What is the class of function that when called repeatedly, has the same effect as calling once?
A function that fulfills this criteria is
int var = 0;
void func1()
{
var = 10;
}
As you can see, calling fun1 10 times has the same effect as calling it once (assigns 10 to var)
A function that does not fulfill this criteria is
int var = 0;
void func2()
{
var++;
}
Calling func2 10 times results in var being assigned a different value as compared to calling func2 once
naming functions
asked 4 hours ago
WoofasWoofas
27713
add a comment |
A function that fulfills this criteria is
int var = 0;
void func1()
{
var = 10;
}
As you can see, calling fun1 10 times has the same effect as calling it once (assigns 10 to var)
A function that does not fulfill this criteria is
int var = 0;
void func2()
{
var++;
}
Calling func2 10 times results in var being assigned a different value as compared to calling func2 once
naming functions
asked 4 hours ago
WoofasWoofas
27713
add a comment |
A function that fulfills this criteria is
int var = 0;
void func1()
{
var = 10;
}
As you can see, calling fun1 10 times has the same effect as calling it once (assigns 10 to var)
A function that does not fulfill this criteria is
int var = 0;
void func2()
{
var++;
}
Calling func2 10 times results in var being assigned a different value as compared to calling func2 once
naming functions
asked 4 hours ago
WoofasWoofas
27713
A function that fulfills this criteria is
int var = 0;
void func1()
{
var = 10;
}
As you can see, calling fun1 10 times has the same effect as calling it once (assigns 10 to var)
A function that does not fulfill this criteria is
int var = 0;
void func2()
{
var++;
}
Calling func2 10 times results in var being assigned a different value as compared to calling func2 once
naming functions
naming functions
asked 4 hours ago
WoofasWoofas
27713
asked 4 hours ago
WoofasWoofas
27713
asked 4 hours ago
WoofasWoofas
27713
asked 4 hours ago
WoofasWoofas
27713
asked 4 hours ago
WoofasWoofas
27713
27713
add a comment |
add a comment |
2 Answers
2
active
oldest
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This type of function / operation is called Idempotent
Idempotence (UK: /ˌɪdɛmˈpoʊtəns/,[1] US: /ˌaɪdəm-/)[2] is the property of certain operations in mathematics and computer science whereby they can be applied multiple times without changing the result beyond the initial application.
answered 4 hours ago
WoofasWoofas
27713
add a comment |
The precise term for this is as @Woofas mentions, is idempotence. I wanted to add that while you could call your func1 method idempotent, you could not call it a pure function. The properties of a pure function are two: it must be idempotent and it must not have side effects, which is to say, no mutation of local static variables, non-local variables, mutable reference arguments or I/O streams.
The reason I mention this is that a idempotent function with side effects is not good either, since technically idempotent refers to the return ouptut of the function, and not to the side effects. So technically your func2 method is idempotent, as the output doesn't change according to the input.
You most likely want to specify that you want a pure function. An example of a pure function might be as follows:
int func1(int var)
{
return var + 1;
}
More reading can be found here.
answered 6 mins ago
NeilNeil
19.7k3566
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
This type of function / operation is called Idempotent
Idempotence (UK: /ˌɪdɛmˈpoʊtəns/,[1] US: /ˌaɪdəm-/)[2] is the property of certain operations in mathematics and computer science whereby they can be applied multiple times without changing the result beyond the initial application.
answered 4 hours ago
WoofasWoofas
27713
add a comment |
This type of function / operation is called Idempotent
Idempotence (UK: /ˌɪdɛmˈpoʊtəns/,[1] US: /ˌaɪdəm-/)[2] is the property of certain operations in mathematics and computer science whereby they can be applied multiple times without changing the result beyond the initial application.
answered 4 hours ago
WoofasWoofas
27713
add a comment |
This type of function / operation is called Idempotent
Idempotence (UK: /ˌɪdɛmˈpoʊtəns/,[1] US: /ˌaɪdəm-/)[2] is the property of certain operations in mathematics and computer science whereby they can be applied multiple times without changing the result beyond the initial application.
answered 4 hours ago
WoofasWoofas
27713
This type of function / operation is called Idempotent
Idempotence (UK: /ˌɪdɛmˈpoʊtəns/,[1] US: /ˌaɪdəm-/)[2] is the property of certain operations in mathematics and computer science whereby they can be applied multiple times without changing the result beyond the initial application.
answered 4 hours ago
WoofasWoofas
27713
answered 4 hours ago
WoofasWoofas
27713
answered 4 hours ago
WoofasWoofas
27713
answered 4 hours ago
WoofasWoofas
27713
27713
add a comment |
add a comment |
The precise term for this is as @Woofas mentions, is idempotence. I wanted to add that while you could call your func1 method idempotent, you could not call it a pure function. The properties of a pure function are two: it must be idempotent and it must not have side effects, which is to say, no mutation of local static variables, non-local variables, mutable reference arguments or I/O streams.
The reason I mention this is that a idempotent function with side effects is not good either, since technically idempotent refers to the return ouptut of the function, and not to the side effects. So technically your func2 method is idempotent, as the output doesn't change according to the input.
You most likely want to specify that you want a pure function. An example of a pure function might be as follows:
int func1(int var)
{
return var + 1;
}
More reading can be found here.
answered 6 mins ago
NeilNeil
19.7k3566
add a comment |
The precise term for this is as @Woofas mentions, is idempotence. I wanted to add that while you could call your func1 method idempotent, you could not call it a pure function. The properties of a pure function are two: it must be idempotent and it must not have side effects, which is to say, no mutation of local static variables, non-local variables, mutable reference arguments or I/O streams.
The reason I mention this is that a idempotent function with side effects is not good either, since technically idempotent refers to the return ouptut of the function, and not to the side effects. So technically your func2 method is idempotent, as the output doesn't change according to the input.
You most likely want to specify that you want a pure function. An example of a pure function might be as follows:
int func1(int var)
{
return var + 1;
}
More reading can be found here.
answered 6 mins ago
NeilNeil
19.7k3566
add a comment |
The precise term for this is as @Woofas mentions, is idempotence. I wanted to add that while you could call your func1 method idempotent, you could not call it a pure function. The properties of a pure function are two: it must be idempotent and it must not have side effects, which is to say, no mutation of local static variables, non-local variables, mutable reference arguments or I/O streams.
The reason I mention this is that a idempotent function with side effects is not good either, since technically idempotent refers to the return ouptut of the function, and not to the side effects. So technically your func2 method is idempotent, as the output doesn't change according to the input.
You most likely want to specify that you want a pure function. An example of a pure function might be as follows:
int func1(int var)
{
return var + 1;
}
More reading can be found here.
answered 6 mins ago
NeilNeil
19.7k3566
The precise term for this is as @Woofas mentions, is idempotence. I wanted to add that while you could call your func1 method idempotent, you could not call it a pure function. The properties of a pure function are two: it must be idempotent and it must not have side effects, which is to say, no mutation of local static variables, non-local variables, mutable reference arguments or I/O streams.
The reason I mention this is that a idempotent function with side effects is not good either, since technically idempotent refers to the return ouptut of the function, and not to the side effects. So technically your func2 method is idempotent, as the output doesn't change according to the input.
You most likely want to specify that you want a pure function. An example of a pure function might be as follows:
int func1(int var)
{
return var + 1;
}
More reading can be found here.
answered 6 mins ago
NeilNeil
19.7k3566
answered 6 mins ago
NeilNeil
19.7k3566
answered 6 mins ago
NeilNeil
19.7k3566
answered 6 mins ago
NeilNeil
19.7k3566
19.7k3566
add a comment |
add a comment |
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