Python 3.6+ function to ask for a multiple-choice answer












5












$begingroup$


# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in range(len(options)):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer


I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?










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  • $begingroup$
    "The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
    $endgroup$
    – Mast
    11 hours ago






  • 1




    $begingroup$
    Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
    $endgroup$
    – JDG
    9 hours ago


















5












$begingroup$


# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in range(len(options)):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer


I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?










share|improve this question









New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    "The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
    $endgroup$
    – Mast
    11 hours ago






  • 1




    $begingroup$
    Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
    $endgroup$
    – JDG
    9 hours ago
















5












5








5





$begingroup$


# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in range(len(options)):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer


I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?










share|improve this question









New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in range(len(options)):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer


I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?







python python-3.x validation






share|improve this question









New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 13 mins ago







Holyprogrammer













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Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 11 hours ago









HolyprogrammerHolyprogrammer

1548




1548




New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    "The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
    $endgroup$
    – Mast
    11 hours ago






  • 1




    $begingroup$
    Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
    $endgroup$
    – JDG
    9 hours ago




















  • $begingroup$
    "The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
    $endgroup$
    – Mast
    11 hours ago






  • 1




    $begingroup$
    Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
    $endgroup$
    – JDG
    9 hours ago


















$begingroup$
"The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
$endgroup$
– Mast
11 hours ago




$begingroup$
"The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
$endgroup$
– Mast
11 hours ago




1




1




$begingroup$
Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
$endgroup$
– JDG
9 hours ago






$begingroup$
Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
$endgroup$
– JDG
9 hours ago












2 Answers
2






active

oldest

votes


















6












$begingroup$

The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.



PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.



The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.



def multi_choice_question(options: list):
while True:
print("nEnter the number of your choice - ")
for i, option in enumerate(options, 1):
print('{0}. {1}'.format(i, option))
print("n")
try:
answer = int(input())
if 1 <= answer <= len(options):
return answer
print("That option does not exist! Try again!")
except ValueError:
print("Doesn't seem like a number! Try again!")




share









$endgroup$









  • 2




    $begingroup$
    Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
    $endgroup$
    – JDG
    9 hours ago








  • 3




    $begingroup$
    @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
    $endgroup$
    – 200_success
    9 hours ago



















3












$begingroup$

I think that 200_success already covered most points. I would however like to add an alternative idea for the printing part:



print("Enter the number of your choice -",
*(f'{i}. {opt}' for i, opt in enumerate(options, 1)),
sep='n', end='nn')


Explanation:
from the docs we see that following signature for the print function:



 print(*objects, sep=' ', end='n', file=sys.stdout, flush=False)


we can therefore print everything with a single print call instead of three individual ones. I leave it up to you which one you perceive easier to use.






share|improve this answer









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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    6












    $begingroup$

    The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.



    PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.



    The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.



    def multi_choice_question(options: list):
    while True:
    print("nEnter the number of your choice - ")
    for i, option in enumerate(options, 1):
    print('{0}. {1}'.format(i, option))
    print("n")
    try:
    answer = int(input())
    if 1 <= answer <= len(options):
    return answer
    print("That option does not exist! Try again!")
    except ValueError:
    print("Doesn't seem like a number! Try again!")




    share









    $endgroup$









    • 2




      $begingroup$
      Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
      $endgroup$
      – JDG
      9 hours ago








    • 3




      $begingroup$
      @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
      $endgroup$
      – 200_success
      9 hours ago
















    6












    $begingroup$

    The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.



    PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.



    The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.



    def multi_choice_question(options: list):
    while True:
    print("nEnter the number of your choice - ")
    for i, option in enumerate(options, 1):
    print('{0}. {1}'.format(i, option))
    print("n")
    try:
    answer = int(input())
    if 1 <= answer <= len(options):
    return answer
    print("That option does not exist! Try again!")
    except ValueError:
    print("Doesn't seem like a number! Try again!")




    share









    $endgroup$









    • 2




      $begingroup$
      Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
      $endgroup$
      – JDG
      9 hours ago








    • 3




      $begingroup$
      @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
      $endgroup$
      – 200_success
      9 hours ago














    6












    6








    6





    $begingroup$

    The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.



    PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.



    The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.



    def multi_choice_question(options: list):
    while True:
    print("nEnter the number of your choice - ")
    for i, option in enumerate(options, 1):
    print('{0}. {1}'.format(i, option))
    print("n")
    try:
    answer = int(input())
    if 1 <= answer <= len(options):
    return answer
    print("That option does not exist! Try again!")
    except ValueError:
    print("Doesn't seem like a number! Try again!")




    share









    $endgroup$



    The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.



    PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.



    The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.



    def multi_choice_question(options: list):
    while True:
    print("nEnter the number of your choice - ")
    for i, option in enumerate(options, 1):
    print('{0}. {1}'.format(i, option))
    print("n")
    try:
    answer = int(input())
    if 1 <= answer <= len(options):
    return answer
    print("That option does not exist! Try again!")
    except ValueError:
    print("Doesn't seem like a number! Try again!")





    share











    share


    share










    answered 11 hours ago









    200_success200_success

    130k16153419




    130k16153419








    • 2




      $begingroup$
      Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
      $endgroup$
      – JDG
      9 hours ago








    • 3




      $begingroup$
      @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
      $endgroup$
      – 200_success
      9 hours ago














    • 2




      $begingroup$
      Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
      $endgroup$
      – JDG
      9 hours ago








    • 3




      $begingroup$
      @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
      $endgroup$
      – 200_success
      9 hours ago








    2




    2




    $begingroup$
    Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
    $endgroup$
    – JDG
    9 hours ago






    $begingroup$
    Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
    $endgroup$
    – JDG
    9 hours ago






    3




    3




    $begingroup$
    @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
    $endgroup$
    – 200_success
    9 hours ago




    $begingroup$
    @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
    $endgroup$
    – 200_success
    9 hours ago













    3












    $begingroup$

    I think that 200_success already covered most points. I would however like to add an alternative idea for the printing part:



    print("Enter the number of your choice -",
    *(f'{i}. {opt}' for i, opt in enumerate(options, 1)),
    sep='n', end='nn')


    Explanation:
    from the docs we see that following signature for the print function:



     print(*objects, sep=' ', end='n', file=sys.stdout, flush=False)


    we can therefore print everything with a single print call instead of three individual ones. I leave it up to you which one you perceive easier to use.






    share|improve this answer









    $endgroup$


















      3












      $begingroup$

      I think that 200_success already covered most points. I would however like to add an alternative idea for the printing part:



      print("Enter the number of your choice -",
      *(f'{i}. {opt}' for i, opt in enumerate(options, 1)),
      sep='n', end='nn')


      Explanation:
      from the docs we see that following signature for the print function:



       print(*objects, sep=' ', end='n', file=sys.stdout, flush=False)


      we can therefore print everything with a single print call instead of three individual ones. I leave it up to you which one you perceive easier to use.






      share|improve this answer









      $endgroup$
















        3












        3








        3





        $begingroup$

        I think that 200_success already covered most points. I would however like to add an alternative idea for the printing part:



        print("Enter the number of your choice -",
        *(f'{i}. {opt}' for i, opt in enumerate(options, 1)),
        sep='n', end='nn')


        Explanation:
        from the docs we see that following signature for the print function:



         print(*objects, sep=' ', end='n', file=sys.stdout, flush=False)


        we can therefore print everything with a single print call instead of three individual ones. I leave it up to you which one you perceive easier to use.






        share|improve this answer









        $endgroup$



        I think that 200_success already covered most points. I would however like to add an alternative idea for the printing part:



        print("Enter the number of your choice -",
        *(f'{i}. {opt}' for i, opt in enumerate(options, 1)),
        sep='n', end='nn')


        Explanation:
        from the docs we see that following signature for the print function:



         print(*objects, sep=' ', end='n', file=sys.stdout, flush=False)


        we can therefore print everything with a single print call instead of three individual ones. I leave it up to you which one you perceive easier to use.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 5 hours ago









        magu_magu_

        4931519




        4931519






















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