Why would you need an op amp for reference voltage when the voltage divider does the trick?












1














Is there a reason this schematic uses an op amp (AD8031) for the reference voltage of the op amp (AD8544) filter when the voltage divider already brings down the voltage anyways? Can the AD8031 op amp be removed? Also, to save power, can the voltage divider be replaced with a buck converter?



enter image description here










share|improve this question





























    1














    Is there a reason this schematic uses an op amp (AD8031) for the reference voltage of the op amp (AD8544) filter when the voltage divider already brings down the voltage anyways? Can the AD8031 op amp be removed? Also, to save power, can the voltage divider be replaced with a buck converter?



    enter image description here










    share|improve this question



























      1












      1








      1







      Is there a reason this schematic uses an op amp (AD8031) for the reference voltage of the op amp (AD8544) filter when the voltage divider already brings down the voltage anyways? Can the AD8031 op amp be removed? Also, to save power, can the voltage divider be replaced with a buck converter?



      enter image description here










      share|improve this question















      Is there a reason this schematic uses an op amp (AD8031) for the reference voltage of the op amp (AD8544) filter when the voltage divider already brings down the voltage anyways? Can the AD8031 op amp be removed? Also, to save power, can the voltage divider be replaced with a buck converter?



      enter image description here







      power-supply op-amp filter






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 7 hours ago







      Tapatio Sombrero

















      asked 8 hours ago









      Tapatio SombreroTapatio Sombrero

      8715




      8715






















          4 Answers
          4






          active

          oldest

          votes


















          5















          Is there a reason this schematic uses an op amp (AD8031) for the reference voltage of the op amp (AD8544) filter when the voltage divider already brings down the voltage anyways?




          The usual reason to use an op-amp to buffer a divider like this is to ensure the reference voltage doesn't change if whatever it's connected to sinks or sources current.




          Can the AD8031 op amp be removed?




          In this case, since the AD8544 has only 4 pA input bias current, I'd expect the AD8031 can be removed without much change in performance.



          Another issue to watch for, since this reference is connected to two different signals, is whether removing the buffer could allow the two signals to crosstalk with each other. Given the high resistor values connecting the two op-amp inputs to the reference, it's unlikely this would be a real issue, but to be sure you could simply make two different dividers and use one for each of the filter stages.




          Also, to save power, can the voltage divider be replaced with a buck converter?




          Any buck converter will have some output ripple. If you used it here, that ripple would be coupled directly into your filtered signal. I wouldn't do it just to save something like 150 uA. (You'd also need to find a buck converter design with less than 150 uA quiescent current to make this a positve trade)



          If those 150 uA are really important to your application, you might rather find an op-amp with very low quiescent current (the AD8031 has 800 uA, you'd be looking for 10's of uA), replace the AD8031 with that, and increase the resistor values in the divider to 100 kohm or more.



          Aside



          The AD8031(A) is only rated to drive capacitive loads up to 15 pF and maintain stability. C2 and C4 in your schematic are probably causing the op-amp to generate noise (it may even be oscillating) rather than reducing noise. I'd remove them.






          share|improve this answer























          • We don't know what else is hanging off of the V+ line -- if there is something drawing current, then taking out the buffer would screw things up. Agreed on the output capacitance issue. Driving capacitive loads with op-amps is well documented; the OP can do a search or ask here. Here is just one example result from searching on "op-amp capacitive load".
            – TimWescott
            7 hours ago






          • 1




            @TimWescott, true enough. OP, my answer is written assuming you've actually told us everything about your circuit. If you're hiding some part of the circuit, the answer may not actually apply.
            – The Photon
            7 hours ago



















          3















          Is there a reason ...




          Yes. The two 10k reisistors give the voltage reference an impedance of 5k. This means that if the current drawn from the reference changes by 0.1 mA that the voltage of the reference would change by 0.1m x 5k = 0.5 V. This would be a very unstable reference.



