Energy of the particles in the particle accelerator












2












$begingroup$


Recently I came across something and I was surprised. I always thought that huge amount of energy is required to accelerate particles in the accelerator in the particle physics.But looks like no. The peak energy of proton beams at the LHC now is around 7 trillion electron Volts (TeV), which is only like 0.00000121J. So energy involved in particles accelerators is not that much then or am I missing something.? May be since the mass of these partciles is so small, their velocity needs to really high to get this much energy and may be that is the big deal.?






particle-physics standard-model







share|cite|improve this question









$endgroup$








  • 2




    $begingroup$
    7 TeVs are over 11 ergs! 7000 times more than the mass of a proton is not a lot? At the moment of impact, energywise, the protons are mostly kinetic energy. How do you define "that much"?
    $endgroup$
    – Cosmas Zachos
    6 hours ago






  • 1




    $begingroup$
    @CosmasZachos I think the OP means that LHC energy is not that high compared to other energy scales in nature, for instance in this list (which includes the LHC value too) here - en.wikipedia.org/wiki/Orders_of_magnitude_(energy)
    $endgroup$
    – Avantgarde
    4 hours ago










  • $begingroup$
    Similarly, energy of superlasers is not "that much" either. The key point is not the absolute amount of energy, but it's intensity, concentration in the small amount of matter, like in LHC, or in small volume and time window, like the laser power of the fusion projects.
    $endgroup$
    – Poutnik
    15 mins ago










  • $begingroup$
    Imagine energy needed to accelerate 1 g of protons. You would need energy equivalent to anihilation of 2x3.5 kg of matter and antimatter. Or fusion of about 1000 kg of hydrogen to helium, if I remember correctly .
    $endgroup$
    – Poutnik
    9 mins ago


















2












$begingroup$


Recently I came across something and I was surprised. I always thought that huge amount of energy is required to accelerate particles in the accelerator in the particle physics.But looks like no. The peak energy of proton beams at the LHC now is around 7 trillion electron Volts (TeV), which is only like 0.00000121J. So energy involved in particles accelerators is not that much then or am I missing something.? May be since the mass of these partciles is so small, their velocity needs to really high to get this much energy and may be that is the big deal.?






particle-physics standard-model







share|cite|improve this question









$endgroup$








  • 2




    $begingroup$
    7 TeVs are over 11 ergs! 7000 times more than the mass of a proton is not a lot? At the moment of impact, energywise, the protons are mostly kinetic energy. How do you define "that much"?
    $endgroup$
    – Cosmas Zachos
    6 hours ago






  • 1




    $begingroup$
    @CosmasZachos I think the OP means that LHC energy is not that high compared to other energy scales in nature, for instance in this list (which includes the LHC value too) here - en.wikipedia.org/wiki/Orders_of_magnitude_(energy)
    $endgroup$
    – Avantgarde
    4 hours ago










  • $begingroup$
    Similarly, energy of superlasers is not "that much" either. The key point is not the absolute amount of energy, but it's intensity, concentration in the small amount of matter, like in LHC, or in small volume and time window, like the laser power of the fusion projects.
    $endgroup$
    – Poutnik
    15 mins ago










  • $begingroup$
    Imagine energy needed to accelerate 1 g of protons. You would need energy equivalent to anihilation of 2x3.5 kg of matter and antimatter. Or fusion of about 1000 kg of hydrogen to helium, if I remember correctly .
    $endgroup$
    – Poutnik
    9 mins ago
















2












2








2





$begingroup$


Recently I came across something and I was surprised. I always thought that huge amount of energy is required to accelerate particles in the accelerator in the particle physics.But looks like no. The peak energy of proton beams at the LHC now is around 7 trillion electron Volts (TeV), which is only like 0.00000121J. So energy involved in particles accelerators is not that much then or am I missing something.? May be since the mass of these partciles is so small, their velocity needs to really high to get this much energy and may be that is the big deal.?






particle-physics standard-model







share|cite|improve this question









$endgroup$




Recently I came across something and I was surprised. I always thought that huge amount of energy is required to accelerate particles in the accelerator in the particle physics.But looks like no. The peak energy of proton beams at the LHC now is around 7 trillion electron Volts (TeV), which is only like 0.00000121J. So energy involved in particles accelerators is not that much then or am I missing something.? May be since the mass of these partciles is so small, their velocity needs to really high to get this much energy and may be that is the big deal.?






particle-physics standard-model




particle-physics standard-model






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 7 hours ago









user31058user31058

488614




488614








  • 2




    $begingroup$
    7 TeVs are over 11 ergs! 7000 times more than the mass of a proton is not a lot? At the moment of impact, energywise, the protons are mostly kinetic energy. How do you define "that much"?
    $endgroup$
    – Cosmas Zachos
    6 hours ago






