and moving it around, you can pick it up by its center of mass, and distribute the stress uniformly.






                  share|cite|improve this answer
























                    13












                    13








                    13






                    The best application that comes to mind is computing the center of mass of an object.



                    Let $f(x)geq g(x)$ on $(a,b),$ then the center of mass of the area bound by the curves $f$ and $g$ is given by the coordinates



                    $$bar{x}=dfrac{int_a^bf(x)^2-g(x)^2dx}{2int_a^b f(x)-g(x)dx}$$
                    and
                    $$bar{y}=dfrac{int_a^bx(f(x)-g(x))dx}{int_a^b f(x)-g(x)dx}.$$



                    So the center of mass is $(bar{x},bar{y}).$



                    Now, you might wonder "why is that useful?" That's a good question.



                    Imagine you have designed a flat, or approximately flat object, which you'd like to move using a single suction cup/suction cup like device. For example, the glass which forms the screen of a modern smart phone. To reduce stress on the glass when picking it up and moving it around, you can pick it up by its center of mass, and distribute the stress uniformly.






                    share|cite|improve this answer












                    The best application that comes to mind is computing the center of mass of an object.



                    Let $f(x)geq g(x)$ on $(a,b),$ then the center of mass of the area bound by the curves $f$ and $g$ is given by the coordinates



                    $$bar{x}=dfrac{int_a^bf(x)^2-g(x)^2dx}{2int_a^b f(x)-g(x)dx}$$
                    and
                    $$bar{y}=dfrac{int_a^bx(f(x)-g(x))dx}{int_a^b f(x)-g(x)dx}.$$



                    So the center of mass is $(bar{x},bar{y}).$



                    Now, you might wonder "why is that useful?" That's a good question.



                    Imagine you have designed a flat, or approximately flat object, which you'd like to move using a single suction cup/suction cup like device. For example, the glass which forms the screen of a modern smart phone. To reduce stress on the glass when picking it up and moving it around, you can pick it up by its center of mass, and distribute the stress uniformly.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered 15 hours ago









                    ChickenmancerChickenmancer

                    3,474724




                    3,474724























                        12














                        There are many applications for the area between curves. For example if the curves represent the speeds,then the area is the difference between the total distance traveled.



                        Another application is for two investments with different interest rates and the area represents the difference between the total interest gained by accounts.






                        share|cite|improve this answer




























                          12














                          There are many applications for the area between curves. For example if the curves represent the speeds,then the area is the difference between the total distance traveled.



                          Another application is for two investments with different interest rates and the area represents the difference between the total interest gained by accounts.






                          share|cite|improve this answer


























                            12












                            12








                            12






                            There are many applications for the area between curves. For example if the curves represent the speeds,then the area is the difference between the total distance traveled.



                            Another application is for two investments with different interest rates and the area represents the difference between the total interest gained by accounts.






                            share|cite|improve this answer














                            There are many applications for the area between curves. For example if the curves represent the speeds,then the area is the difference between the total distance traveled.



                            Another application is for two investments with different interest rates and the area represents the difference between the total interest gained by accounts.







                            share|cite|improve this answer














                            share|cite|improve this answer



                            share|cite|improve this answer








                            edited 15 hours ago

























                            answered 15 hours ago









                            Mohammad Riazi-KermaniMohammad Riazi-Kermani

                            41.1k42060




                            41.1k42060























                                5














                                For instance, computing that area of the disk$${(x,y)inmathbb{R}^2,|,x^2+y^2leqslant r^2}$$ is the same thing as computing the areas between the curves$$begin{array}{ccc}[-r,r]&longrightarrow&mathbb{R}^2\x&mapsto&sqrt{r^2-x^2}end{array}$$and$$begin{array}{ccc}[-r,r]&longrightarrow&mathbb{R}^2\x&mapsto&-sqrt{r^2-x^2}end{array}.$$So, unless you find the problem of computing the area of a disk beneath you, you can see that it is as interesting as the problem of finding the area between two specific curves.