          The op-amp buffer fixes this. The output impedance of the buffer is close to zero in comparison. This is a stable reference.




          Can the AD8031 op amp be removed?




          Maybe, but probably not a good idea.




          Also, to save power, can the voltage divider be replaced with a buck converter?




          The voltage divider consumes $ I = frac {V}{R} = frac {3.3}{20k} = 165 mu text A $.



          A buck converter is designed for power supplies rather than a voltage reference. The converter would likely consume more than 165 μA so there would be no advantage.






          share|improve this answer























          • Yup! Fixed thank you.
            – Transistor
            7 hours ago



















          3














          That's a horrible circuit, I wonder where you got it from.



          The AD8031 is very intolerance of capacitive loads, see Figure 46 in the datasheet, so most likely that op-amp will be oscillating at high frequency, which will, at a minimum, cause increased power consumption.



          You can use a TLE2426, which will consume only 170uA typically at 5V.



          Below is a way to connect a conventional op-amp in a stable manner (from a TI ADC datasheet):



          enter image description here



          That's a low-noise high speed amplifier, for yours you might try increasing the resistor values by an order of magnitude.






          share|improve this answer































            0














            I worked with a guy who developed the switch-cap I+Q filters for GSM minimum-shift-keying for a cell-phone.



            Each of the two channels used EIGHT switch-cap pole-zero contributors. Each stage was 2nd order, some were zero-pole, some were pole-pole.



            He gathered up the design equations, talked to various filtering-jocks around the company to learn what non-SPICE tools they used to further model the filter and avoid mistakes. He took his time, and was very thorough.



            The silicon comes back and most of the chip works, including that I+Q filter module. The performance is excellent, the frequency response is excellent, meaning he'd done a fine job in describing the various parasitics, and noise floor was excellent.



            People were delighted, because the design and layout he'd developed would be invaluable in the future, for lowering power and reducing area and achieving high-accuracy-frequency-response filtering.



            Except.



            When he overdrove the filter, to evaluate overload recovery, the filter would lock up and only produce a DC output.



            This chip ran on 0/+5v.



            Can you guess what was the problem?






            share|improve this answer























            • You answered the question with a question? (or a test :) I suppose he used one of his fancy filters to generate the V/2 reference voltage?
              – gbarry
              4 hours ago










            • This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
              – Blup1980
              1 hour ago











            Your Answer





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            4 Answers
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            active

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            4 Answers
            4






            active

            oldest

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            active

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            active

            oldest

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            5















            Is there a reason this schematic uses an op amp (AD8031) for the reference voltage of the op amp (AD8544) filter when the voltage divider already brings down the voltage anyways?




            The usual reason to use an op-amp to buffer a divider like this is to ensure the reference voltage doesn't change if whatever it's connected to sinks or sources current.




            Can the AD8031 op amp be removed?




            In this case, since the AD8544 has only 4 pA input bias current, I'd expect the AD8031 can be removed without much change in performance.



            Another issue to watch for, since this reference is connected to two different signals, is whether removing the buffer could allow the two signals to crosstalk with each other. Given the high resistor values connecting the two op-amp inputs to the reference, it's unlikely this would be a real issue, but to be sure you could simply make two different dividers and use one for each of the filter stages.




            Also, to save power, can the voltage divider be replaced with a buck converter?




            Any buck converter will have some output ripple. If you used it here, that ripple would be coupled directly into your filtered signal. I wouldn't do it just to save something like 150 uA. (You'd also need to find a buck converter design with less than 150 uA quiescent current to make this a positve trade)



            If those 150 uA are really important to your application, you might rather find an op-amp with very low quiescent current (the AD8031 has 800 uA, you'd be looking for 10's of uA), replace the AD8031 with that, and increase the resistor values in the divider to 100 kohm or more.



