How to perform count(), count(distinct) in the same output using POSTGRESQL












0















I am trying to perform both count(distinct(keyword)) and count(keyword) from same tables. Here are the two queries.



Query-1



SELECT t1.count(distinct(keyword)) from keyword t1, sent t2,tweets t3,users t4                                       
WHERE t4.user_id='18839785'
AND t1.id=t2.id AND t2.id=t3.id AND t3.user_id=t4.user_id AND t2.sent='Pos';

count
-------
251
(1 row)


Query-2



SELECT t1.keyword,t1.count(keyword) FROM keyword t1, sent t2,tweets t3,users t4 
WHERE t4.name='narendramodi' AND t3.id=t4.user_id AND t2.id=t3.id
AND t2.id=t1.id AND t2.sent='Pos' GROUP BY t1.nlp_keyword_name order by count(keyword) desc ;

nlp_keyword_name | count
------------------+-------
happy | 5
people | 4
handsome | 4
glad | 3
forward | 3
wishes | 3
proud | 2
(7 rows)


Query-3



SELECT distinct_drivers,positive_drivers,countt
from (

SELECT t1.count(distinct(keyword)) as distinct_drivers ,
t1.nlp_keyword_name as P_drivers,
t1.count(nlp_keyword_name) as countt
FROM keyword t1 LEFT JOIN sent t2 on t1.id=t2.id
LEFT JOIN tweets t3 on t3.id=t2.id
LEFT JOIN users t4 on t4.user_id=t3.user_id
WHERE (t4.user_id)=('18839785') AND t2.sent='Pos' GROUP BY t1.nlp_keyword_name order by countt desc) T;


But I am getting my output as



distinct_drivers | positive_drivers | countt 
------------------+------------------+--------
1 | happy | 5
1 | people | 4
1 | handsome | 4
1 | glad | 3
1 | forward | 3


Here after executing query-3 my output has to be below way which I am not getting like that.



 **desired_output:**

distinct_drivers | positive_drivers | countt
------------------+------------------+--------
251 | happy | 5
251 | people | 4
251 | handsome | 4
251 | glad | 3
251 | forward | 3


Can anyone help me out in achieving desired output. I will be thankful.
resources I have gone through Rolling sum / count / average over date interval









share



























    0















    I am trying to perform both count(distinct(keyword)) and count(keyword) from same tables. Here are the two queries.



    Query-1



    SELECT t1.count(distinct(keyword)) from keyword t1, sent t2,tweets t3,users t4                                       
    WHERE t4.user_id='18839785'
    AND t1.id=t2.id AND t2.id=t3.id AND t3.user_id=t4.user_id AND t2.sent='Pos';

    count
    -------
    251
    (1 row)


    Query-2



    SELECT t1.keyword,t1.count(keyword) FROM keyword t1, sent t2,tweets t3,users t4 
    WHERE t4.name='narendramodi' AND t3.id=t4.user_id AND t2.id=t3.id
    AND t2.id=t1.id AND t2.sent='Pos' GROUP BY t1.nlp_keyword_name order by count(keyword) desc ;

    nlp_keyword_name | count
    ------------------+-------
    happy | 5
    people | 4
    handsome | 4
    glad | 3
    forward | 3
    wishes | 3
    proud | 2
    (7 rows)


    Query-3



    SELECT distinct_drivers,positive_drivers,countt
    from (

    SELECT t1.count(distinct(keyword)) as distinct_drivers ,
    t1.nlp_keyword_name as P_drivers,
    t1.count(nlp_keyword_name) as countt
    FROM keyword t1 LEFT JOIN sent t2 on t1.id=t2.id
    LEFT JOIN tweets t3 on t3.id=t2.id
    LEFT JOIN users t4 on t4.user_id=t3.user_id
    WHERE (t4.user_id)=('18839785') AND t2.sent='Pos' GROUP BY t1.nlp_keyword_name order by countt desc) T;


    But I am getting my output as



    distinct_drivers | positive_drivers | countt 
    ------------------+------------------+--------
    1 | happy | 5
    1 | people | 4
    1 | handsome | 4
    1 | glad | 3
    1 | forward | 3


    Here after executing query-3 my output has to be below way which I am not getting like that.



     **desired_output:**

    distinct_drivers | positive_drivers | countt
    ------------------+------------------+--------
    251 | happy | 5
    251 | people | 4
    251 | handsome | 4
    251 | glad | 3
    251 | forward | 3


    Can anyone help me out in achieving desired output. I will be thankful.
    resources I have gone through Rolling sum / count / average over date interval









    share

























      0












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      0








      I am trying to perform both count(distinct(keyword)) and count(keyword) from same tables. Here are the two queries.



