Mysql query to fetch records which are not matched form both tables
I am new to here.
I have two two tables , one is temporary table and another one is main table.Before doing final process user click on refresh button . Then I am populating data into the temporary table and need to display to user if there is any difference between two tables like old value - new value. For this I tried below query but not able get the old value. I am getting as null
Temporay table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |2 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138875| 30059320 |25 |
+------+--------------+----------------+--+--+
Main Table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |5 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138888| 30059320 |25 |
+------+--------------+----------------+--+--+
From both tables I have change in ean field and in quantity field
For this I am using this query
SELECT
t2.id,t2.ean,t2.belegnr,t2.`quantity`,t1.`quantity` FROM
temp_table t2
LEFT OUTER JOIN details t1 ON
t1.asn = t2.asn
AND t1.ean = t2.ean
AND t1.belegnr = t2.belegnr
AND t1.quantity = t2.quantity
WHERE t2.asn = 700000845
AND t2.`belegnr` in(30059314,30059320)
AND t1.id IS NULL
Below is the my expected result
+------+--------------+----------------+-----+----------------------
| asn | ean | oldean| belegnr |quantity|Oldqty|
+------+--------------+----------------+-----+----------------------|
| 700000845 | 4046228201122| 4046228201122 |30059314 |2 | 5 |
| 700000845 | 4046228138875| 4046228138888 |30059320 |25 | 25 |
+------+--------------+----------------+--+--+--------+-------------+
Any help would be greatly appreciated.
mysql join
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user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
I am new to here.
I have two two tables , one is temporary table and another one is main table.Before doing final process user click on refresh button . Then I am populating data into the temporary table and need to display to user if there is any difference between two tables like old value - new value. For this I tried below query but not able get the old value. I am getting as null
Temporay table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |2 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138875| 30059320 |25 |
+------+--------------+----------------+--+--+
Main Table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |5 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138888| 30059320 |25 |
+------+--------------+----------------+--+--+
From both tables I have change in ean field and in quantity field
For this I am using this query
SELECT
t2.id,t2.ean,t2.belegnr,t2.`quantity`,t1.`quantity` FROM
temp_table t2
LEFT OUTER JOIN details t1 ON
t1.asn = t2.asn
AND t1.ean = t2.ean
AND t1.belegnr = t2.belegnr
AND t1.quantity = t2.quantity
WHERE t2.asn = 700000845
AND t2.`belegnr` in(30059314,30059320)
AND t1.id IS NULL
Below is the my expected result
+------+--------------+----------------+-----+----------------------
| asn | ean | oldean| belegnr |quantity|Oldqty|
+------+--------------+----------------+-----+----------------------|
| 700000845 | 4046228201122| 4046228201122 |30059314 |2 | 5 |
| 700000845 | 4046228138875| 4046228138888 |30059320 |25 | 25 |
+------+--------------+----------------+--+--+--------+-------------+
Any help would be greatly appreciated.
mysql join
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
IsasnthePRIMARY KEYin each table? Please provideSHOW CREATE TABLE.
– Rick James
11 secs ago
add a comment |
I am new to here.
I have two two tables , one is temporary table and another one is main table.Before doing final process user click on refresh button . Then I am populating data into the temporary table and need to display to user if there is any difference between two tables like old value - new value. For this I tried below query but not able get the old value. I am getting as null
Temporay table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |2 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138875| 30059320 |25 |
+------+--------------+----------------+--+--+
Main Table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |5 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138888| 30059320 |25 |
+------+--------------+----------------+--+--+
From both tables I have change in ean field and in quantity field
For this I am using this query
SELECT
t2.id,t2.ean,t2.belegnr,t2.`quantity`,t1.`quantity` FROM
temp_table t2
LEFT OUTER JOIN details t1 ON
t1.asn = t2.asn
AND t1.ean = t2.ean
AND t1.belegnr = t2.belegnr
AND t1.quantity = t2.quantity
WHERE t2.asn = 700000845
AND t2.`belegnr` in(30059314,30059320)
AND t1.id IS NULL
Below is the my expected result
+------+--------------+----------------+-----+----------------------
| asn | ean | oldean| belegnr |quantity|Oldqty|
+------+--------------+----------------+-----+----------------------|
| 700000845 | 4046228201122| 4046228201122 |30059314 |2 | 5 |
| 700000845 | 4046228138875| 4046228138888 |30059320 |25 | 25 |
+------+--------------+----------------+--+--+--------+-------------+
Any help would be greatly appreciated.
mysql join
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am new to here.
I have two two tables , one is temporary table and another one is main table.Before doing final process user click on refresh button . Then I am populating data into the temporary table and need to display to user if there is any difference between two tables like old value - new value. For this I tried below query but not able get the old value. I am getting as null
Temporay table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |2 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138875| 30059320 |25 |
+------+--------------+----------------+--+--+
Main Table
+------+--------------+----------------+-----+
| asn | ean | belegnr |quantity|
+------+--------------+----------------+-----+
| 700000845 | 4046228201122| 30059314 |5 |
| 700000845 | 4046228138879| 30059314 |3 |
| 700000845 | 4046228138888| 30059320 |25 |
+------+--------------+----------------+--+--+
From both tables I have change in ean field and in quantity field
For this I am using this query
SELECT
t2.id,t2.ean,t2.belegnr,t2.`quantity`,t1.`quantity` FROM
temp_table t2
LEFT OUTER JOIN details t1 ON
t1.asn = t2.asn
AND t1.ean = t2.ean
AND t1.belegnr = t2.belegnr
AND t1.quantity = t2.quantity
WHERE t2.asn = 700000845
AND t2.`belegnr` in(30059314,30059320)
AND t1.id IS NULL
Below is the my expected result
+------+--------------+----------------+-----+----------------------
| asn | ean | oldean| belegnr |quantity|Oldqty|
+------+--------------+----------------+-----+----------------------|
| 700000845 | 4046228201122| 4046228201122 |30059314 |2 | 5 |
| 700000845 | 4046228138875| 4046228138888 |30059320 |25 | 25 |
+------+--------------+----------------+--+--+--------+-------------+
Any help would be greatly appreciated.
mysql join
mysql join
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
user3408779user3408779
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New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user3408779 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
IsasnthePRIMARY KEYin each table? Please provideSHOW CREATE TABLE.
– Rick James
11 secs ago
add a comment |
IsasnthePRIMARY KEYin each table? Please provideSHOW CREATE TABLE.
– Rick James
11 secs ago
Is
asn the PRIMARY KEY in each table? Please provide SHOW CREATE TABLE.– Rick James
11 secs ago
Is
asn the PRIMARY KEY in each table? Please provide SHOW CREATE TABLE.– Rick James
11 secs ago
add a comment |
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asnthePRIMARY KEYin each table? Please provideSHOW CREATE TABLE.– Rick James
11 secs ago