            Aside



            The AD8031(A) is only rated to drive capacitive loads up to 15 pF and maintain stability. C2 and C4 in your schematic are probably causing the op-amp to generate noise (it may even be oscillating) rather than reducing noise. I'd remove them.






            share|improve this answer























            • We don't know what else is hanging off of the V+ line -- if there is something drawing current, then taking out the buffer would screw things up. Agreed on the output capacitance issue. Driving capacitive loads with op-amps is well documented; the OP can do a search or ask here. Here is just one example result from searching on "op-amp capacitive load".
              – TimWescott
              7 hours ago






            • 1




              @TimWescott, true enough. OP, my answer is written assuming you've actually told us everything about your circuit. If you're hiding some part of the circuit, the answer may not actually apply.
              – The Photon
              7 hours ago
















            5















            Is there a reason this schematic uses an op amp (AD8031) for the reference voltage of the op amp (AD8544) filter when the voltage divider already brings down the voltage anyways?




            The usual reason to use an op-amp to buffer a divider like this is to ensure the reference voltage doesn't change if whatever it's connected to sinks or sources current.




            Can the AD8031 op amp be removed?




            In this case, since the AD8544 has only 4 pA input bias current, I'd expect the AD8031 can be removed without much change in performance.



            Another issue to watch for, since this reference is connected to two different signals, is whether removing the buffer could allow the two signals to crosstalk with each other. Given the high resistor values connecting the two op-amp inputs to the reference, it's unlikely this would be a real issue, but to be sure you could simply make two different dividers and use one for each of the filter stages.




            Also, to save power, can the voltage divider be replaced with a buck converter?




            Any buck converter will have some output ripple. If you used it here, that ripple would be coupled directly into your filtered signal. I wouldn't do it just to save something like 150 uA. (You'd also need to find a buck converter design with less than 150 uA quiescent current to make this a positve trade)



            If those 150 uA are really important to your application, you might rather find an op-amp with very low quiescent current (the AD8031 has 800 uA, you'd be looking for 10's of uA), replace the AD8031 with that, and increase the resistor values in the divider to 100 kohm or more.



            Aside



            The AD8031(A) is only rated to drive capacitive loads up to 15 pF and maintain stability. C2 and C4 in your schematic are probably causing the op-amp to generate noise (it may even be oscillating) rather than reducing noise. I'd remove them.






            share|improve this answer























            • We don't know what else is hanging off of the V+ line -- if there is something drawing current, then taking out the buffer would screw things up. Agreed on the output capacitance issue. Driving capacitive loads with op-amps is well documented; the OP can do a search or ask here. Here is just one example result from searching on "op-amp capacitive load".
              – TimWescott
              7 hours ago






            • 1




              @TimWescott, true enough. OP, my answer is written assuming you've actually told us everything about your circuit. If you're hiding some part of the circuit, the answer may not actually apply.
              – The Photon
              7 hours ago














            5












            5








            5







            Is there a reason this schematic uses an op amp (AD8031) for the reference voltage of the op amp (AD8544) filter when the voltage divider already brings down the voltage anyways?




            The usual reason to use an op-amp to buffer a divider like this is to ensure the reference voltage doesn't change if whatever it's connected to sinks or sources current.




            Can the AD8031 op amp be removed?




            In this case, since the AD8544 has only 4 pA input bias current, I'd expect the AD8031 can be removed without much change in performance.



            Another issue to watch for, since this reference is connected to two different signals, is whether removing the buffer could allow the two signals to crosstalk with each other. Given the high resistor values connecting the two op-amp inputs to the reference, it's unlikely this would be a real issue, but to be sure you could simply make two different dividers and use one for each of the filter stages.




            Also, to save power, can the voltage divider be replaced with a buck converter?




            Any buck converter will have some output ripple. If you used it here, that ripple would be coupled directly into your filtered signal. I wouldn't do it just to save something like 150 uA. (You'd also need to find a buck converter design with less than 150 uA quiescent current to make this a positve trade)



            If those 150 uA are really important to your application, you might rather find an op-amp with very low quiescent current (the AD8031 has 800 uA, you'd be looking for 10's of uA), replace the AD8031 with that, and increase the resistor values in the divider to 100 kohm or more.