      Query-1



      SELECT t1.count(distinct(keyword)) from keyword t1, sent t2,tweets t3,users t4                                       
      WHERE t4.user_id='18839785'
      AND t1.id=t2.id AND t2.id=t3.id AND t3.user_id=t4.user_id AND t2.sent='Pos';

      count
      -------
      251
      (1 row)


      Query-2



      SELECT t1.keyword,t1.count(keyword) FROM keyword t1, sent t2,tweets t3,users t4 
      WHERE t4.name='narendramodi' AND t3.id=t4.user_id AND t2.id=t3.id
      AND t2.id=t1.id AND t2.sent='Pos' GROUP BY t1.nlp_keyword_name order by count(keyword) desc ;

      nlp_keyword_name | count
      ------------------+-------
      happy | 5
      people | 4
      handsome | 4
      glad | 3
      forward | 3
      wishes | 3
      proud | 2
      (7 rows)


      Query-3



      SELECT distinct_drivers,positive_drivers,countt
      from (

      SELECT t1.count(distinct(keyword)) as distinct_drivers ,
      t1.nlp_keyword_name as P_drivers,
      t1.count(nlp_keyword_name) as countt
      FROM keyword t1 LEFT JOIN sent t2 on t1.id=t2.id
      LEFT JOIN tweets t3 on t3.id=t2.id
      LEFT JOIN users t4 on t4.user_id=t3.user_id
      WHERE (t4.user_id)=('18839785') AND t2.sent='Pos' GROUP BY t1.nlp_keyword_name order by countt desc) T;


      But I am getting my output as



      distinct_drivers | positive_drivers | countt 
      ------------------+------------------+--------
      1 | happy | 5
      1 | people | 4
      1 | handsome | 4
      1 | glad | 3
      1 | forward | 3


      Here after executing query-3 my output has to be below way which I am not getting like that.



       **desired_output:**

      distinct_drivers | positive_drivers | countt
      ------------------+------------------+--------
      251 | happy | 5
      251 | people | 4
      251 | handsome | 4
      251 | glad | 3
      251 | forward | 3


      Can anyone help me out in achieving desired output. I will be thankful.
      resources I have gone through Rolling sum / count / average over date interval









      share














      I am trying to perform both count(distinct(keyword)) and count(keyword) from same tables. Here are the two queries.



      Query-1



      SELECT t1.count(distinct(keyword)) from keyword t1, sent t2,tweets t3,users t4                                       
      WHERE t4.user_id='18839785'
      AND t1.id=t2.id AND t2.id=t3.id AND t3.user_id=t4.user_id AND t2.sent='Pos';

      count
      -------
      251
      (1 row)


      Query-2



      SELECT t1.keyword,t1.count(keyword) FROM keyword t1, sent t2,tweets t3,users t4 
      WHERE t4.name='narendramodi' AND t3.id=t4.user_id AND t2.id=t3.id
      AND t2.id=t1.id AND t2.sent='Pos' GROUP BY t1.nlp_keyword_name order by count(keyword) desc ;

      nlp_keyword_name | count
      ------------------+-------
      happy | 5
      people | 4
      handsome | 4
      glad | 3
      forward | 3
      wishes | 3
      proud | 2
      (7 rows)


      Query-3



      SELECT distinct_drivers,positive_drivers,countt
      from (

      SELECT t1.count(distinct(keyword)) as distinct_drivers ,
      t1.nlp_keyword_name as P_drivers,
      t1.count(nlp_keyword_name) as countt
      FROM keyword t1 LEFT JOIN sent t2 on t1.id=t2.id
      LEFT JOIN tweets t3 on t3.id=t2.id
      LEFT JOIN users t4 on t4.user_id=t3.user_id
      WHERE (t4.user_id)=('18839785') AND t2.sent='Pos' GROUP BY t1.nlp_keyword_name order by countt desc) T;


      But I am getting my output as



      distinct_drivers | positive_drivers | countt 
      ------------------+------------------+--------
      1 | happy | 5
      1 | people | 4
      1 | handsome | 4
      1 | glad | 3
      1 | forward | 3


      Here after executing query-3 my output has to be below way which I am not getting like that.



       **desired_output:**

      distinct_drivers | positive_drivers | countt
      ------------------+------------------+--------
      251 | happy | 5
      251 | people | 4
      251 | handsome | 4
      251 | glad | 3
      251 | forward | 3


      Can anyone help me out in achieving desired output. I will be thankful.
      resources I have gone through Rolling sum / count / average over date interval







      postgresql-9.4





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