                                share|cite|improve this answer


























                                  5














                                  For instance, computing that area of the disk$${(x,y)inmathbb{R}^2,|,x^2+y^2leqslant r^2}$$ is the same thing as computing the areas between the curves$$begin{array}{ccc}[-r,r]&longrightarrow&mathbb{R}^2\x&mapsto&sqrt{r^2-x^2}end{array}$$and$$begin{array}{ccc}[-r,r]&longrightarrow&mathbb{R}^2\x&mapsto&-sqrt{r^2-x^2}end{array}.$$So, unless you find the problem of computing the area of a disk beneath you, you can see that it is as interesting as the problem of finding the area between two specific curves.






                                  share|cite|improve this answer
























                                    5












                                    5








                                    5






                                    For instance, computing that area of the disk$${(x,y)inmathbb{R}^2,|,x^2+y^2leqslant r^2}$$ is the same thing as computing the areas between the curves$$begin{array}{ccc}[-r,r]&longrightarrow&mathbb{R}^2\x&mapsto&sqrt{r^2-x^2}end{array}$$and$$begin{array}{ccc}[-r,r]&longrightarrow&mathbb{R}^2\x&mapsto&-sqrt{r^2-x^2}end{array}.$$So, unless you find the problem of computing the area of a disk beneath you, you can see that it is as interesting as the problem of finding the area between two specific curves.






                                    share|cite|improve this answer












                                    For instance, computing that area of the disk$${(x,y)inmathbb{R}^2,|,x^2+y^2leqslant r^2}$$ is the same thing as computing the areas between the curves$$begin{array}{ccc}[-r,r]&longrightarrow&mathbb{R}^2\x&mapsto&sqrt{r^2-x^2}end{array}$$and$$begin{array}{ccc}[-r,r]&longrightarrow&mathbb{R}^2\x&mapsto&-sqrt{r^2-x^2}end{array}.$$So, unless you find the problem of computing the area of a disk beneath you, you can see that it is as interesting as the problem of finding the area between two specific curves.







                                    share|cite|improve this answer












                                    share|cite|improve this answer



                                    share|cite|improve this answer










                                    answered 15 hours ago









                                    José Carlos SantosJosé Carlos Santos

                                    152k22123226




                                    152k22123226























                                        4














                                        There are loads of examples in the real world outside of pure mathematics.



                                        In terms of materials, finding the area under the stress-strain curve tells that material's toughness - how much abuse (energy) it can take (absorb) before it begins to fracture. If you take the difference between two materials' toughness, you can see which one is tougher, which is something that's not always apparent at just looking at their graphs.



                                        Example: Say we have materials A and B, each with stress-strain curves given by $sigma(epsilon)$.



                                        begin{cases}
                                        begin{align}
                                        sigma_A(epsilon) &= 5 epsilon, &epsilon in (0,1)\
                                        sigma_B(epsilon) &= tanhepsilon, &epsilon in (0,3)
                                        end{align}
                                        end{cases}



                                        These functions, by the way, are wildly unrealistic in most occurrences, but the concept is still relevant.



                                        $hskip 1 in$ Plotting material A and material B



                                        It's not exactly clear which material has the higher toughness. Material A's looks like a lot more, but maybe the longevity of material B makes up for its low yield. We could find the area under each and see which is higher but we could assume material A is tougher and find the area between A and B.



                                        $$Delta U = int_0^3 Big( 5epsilon big(1 - h(epsilon - 1)big) - tanh epsilon Big) , depsilon =frac{5}{2} - logcosh3approx 0.19.$$



                                        So material A is actually hardly more tough than material B.





                                        In terms of systems, you can design an integral-feedback control system that reduces the error in the output from the desired output. In practice, these are PID controllers (Proportional, Integral, Derivative), all 3 of which are focused on changing the actual output to what it should be based on the desired output. The goal is for the error to be zero, i.e. in the integral controller, you're looking for the area between the desired output and actual output to be exactly zero.



                                        For instance, suppose you're driving and you click on the cruise control. You've just told the car you want it to keep going the speed that you are going right this moment. Now the road starts leading you uphill. The car is going to slow down initially, but it is also going to do everything it can to keep you going how fast you told it to go. That is, going uphill, it has encountered some error between the actual speed and desired speed and it wants to bring that error back to zero. The same applies for going downhill as well.