            Aside



            The AD8031(A) is only rated to drive capacitive loads up to 15 pF and maintain stability. C2 and C4 in your schematic are probably causing the op-amp to generate noise (it may even be oscillating) rather than reducing noise. I'd remove them.






            share|improve this answer















            Is there a reason this schematic uses an op amp (AD8031) for the reference voltage of the op amp (AD8544) filter when the voltage divider already brings down the voltage anyways?




            The usual reason to use an op-amp to buffer a divider like this is to ensure the reference voltage doesn't change if whatever it's connected to sinks or sources current.




            Can the AD8031 op amp be removed?




            In this case, since the AD8544 has only 4 pA input bias current, I'd expect the AD8031 can be removed without much change in performance.



            Another issue to watch for, since this reference is connected to two different signals, is whether removing the buffer could allow the two signals to crosstalk with each other. Given the high resistor values connecting the two op-amp inputs to the reference, it's unlikely this would be a real issue, but to be sure you could simply make two different dividers and use one for each of the filter stages.




            Also, to save power, can the voltage divider be replaced with a buck converter?




            Any buck converter will have some output ripple. If you used it here, that ripple would be coupled directly into your filtered signal. I wouldn't do it just to save something like 150 uA. (You'd also need to find a buck converter design with less than 150 uA quiescent current to make this a positve trade)



            If those 150 uA are really important to your application, you might rather find an op-amp with very low quiescent current (the AD8031 has 800 uA, you'd be looking for 10's of uA), replace the AD8031 with that, and increase the resistor values in the divider to 100 kohm or more.



            Aside



            The AD8031(A) is only rated to drive capacitive loads up to 15 pF and maintain stability. C2 and C4 in your schematic are probably causing the op-amp to generate noise (it may even be oscillating) rather than reducing noise. I'd remove them.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 7 hours ago

























            answered 7 hours ago









            The PhotonThe Photon

            83.6k396194




            83.6k396194












            • We don't know what else is hanging off of the V+ line -- if there is something drawing current, then taking out the buffer would screw things up. Agreed on the output capacitance issue. Driving capacitive loads with op-amps is well documented; the OP can do a search or ask here. Here is just one example result from searching on "op-amp capacitive load".
              – TimWescott
              7 hours ago






            • 1




              @TimWescott, true enough. OP, my answer is written assuming you've actually told us everything about your circuit. If you're hiding some part of the circuit, the answer may not actually apply.
              – The Photon
              7 hours ago


















            • We don't know what else is hanging off of the V+ line -- if there is something drawing current, then taking out the buffer would screw things up. Agreed on the output capacitance issue. Driving capacitive loads with op-amps is well documented; the OP can do a search or ask here. Here is just one example result from searching on "op-amp capacitive load".
              – TimWescott
              7 hours ago






            • 1




              @TimWescott, true enough. OP, my answer is written assuming you've actually told us everything about your circuit. If you're hiding some part of the circuit, the answer may not actually apply.
              – The Photon
              7 hours ago
















            We don't know what else is hanging off of the V+ line -- if there is something drawing current, then taking out the buffer would screw things up. Agreed on the output capacitance issue. Driving capacitive loads with op-amps is well documented; the OP can do a search or ask here. Here is just one example result from searching on "op-amp capacitive load".
            – TimWescott
            7 hours ago




            We don't know what else is hanging off of the V+ line -- if there is something drawing current, then taking out the buffer would screw things up. Agreed on the output capacitance issue. Driving capacitive loads with op-amps is well documented; the OP can do a search or ask here. Here is just one example result from searching on "op-amp capacitive load".
            – TimWescott
            7 hours ago




            1




            1




            @TimWescott, true enough. OP, my answer is written assuming you've actually told us everything about your circuit. If you're hiding some part of the circuit, the answer may not actually apply.
            – The Photon
            7 hours ago




            @TimWescott, true enough. OP, my answer is written assuming you've actually told us everything about your circuit. If you're hiding some part of the circuit, the answer may not actually apply.
            – The Photon
            7 hours ago













            3















            Is there a reason ...




