group by like string
I have a table employee
in this table i have id company_name employee_id
1 abc 2015_acb_1
2 abc 2015_acb_2
3 abc 2015_acb_3
4 abc 2015_acb_4
5 xyz 2016_xyz_9
5 xyz 2017_xyz_2
5 xyz 2016_xyz_3
5 xyz 2019_xyz_5
I want to select unique string such as from employee table
_abc_
_xyz_
i have try select employee_id where employee_id like %_%;
its not giving as i expected
postgresql postgresql-performance
New contributor
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I have a table employee
in this table i have id company_name employee_id
1 abc 2015_acb_1
2 abc 2015_acb_2
3 abc 2015_acb_3
4 abc 2015_acb_4
5 xyz 2016_xyz_9
5 xyz 2017_xyz_2
5 xyz 2016_xyz_3
5 xyz 2019_xyz_5
I want to select unique string such as from employee table
_abc_
_xyz_
i have try select employee_id where employee_id like %_%;
its not giving as i expected
postgresql postgresql-performance
New contributor
add a comment |
I have a table employee
in this table i have id company_name employee_id
1 abc 2015_acb_1
2 abc 2015_acb_2
3 abc 2015_acb_3
4 abc 2015_acb_4
5 xyz 2016_xyz_9
5 xyz 2017_xyz_2
5 xyz 2016_xyz_3
5 xyz 2019_xyz_5
I want to select unique string such as from employee table
_abc_
_xyz_
i have try select employee_id where employee_id like %_%;
its not giving as i expected
postgresql postgresql-performance
New contributor
I have a table employee
in this table i have id company_name employee_id
1 abc 2015_acb_1
2 abc 2015_acb_2
3 abc 2015_acb_3
4 abc 2015_acb_4
5 xyz 2016_xyz_9
5 xyz 2017_xyz_2
5 xyz 2016_xyz_3
5 xyz 2019_xyz_5
I want to select unique string such as from employee table
_abc_
_xyz_
i have try select employee_id where employee_id like %_%;
its not giving as i expected
postgresql postgresql-performance
postgresql postgresql-performance
New contributor
New contributor
New contributor
asked 25 mins ago
deviyadeviya
1
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1 Answer
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SELECT DISTINCT SUBSTRING(employee_id FROM 5 FOR 5)
FROM employee;
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1 Answer
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1 Answer
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active
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SELECT DISTINCT SUBSTRING(employee_id FROM 5 FOR 5)
FROM employee;
add a comment |
SELECT DISTINCT SUBSTRING(employee_id FROM 5 FOR 5)
FROM employee;
add a comment |
SELECT DISTINCT SUBSTRING(employee_id FROM 5 FOR 5)
FROM employee;
SELECT DISTINCT SUBSTRING(employee_id FROM 5 FOR 5)
FROM employee;
answered 12 mins ago
AkinaAkina
4,0361311
4,0361311
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deviya is a new contributor. Be nice, and check out our Code of Conduct.
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