                                        Another example could be controlling the temperature inside an oven, perhaps an expensive one with variable heating elements using a similarly styled controller.



                                        These are just a few examples; there's really no shortage of applications.






                                        share|cite|improve this answer


























                                          4














                                          There are loads of examples in the real world outside of pure mathematics.



                                          In terms of materials, finding the area under the stress-strain curve tells that material's toughness - how much abuse (energy) it can take (absorb) before it begins to fracture. If you take the difference between two materials' toughness, you can see which one is tougher, which is something that's not always apparent at just looking at their graphs.



                                          Example: Say we have materials A and B, each with stress-strain curves given by $sigma(epsilon)$.



                                          begin{cases}
                                          begin{align}
                                          sigma_A(epsilon) &= 5 epsilon, &epsilon in (0,1)\
                                          sigma_B(epsilon) &= tanhepsilon, &epsilon in (0,3)
                                          end{align}
                                          end{cases}



                                          These functions, by the way, are wildly unrealistic in most occurrences, but the concept is still relevant.



                                          $hskip 1 in$ Plotting material A and material B



                                          It's not exactly clear which material has the higher toughness. Material A's looks like a lot more, but maybe the longevity of material B makes up for its low yield. We could find the area under each and see which is higher but we could assume material A is tougher and find the area between A and B.



                                          $$Delta U = int_0^3 Big( 5epsilon big(1 - h(epsilon - 1)big) - tanh epsilon Big) , depsilon =frac{5}{2} - logcosh3approx 0.19.$$



                                          So material A is actually hardly more tough than material B.





                                          In terms of systems, you can design an integral-feedback control system that reduces the error in the output from the desired output. In practice, these are PID controllers (Proportional, Integral, Derivative), all 3 of which are focused on changing the actual output to what it should be based on the desired output. The goal is for the error to be zero, i.e. in the integral controller, you're looking for the area between the desired output and actual output to be exactly zero.



                                          For instance, suppose you're driving and you click on the cruise control. You've just told the car you want it to keep going the speed that you are going right this moment. Now the road starts leading you uphill. The car is going to slow down initially, but it is also going to do everything it can to keep you going how fast you told it to go. That is, going uphill, it has encountered some error between the actual speed and desired speed and it wants to bring that error back to zero. The same applies for going downhill as well.



                                          Another example could be controlling the temperature inside an oven, perhaps an expensive one with variable heating elements using a similarly styled controller.



                                          These are just a few examples; there's really no shortage of applications.






                                          share|cite|improve this answer
























                                            4












                                            4








                                            4






                                            There are loads of examples in the real world outside of pure mathematics.



                                            In terms of materials, finding the area under the stress-strain curve tells that material's toughness - how much abuse (energy) it can take (absorb) before it begins to fracture. If you take the difference between two materials' toughness, you can see which one is tougher, which is something that's not always apparent at just looking at their graphs.



                                            Example: Say we have materials A and B, each with stress-strain curves given by $sigma(epsilon)$.



                                            begin{cases}
                                            begin{align}
                                            sigma_A(epsilon) &= 5 epsilon, &epsilon in (0,1)\
                                            sigma_B(epsilon) &= tanhepsilon, &epsilon in (0,3)
                                            end{align}
                                            end{cases}



                                            These functions, by the way, are wildly unrealistic in most occurrences, but the concept is still relevant.



                                            $hskip 1 in$ Plotting material A and material B



                                            It's not exactly clear which material has the higher toughness. Material A's looks like a lot more, but maybe the longevity of material B makes up for its low yield. We could find the area under each and see which is higher but we could assume material A is tougher and find the area between A and B.



                                            $$Delta U = int_0^3 Big( 5epsilon big(1 - h(epsilon - 1)big) - tanh epsilon Big) , depsilon =frac{5}{2} - logcosh3approx 0.19.$$



                                            So material A is actually hardly more tough than material B.





                                            In terms of systems, you can design an integral-feedback control system that reduces the error in the output from the desired output. In practice, these are PID controllers (Proportional, Integral, Derivative), all 3 of which are focused on changing the actual output to what it should be based on the desired output. The goal is for the error to be zero, i.e. in the integral controller, you're looking for the area between the desired output and actual output to be exactly zero.