            Yes. The two 10k reisistors give the voltage reference an impedance of 5k. This means that if the current drawn from the reference changes by 0.1 mA that the voltage of the reference would change by 0.1m x 5k = 0.5 V. This would be a very unstable reference.



            The op-amp buffer fixes this. The output impedance of the buffer is close to zero in comparison. This is a stable reference.




            Can the AD8031 op amp be removed?




            Maybe, but probably not a good idea.




            Also, to save power, can the voltage divider be replaced with a buck converter?




            The voltage divider consumes $ I = frac {V}{R} = frac {3.3}{20k} = 165 mu text A $.



            A buck converter is designed for power supplies rather than a voltage reference. The converter would likely consume more than 165 μA so there would be no advantage.






            share|improve this answer























            • Yup! Fixed thank you.
              – Transistor
              7 hours ago
















            3















            Is there a reason ...




            Yes. The two 10k reisistors give the voltage reference an impedance of 5k. This means that if the current drawn from the reference changes by 0.1 mA that the voltage of the reference would change by 0.1m x 5k = 0.5 V. This would be a very unstable reference.



            The op-amp buffer fixes this. The output impedance of the buffer is close to zero in comparison. This is a stable reference.




            Can the AD8031 op amp be removed?




            Maybe, but probably not a good idea.




            Also, to save power, can the voltage divider be replaced with a buck converter?




            The voltage divider consumes $ I = frac {V}{R} = frac {3.3}{20k} = 165 mu text A $.



            A buck converter is designed for power supplies rather than a voltage reference. The converter would likely consume more than 165 μA so there would be no advantage.






            share|improve this answer























            • Yup! Fixed thank you.
              – Transistor
              7 hours ago














            3












            3








            3







            Is there a reason ...




            Yes. The two 10k reisistors give the voltage reference an impedance of 5k. This means that if the current drawn from the reference changes by 0.1 mA that the voltage of the reference would change by 0.1m x 5k = 0.5 V. This would be a very unstable reference.



            The op-amp buffer fixes this. The output impedance of the buffer is close to zero in comparison. This is a stable reference.




            Can the AD8031 op amp be removed?




            Maybe, but probably not a good idea.




            Also, to save power, can the voltage divider be replaced with a buck converter?




            The voltage divider consumes $ I = frac {V}{R} = frac {3.3}{20k} = 165 mu text A $.



            A buck converter is designed for power supplies rather than a voltage reference. The converter would likely consume more than 165 μA so there would be no advantage.






            share|improve this answer















            Is there a reason ...




            Yes. The two 10k reisistors give the voltage reference an impedance of 5k. This means that if the current drawn from the reference changes by 0.1 mA that the voltage of the reference would change by 0.1m x 5k = 0.5 V. This would be a very unstable reference.



            The op-amp buffer fixes this. The output impedance of the buffer is close to zero in comparison. This is a stable reference.




            Can the AD8031 op amp be removed?




            Maybe, but probably not a good idea.




            Also, to save power, can the voltage divider be replaced with a buck converter?




            The voltage divider consumes $ I = frac {V}{R} = frac {3.3}{20k} = 165 mu text A $.



            A buck converter is designed for power supplies rather than a voltage reference. The converter would likely consume more than 165 μA so there would be no advantage.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 7 hours ago

























            answered 7 hours ago









            TransistorTransistor

            81k778174




            81k778174












            • Yup! Fixed thank you.
              – Transistor
              7 hours ago


















            • Yup! Fixed thank you.
              – Transistor
              7 hours ago
















            Yup! Fixed thank you.
            – Transistor
            7 hours ago




            Yup! Fixed thank you.
            – Transistor
            7 hours ago











            3














            That's a horrible circuit, I wonder where you got it from.