  • 1




    $begingroup$
    @CosmasZachos I think the OP means that LHC energy is not that high compared to other energy scales in nature, for instance in this list (which includes the LHC value too) here - en.wikipedia.org/wiki/Orders_of_magnitude_(energy)
    $endgroup$
    – Avantgarde
    4 hours ago










  • $begingroup$
    Similarly, energy of superlasers is not "that much" either. The key point is not the absolute amount of energy, but it's intensity, concentration in the small amount of matter, like in LHC, or in small volume and time window, like the laser power of the fusion projects.
    $endgroup$
    – Poutnik
    15 mins ago










  • $begingroup$
    Imagine energy needed to accelerate 1 g of protons. You would need energy equivalent to anihilation of 2x3.5 kg of matter and antimatter. Or fusion of about 1000 kg of hydrogen to helium, if I remember correctly .
    $endgroup$
    – Poutnik
    9 mins ago
















  • 2




    $begingroup$
    7 TeVs are over 11 ergs! 7000 times more than the mass of a proton is not a lot? At the moment of impact, energywise, the protons are mostly kinetic energy. How do you define "that much"?
    $endgroup$
    – Cosmas Zachos
    6 hours ago






  • 1




    $begingroup$
    @CosmasZachos I think the OP means that LHC energy is not that high compared to other energy scales in nature, for instance in this list (which includes the LHC value too) here - en.wikipedia.org/wiki/Orders_of_magnitude_(energy)
    $endgroup$
    – Avantgarde
    4 hours ago










  • $begingroup$
    Similarly, energy of superlasers is not "that much" either. The key point is not the absolute amount of energy, but it's intensity, concentration in the small amount of matter, like in LHC, or in small volume and time window, like the laser power of the fusion projects.
    $endgroup$
    – Poutnik
    15 mins ago










  • $begingroup$
    Imagine energy needed to accelerate 1 g of protons. You would need energy equivalent to anihilation of 2x3.5 kg of matter and antimatter. Or fusion of about 1000 kg of hydrogen to helium, if I remember correctly .
    $endgroup$
    – Poutnik
    9 mins ago










2




2




$begingroup$
7 TeVs are over 11 ergs! 7000 times more than the mass of a proton is not a lot? At the moment of impact, energywise, the protons are mostly kinetic energy. How do you define "that much"?
$endgroup$
– Cosmas Zachos
6 hours ago




$begingroup$
7 TeVs are over 11 ergs! 7000 times more than the mass of a proton is not a lot? At the moment of impact, energywise, the protons are mostly kinetic energy. How do you define "that much"?
$endgroup$
– Cosmas Zachos
6 hours ago




1




1




$begingroup$
@CosmasZachos I think the OP means that LHC energy is not that high compared to other energy scales in nature, for instance in this list (which includes the LHC value too) here - en.wikipedia.org/wiki/Orders_of_magnitude_(energy)
$endgroup$
– Avantgarde
4 hours ago




$begingroup$
@CosmasZachos I think the OP means that LHC energy is not that high compared to other energy scales in nature, for instance in this list (which includes the LHC value too) here - en.wikipedia.org/wiki/Orders_of_magnitude_(energy)
$endgroup$
– Avantgarde
4 hours ago












$begingroup$
Similarly, energy of superlasers is not "that much" either. The key point is not the absolute amount of energy, but it's intensity, concentration in the small amount of matter, like in LHC, or in small volume and time window, like the laser power of the fusion projects.
$endgroup$
– Poutnik
15 mins ago




$begingroup$
Similarly, energy of superlasers is not "that much" either. The key point is not the absolute amount of energy, but it's intensity, concentration in the small amount of matter, like in LHC, or in small volume and time window, like the laser power of the fusion projects.
$endgroup$
– Poutnik
15 mins ago












$begingroup$
Imagine energy needed to accelerate 1 g of protons. You would need energy equivalent to anihilation of 2x3.5 kg of matter and antimatter. Or fusion of about 1000 kg of hydrogen to helium, if I remember correctly .
$endgroup$
– Poutnik
9 mins ago






$begingroup$
Imagine energy needed to accelerate 1 g of protons. You would need energy equivalent to anihilation of 2x3.5 kg of matter and antimatter. Or fusion of about 1000 kg of hydrogen to helium, if I remember correctly .
$endgroup$
– Poutnik
9 mins ago