                                            For instance, suppose you're driving and you click on the cruise control. You've just told the car you want it to keep going the speed that you are going right this moment. Now the road starts leading you uphill. The car is going to slow down initially, but it is also going to do everything it can to keep you going how fast you told it to go. That is, going uphill, it has encountered some error between the actual speed and desired speed and it wants to bring that error back to zero. The same applies for going downhill as well.



                                            Another example could be controlling the temperature inside an oven, perhaps an expensive one with variable heating elements using a similarly styled controller.



                                            These are just a few examples; there's really no shortage of applications.






                                            share|cite|improve this answer












                                            There are loads of examples in the real world outside of pure mathematics.



                                            In terms of materials, finding the area under the stress-strain curve tells that material's toughness - how much abuse (energy) it can take (absorb) before it begins to fracture. If you take the difference between two materials' toughness, you can see which one is tougher, which is something that's not always apparent at just looking at their graphs.



                                            Example: Say we have materials A and B, each with stress-strain curves given by $sigma(epsilon)$.



                                            begin{cases}
                                            begin{align}
                                            sigma_A(epsilon) &= 5 epsilon, &epsilon in (0,1)\
                                            sigma_B(epsilon) &= tanhepsilon, &epsilon in (0,3)
                                            end{align}
                                            end{cases}



                                            These functions, by the way, are wildly unrealistic in most occurrences, but the concept is still relevant.



                                            $hskip 1 in$ Plotting material A and material B



                                            It's not exactly clear which material has the higher toughness. Material A's looks like a lot more, but maybe the longevity of material B makes up for its low yield. We could find the area under each and see which is higher but we could assume material A is tougher and find the area between A and B.



                                            $$Delta U = int_0^3 Big( 5epsilon big(1 - h(epsilon - 1)big) - tanh epsilon Big) , depsilon =frac{5}{2} - logcosh3approx 0.19.$$



                                            So material A is actually hardly more tough than material B.





                                            In terms of systems, you can design an integral-feedback control system that reduces the error in the output from the desired output. In practice, these are PID controllers (Proportional, Integral, Derivative), all 3 of which are focused on changing the actual output to what it should be based on the desired output. The goal is for the error to be zero, i.e. in the integral controller, you're looking for the area between the desired output and actual output to be exactly zero.



                                            For instance, suppose you're driving and you click on the cruise control. You've just told the car you want it to keep going the speed that you are going right this moment. Now the road starts leading you uphill. The car is going to slow down initially, but it is also going to do everything it can to keep you going how fast you told it to go. That is, going uphill, it has encountered some error between the actual speed and desired speed and it wants to bring that error back to zero. The same applies for going downhill as well.



                                            Another example could be controlling the temperature inside an oven, perhaps an expensive one with variable heating elements using a similarly styled controller.



                                            These are just a few examples; there's really no shortage of applications.







                                            share|cite|improve this answer












                                            share|cite|improve this answer



                                            share|cite|improve this answer










                                            answered 13 hours ago









                                            SkipSkip

                                            1,252214




                                            1,252214























                                                2














                                                Another aspect worth pointing out is that definite integrals solve many problems other than finding the area between curves- e.g. finding total net change in some system given the instantaneous rates of change. Finding the area between curves is an application that happens to be particularly easy to visualize.






                                                share|cite|improve this answer


























                                                  2














                                                  Another aspect worth pointing out is that definite integrals solve many problems other than finding the area between curves- e.g. finding total net change in some system given the instantaneous rates of change. Finding the area between curves is an application that happens to be particularly easy to visualize.






                                                  share|cite|improve this answer
























                                                    2












                                                    2








                                                    2






                                                    Another aspect worth pointing out is that definite integrals solve many problems other than finding the area between curves- e.g. finding total net change in some system given the instantaneous rates of change. Finding the area between curves is an application that happens to be particularly easy to visualize.