            The AD8031 is very intolerance of capacitive loads, see Figure 46 in the datasheet, so most likely that op-amp will be oscillating at high frequency, which will, at a minimum, cause increased power consumption.



            You can use a TLE2426, which will consume only 170uA typically at 5V.



            Below is a way to connect a conventional op-amp in a stable manner (from a TI ADC datasheet):



            enter image description here



            That's a low-noise high speed amplifier, for yours you might try increasing the resistor values by an order of magnitude.






            share|improve this answer




























              3














              That's a horrible circuit, I wonder where you got it from.



              The AD8031 is very intolerance of capacitive loads, see Figure 46 in the datasheet, so most likely that op-amp will be oscillating at high frequency, which will, at a minimum, cause increased power consumption.



              You can use a TLE2426, which will consume only 170uA typically at 5V.



              Below is a way to connect a conventional op-amp in a stable manner (from a TI ADC datasheet):



              enter image description here



              That's a low-noise high speed amplifier, for yours you might try increasing the resistor values by an order of magnitude.






              share|improve this answer


























                3












                3








                3






                That's a horrible circuit, I wonder where you got it from.



                The AD8031 is very intolerance of capacitive loads, see Figure 46 in the datasheet, so most likely that op-amp will be oscillating at high frequency, which will, at a minimum, cause increased power consumption.



                You can use a TLE2426, which will consume only 170uA typically at 5V.



                Below is a way to connect a conventional op-amp in a stable manner (from a TI ADC datasheet):



                enter image description here



                That's a low-noise high speed amplifier, for yours you might try increasing the resistor values by an order of magnitude.






                share|improve this answer














                That's a horrible circuit, I wonder where you got it from.



                The AD8031 is very intolerance of capacitive loads, see Figure 46 in the datasheet, so most likely that op-amp will be oscillating at high frequency, which will, at a minimum, cause increased power consumption.



                You can use a TLE2426, which will consume only 170uA typically at 5V.



                Below is a way to connect a conventional op-amp in a stable manner (from a TI ADC datasheet):



                enter image description here



                That's a low-noise high speed amplifier, for yours you might try increasing the resistor values by an order of magnitude.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 7 hours ago

























                answered 7 hours ago









                Spehro PefhanySpehro Pefhany

                204k4150408




                204k4150408























                    0














                    I worked with a guy who developed the switch-cap I+Q filters for GSM minimum-shift-keying for a cell-phone.



                    Each of the two channels used EIGHT switch-cap pole-zero contributors. Each stage was 2nd order, some were zero-pole, some were pole-pole.



                    He gathered up the design equations, talked to various filtering-jocks around the company to learn what non-SPICE tools they used to further model the filter and avoid mistakes. He took his time, and was very thorough.



                    The silicon comes back and most of the chip works, including that I+Q filter module. The performance is excellent, the frequency response is excellent, meaning he'd done a fine job in describing the various parasitics, and noise floor was excellent.



                    People were delighted, because the design and layout he'd developed would be invaluable in the future, for lowering power and reducing area and achieving high-accuracy-frequency-response filtering.



                    Except.



                    When he overdrove the filter, to evaluate overload recovery, the filter would lock up and only produce a DC output.



                    This chip ran on 0/+5v.



                    Can you guess what was the problem?






                    share|improve this answer























                    • You answered the question with a question? (or a test :) I suppose he used one of his fancy filters to generate the V/2 reference voltage?
                      – gbarry
                      4 hours ago










                    • This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
                      – Blup1980
                      1 hour ago
















                    0














                    I worked with a guy who developed the switch-cap I+Q filters for GSM minimum-shift-keying for a cell-phone.



                    Each of the two channels used EIGHT switch-cap pole-zero contributors. Each stage was 2nd order, some were zero-pole, some were pole-pole.