2 Answers
2






active

oldest

votes


















4












$begingroup$

Yes, you are missing something. First, 7 TeV is the energy of each proton. The LHC beam contains 300 trillion protons! Second, the protons continuously lose energy as they radiate synchrotron radiation, so you have to continuously put in energy just to keep them going around at the same speed.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    $300cdot10^{12}$ particles times $0.00000121J$ gives $363 MJ$...
    $endgroup$
    – cmaster
    43 secs ago





















3












$begingroup$

A particle accelerator does not work with one particle at a time. At any moment, there will be billions of particles distributed into a beam (usually with bunches in it). Because they are charged, the particles in the beam represent a current. Electrical power is (current x voltage) and as such the beam packs enough wallop to tear holes in the beam tube and wreak havoc upon the equipment nearby if it gets out of control.






share|cite|improve this answer









$endgroup$













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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4












    $begingroup$

    Yes, you are missing something. First, 7 TeV is the energy of each proton. The LHC beam contains 300 trillion protons! Second, the protons continuously lose energy as they radiate synchrotron radiation, so you have to continuously put in energy just to keep them going around at the same speed.






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      $300cdot10^{12}$ particles times $0.00000121J$ gives $363 MJ$...
      $endgroup$
      – cmaster
      43 secs ago


















    4












    $begingroup$

    Yes, you are missing something. First, 7 TeV is the energy of each proton. The LHC beam contains 300 trillion protons! Second, the protons continuously lose energy as they radiate synchrotron radiation, so you have to continuously put in energy just to keep them going around at the same speed.






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      $300cdot10^{12}$ particles times $0.00000121J$ gives $363 MJ$...
      $endgroup$
      – cmaster
      43 secs ago
















    4












    4








    4





    $begingroup$

    Yes, you are missing something. First, 7 TeV is the energy of each proton. The LHC beam contains 300 trillion protons! Second, the protons continuously lose energy as they radiate synchrotron radiation, so you have to continuously put in energy just to keep them going around at the same speed.






    share|cite|improve this answer









    $endgroup$



    Yes, you are missing something. First, 7 TeV is the energy of each proton. The LHC beam contains 300 trillion protons! Second, the protons continuously lose energy as they radiate synchrotron radiation, so you have to continuously put in energy just to keep them going around at the same speed.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered 5 hours ago









    G. SmithG. Smith

    9,98111428




    9,98111428












    • $begingroup$
      $300cdot10^{12}$ particles times $0.00000121J$ gives $363 MJ$...
      $endgroup$
      – cmaster
      43 secs ago




















    • $begingroup$
      $300cdot10^{12}$ particles times $0.00000121J$ gives $363 MJ$...
      $endgroup$
      – cmaster
      43 secs ago


















    $begingroup$
    $300cdot10^{12}$ particles times $0.00000121J$ gives $363 MJ$...
    $endgroup$
    – cmaster
    43 secs ago






    $begingroup$
    $300cdot10^{12}$ particles times $0.00000121J$ gives $363 MJ$...
    $endgroup$
    – cmaster
    43 secs ago













    3












    $begingroup$

    A particle accelerator does not work with one particle at a time. At any moment, there will be billions of particles distributed into a beam (usually with bunches in it). Because they are charged, the particles in the beam represent a current. Electrical power is (current x voltage) and as such the beam packs enough wallop to tear holes in the beam tube and wreak havoc upon the equipment nearby if it gets out of control.






    share|cite|improve this answer









    $endgroup$


















      3












      $begingroup$

      A particle accelerator does not work with one particle at a time. At any moment, there will be billions of particles distributed into a beam (usually with bunches in it). Because they are charged, the particles in the beam represent a current. Electrical power is (current x voltage) and as such the beam packs enough wallop to tear holes in the beam tube and wreak havoc upon the equipment nearby if it gets out of control.






      share|cite|improve this answer









      $endgroup$
















        3












        3








        3





        $begingroup$

        A particle accelerator does not work with one particle at a time. At any moment, there will be billions of particles distributed into a beam (usually with bunches in it). Because they are charged, the particles in the beam represent a current. Electrical power is (current x voltage) and as such the beam packs enough wallop to tear holes in the beam tube and wreak havoc upon the equipment nearby if it gets out of control.






        share|cite|improve this answer









        $endgroup$



        A particle accelerator does not work with one particle at a time. At any moment, there will be billions of particles distributed into a beam (usually with bunches in it). Because they are charged, the particles in the beam represent a current. Electrical power is (current x voltage) and as such the beam packs enough wallop to tear holes in the beam tube and wreak havoc upon the equipment nearby if it gets out of control.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 5 hours ago









        niels nielsenniels nielsen

        21k53062




        21k53062






























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