                                                    share|cite|improve this answer












                                                    Another aspect worth pointing out is that definite integrals solve many problems other than finding the area between curves- e.g. finding total net change in some system given the instantaneous rates of change. Finding the area between curves is an application that happens to be particularly easy to visualize.







                                                    share|cite|improve this answer












                                                    share|cite|improve this answer



                                                    share|cite|improve this answer










                                                    answered 15 hours ago









                                                    Gregory J. PuleoGregory J. Puleo

                                                    4,49731520




                                                    4,49731520























                                                        0














                                                        Given two interest rate functions of time (the instantaneous rates of change of the values of two investments), the integral of the difference between them with respect to time is the difference in the returns of the two investments they represent over the interval of integration.



                                                        Chromatographic peak assignment associates mass with the area between a sensor response curve and the baseline curve. A few examples are shown here. (The Wikipedia has this



                                                        enter image description here



                                                        although the baseline is not explicitly shown. That determining the baseline between, say, 20 and 25 minutes doesn't yield something simple should be easy to see.)






                                                        share|cite|improve this answer


























                                                          0














                                                          Given two interest rate functions of time (the instantaneous rates of change of the values of two investments), the integral of the difference between them with respect to time is the difference in the returns of the two investments they represent over the interval of integration.



                                                          Chromatographic peak assignment associates mass with the area between a sensor response curve and the baseline curve. A few examples are shown here. (The Wikipedia has this



                                                          enter image description here



                                                          although the baseline is not explicitly shown. That determining the baseline between, say, 20 and 25 minutes doesn't yield something simple should be easy to see.)






                                                          share|cite|improve this answer
























                                                            0












                                                            0








                                                            0






                                                            Given two interest rate functions of time (the instantaneous rates of change of the values of two investments), the integral of the difference between them with respect to time is the difference in the returns of the two investments they represent over the interval of integration.



                                                            Chromatographic peak assignment associates mass with the area between a sensor response curve and the baseline curve. A few examples are shown here. (The Wikipedia has this



                                                            enter image description here



                                                            although the baseline is not explicitly shown. That determining the baseline between, say, 20 and 25 minutes doesn't yield something simple should be easy to see.)






                                                            share|cite|improve this answer












                                                            Given two interest rate functions of time (the instantaneous rates of change of the values of two investments), the integral of the difference between them with respect to time is the difference in the returns of the two investments they represent over the interval of integration.



                                                            Chromatographic peak assignment associates mass with the area between a sensor response curve and the baseline curve. A few examples are shown here. (The Wikipedia has this



                                                            enter image description here



                                                            although the baseline is not explicitly shown. That determining the baseline between, say, 20 and 25 minutes doesn't yield something simple should be easy to see.)







                                                            share|cite|improve this answer












                                                            share|cite|improve this answer



                                                            share|cite|improve this answer










                                                            answered 4 hours ago









                                                            Eric TowersEric Towers

                                                            32.1k22267




                                                            32.1k22267























                                                                0














                                                                Integration is the art of adding together very many, very small things. There are many things other than areas which can be added together this way, but areas are nice to represent visually, and relatively easy to intuit about (as long as your examples aren't too pathological). So that's the analogy most authors and lecturers go for when they introduce integration.



                                                                Note that once the things you add become something different than real numbers (like vectors, or complex numbers), then the area analogy breaks down (it even struggles somewhat for negative numbers). For someone who cannot think of integration as anything other than finding areas, that's going to be a difficult transition. So I definitely would advise you to think about integration in other terms as well.



                                                                One standard example would be if you had velocity as a function of time. You could draw the graph of that function and say that the area under the graph represents distance travelled. But this becomes very difficult to generalize once, say, you add direction of travel into the mix (i.e. you're traveling in a plane rather than on a line). You can somewhat still recover the intuition for total distance travelled, but for net distance (i.e. the straight line distance from starting point to end point) it becomes a hassle.



                                                                On the other hand, one could forgo the area analogy completely and just say that for a very small time interval, you travelled a very small distance, and then add all those small distances together to find the total distance travelled. This is much easier to intuitively generalize from travel along a line to travel in a plane (especially if you're interested in net distance travelled), and on to higher dimensions.