                    He gathered up the design equations, talked to various filtering-jocks around the company to learn what non-SPICE tools they used to further model the filter and avoid mistakes. He took his time, and was very thorough.



                    The silicon comes back and most of the chip works, including that I+Q filter module. The performance is excellent, the frequency response is excellent, meaning he'd done a fine job in describing the various parasitics, and noise floor was excellent.



                    People were delighted, because the design and layout he'd developed would be invaluable in the future, for lowering power and reducing area and achieving high-accuracy-frequency-response filtering.



                    Except.



                    When he overdrove the filter, to evaluate overload recovery, the filter would lock up and only produce a DC output.



                    This chip ran on 0/+5v.



                    Can you guess what was the problem?






                    share|improve this answer























                    • You answered the question with a question? (or a test :) I suppose he used one of his fancy filters to generate the V/2 reference voltage?
                      – gbarry
                      4 hours ago










                    • This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
                      – Blup1980
                      1 hour ago














                    0












                    0








                    0






                    I worked with a guy who developed the switch-cap I+Q filters for GSM minimum-shift-keying for a cell-phone.



                    Each of the two channels used EIGHT switch-cap pole-zero contributors. Each stage was 2nd order, some were zero-pole, some were pole-pole.



                    He gathered up the design equations, talked to various filtering-jocks around the company to learn what non-SPICE tools they used to further model the filter and avoid mistakes. He took his time, and was very thorough.



                    The silicon comes back and most of the chip works, including that I+Q filter module. The performance is excellent, the frequency response is excellent, meaning he'd done a fine job in describing the various parasitics, and noise floor was excellent.



                    People were delighted, because the design and layout he'd developed would be invaluable in the future, for lowering power and reducing area and achieving high-accuracy-frequency-response filtering.



                    Except.



                    When he overdrove the filter, to evaluate overload recovery, the filter would lock up and only produce a DC output.



                    This chip ran on 0/+5v.



                    Can you guess what was the problem?






                    share|improve this answer














                    I worked with a guy who developed the switch-cap I+Q filters for GSM minimum-shift-keying for a cell-phone.



                    Each of the two channels used EIGHT switch-cap pole-zero contributors. Each stage was 2nd order, some were zero-pole, some were pole-pole.



                    He gathered up the design equations, talked to various filtering-jocks around the company to learn what non-SPICE tools they used to further model the filter and avoid mistakes. He took his time, and was very thorough.



                    The silicon comes back and most of the chip works, including that I+Q filter module. The performance is excellent, the frequency response is excellent, meaning he'd done a fine job in describing the various parasitics, and noise floor was excellent.



                    People were delighted, because the design and layout he'd developed would be invaluable in the future, for lowering power and reducing area and achieving high-accuracy-frequency-response filtering.



                    Except.



                    When he overdrove the filter, to evaluate overload recovery, the filter would lock up and only produce a DC output.



                    This chip ran on 0/+5v.



                    Can you guess what was the problem?







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 6 hours ago

























                    answered 6 hours ago









                    analogsystemsrfanalogsystemsrf

                    13.8k2717




                    13.8k2717












                    • You answered the question with a question? (or a test :) I suppose he used one of his fancy filters to generate the V/2 reference voltage?
                      – gbarry
                      4 hours ago










                    • This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
                      – Blup1980
                      1 hour ago


















                    • You answered the question with a question? (or a test :) I suppose he used one of his fancy filters to generate the V/2 reference voltage?
                      – gbarry
                      4 hours ago










                    • This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
                      – Blup1980
                      1 hour ago
















                    You answered the question with a question? (or a test :) I suppose he used one of his fancy filters to generate the V/2 reference voltage?
                    – gbarry
                    4 hours ago




                    You answered the question with a question? (or a test :) I suppose he used one of his fancy filters to generate the V/2 reference voltage?
                    – gbarry
                    4 hours ago












                    This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
                    – Blup1980
                    1 hour ago




                    This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
                    – Blup1980
                    1 hour ago


















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