                                                                share|cite|improve this answer




























                                                                  0














                                                                  Integration is the art of adding together very many, very small things. There are many things other than areas which can be added together this way, but areas are nice to represent visually, and relatively easy to intuit about (as long as your examples aren't too pathological). So that's the analogy most authors and lecturers go for when they introduce integration.



                                                                  Note that once the things you add become something different than real numbers (like vectors, or complex numbers), then the area analogy breaks down (it even struggles somewhat for negative numbers). For someone who cannot think of integration as anything other than finding areas, that's going to be a difficult transition. So I definitely would advise you to think about integration in other terms as well.



                                                                  One standard example would be if you had velocity as a function of time. You could draw the graph of that function and say that the area under the graph represents distance travelled. But this becomes very difficult to generalize once, say, you add direction of travel into the mix (i.e. you're traveling in a plane rather than on a line). You can somewhat still recover the intuition for total distance travelled, but for net distance (i.e. the straight line distance from starting point to end point) it becomes a hassle.



                                                                  On the other hand, one could forgo the area analogy completely and just say that for a very small time interval, you travelled a very small distance, and then add all those small distances together to find the total distance travelled. This is much easier to intuitively generalize from travel along a line to travel in a plane (especially if you're interested in net distance travelled), and on to higher dimensions.






                                                                  share|cite|improve this answer


























                                                                    0












                                                                    0








                                                                    0






                                                                    Integration is the art of adding together very many, very small things. There are many things other than areas which can be added together this way, but areas are nice to represent visually, and relatively easy to intuit about (as long as your examples aren't too pathological). So that's the analogy most authors and lecturers go for when they introduce integration.



                                                                    Note that once the things you add become something different than real numbers (like vectors, or complex numbers), then the area analogy breaks down (it even struggles somewhat for negative numbers). For someone who cannot think of integration as anything other than finding areas, that's going to be a difficult transition. So I definitely would advise you to think about integration in other terms as well.



                                                                    One standard example would be if you had velocity as a function of time. You could draw the graph of that function and say that the area under the graph represents distance travelled. But this becomes very difficult to generalize once, say, you add direction of travel into the mix (i.e. you're traveling in a plane rather than on a line). You can somewhat still recover the intuition for total distance travelled, but for net distance (i.e. the straight line distance from starting point to end point) it becomes a hassle.



                                                                    On the other hand, one could forgo the area analogy completely and just say that for a very small time interval, you travelled a very small distance, and then add all those small distances together to find the total distance travelled. This is much easier to intuitively generalize from travel along a line to travel in a plane (especially if you're interested in net distance travelled), and on to higher dimensions.






                                                                    share|cite|improve this answer














                                                                    Integration is the art of adding together very many, very small things. There are many things other than areas which can be added together this way, but areas are nice to represent visually, and relatively easy to intuit about (as long as your examples aren't too pathological). So that's the analogy most authors and lecturers go for when they introduce integration.



                                                                    Note that once the things you add become something different than real numbers (like vectors, or complex numbers), then the area analogy breaks down (it even struggles somewhat for negative numbers). For someone who cannot think of integration as anything other than finding areas, that's going to be a difficult transition. So I definitely would advise you to think about integration in other terms as well.



                                                                    One standard example would be if you had velocity as a function of time. You could draw the graph of that function and say that the area under the graph represents distance travelled. But this becomes very difficult to generalize once, say, you add direction of travel into the mix (i.e. you're traveling in a plane rather than on a line). You can somewhat still recover the intuition for total distance travelled, but for net distance (i.e. the straight line distance from starting point to end point) it becomes a hassle.



                                                                    On the other hand, one could forgo the area analogy completely and just say that for a very small time interval, you travelled a very small distance, and then add all those small distances together to find the total distance travelled. This is much easier to intuitively generalize from travel along a line to travel in a plane (especially if you're interested in net distance travelled), and on to higher dimensions.







                                                                    share|cite|improve this answer














                                                                    share|cite|improve this answer



                                                                    share|cite|improve this answer








                                                                    edited 26 mins ago

























                                                                    answered 43 mins ago









                                                                    ArthurArthur

                                                                    111k7106187




                                                                    111k7106187






















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