Coercion in JavaScript
I was wondering a few things about coercion.
When you do:
1 == true // true
Which one is coerced into which one ? is it the left one or the right one ?
When you do
undefined == null // true
How does it work exactly ?
In which order does it try to convert it ?
By instance:
1) String(undefined) == String(null) // false
2) Number(undefined) == Number(null) // false
3) Boolean(undefined) == Boolean(null) // true
Does it first try to coerce the left side operand ? then the right ? then both ?
javascript coercion
edited 11 mins ago
tomerpacific
769322
asked 1 hour ago
ScipionScipion
2,76343580
add a comment |
I was wondering a few things about coercion.
When you do:
1 == true // true
Which one is coerced into which one ? is it the left one or the right one ?
When you do
undefined == null // true
How does it work exactly ?
In which order does it try to convert it ?
By instance:
1) String(undefined) == String(null) // false
2) Number(undefined) == Number(null) // false
3) Boolean(undefined) == Boolean(null) // true
Does it first try to coerce the left side operand ? then the right ? then both ?
javascript coercion
edited 11 mins ago
tomerpacific
769322
asked 1 hour ago
ScipionScipion
2,76343580
2
developer.mozilla.org/en-US/docs/Web/JavaScript/…
– VLAZ
1 hour ago
Possible duplicate of Is true == 1 and false == 0 in JavaScript?
– adiga
1 hour ago
3
@adiga definitely not a duplicate. While both questions are about type coercion, this one asks which operand get coerced into the other. The other one is about the source of truth when evaluating the coerced types
– molamk
54 mins ago
1
@adiga Its not a dupe. Marked link is checking equality and this post is asking the process of equality. Its like Why 1 == true is true vs How 1 == true is true
– Rajesh
54 mins ago
1
@Rajesh It's a possible duplicate. They are related. It's useful future users (and OP) who come to this question and might want to read the linked question.
– adiga
50 mins ago
add a comment |
I was wondering a few things about coercion.
When you do:
1 == true // true
Which one is coerced into which one ? is it the left one or the right one ?
When you do
undefined == null // true
How does it work exactly ?
In which order does it try to convert it ?
By instance:
1) String(undefined) == String(null) // false
2) Number(undefined) == Number(null) // false
3) Boolean(undefined) == Boolean(null) // true
Does it first try to coerce the left side operand ? then the right ? then both ?
javascript coercion
edited 11 mins ago
tomerpacific
769322
asked 1 hour ago
ScipionScipion
2,76343580
I was wondering a few things about coercion.
When you do:
1 == true // true
Which one is coerced into which one ? is it the left one or the right one ?
When you do
undefined == null // true
How does it work exactly ?
In which order does it try to convert it ?
By instance:
1) String(undefined) == String(null) // false
2) Number(undefined) == Number(null) // false
3) Boolean(undefined) == Boolean(null) // true
Does it first try to coerce the left side operand ? then the right ? then both ?
javascript coercion
javascript coercion
edited 11 mins ago
tomerpacific
769322
asked 1 hour ago
ScipionScipion
2,76343580
edited 11 mins ago
tomerpacific
769322
asked 1 hour ago
ScipionScipion
2,76343580
edited 11 mins ago
tomerpacific
769322
edited 11 mins ago
tomerpacific
769322
edited 11 mins ago
tomerpacific
769322
769322
asked 1 hour ago
ScipionScipion
2,76343580
asked 1 hour ago
ScipionScipion
2,76343580
asked 1 hour ago
ScipionScipion
2,76343580
2,76343580
2
developer.mozilla.org/en-US/docs/Web/JavaScript/…
– VLAZ
1 hour ago
Possible duplicate of Is true == 1 and false == 0 in JavaScript?
– adiga
1 hour ago
3
@adiga definitely not a duplicate. While both questions are about type coercion, this one asks which operand get coerced into the other. The other one is about the source of truth when evaluating the coerced types
– molamk
54 mins ago
1
@adiga Its not a dupe. Marked link is checking equality and this post is asking the process of equality. Its like Why 1 == true is true vs How 1 == true is true
– Rajesh
54 mins ago
1
@Rajesh It's a possible duplicate. They are related. It's useful future users (and OP) who come to this question and might want to read the linked question.
– adiga
50 mins ago
add a comment |
2
developer.mozilla.org/en-US/docs/Web/JavaScript/…
– VLAZ
1 hour ago
Possible duplicate of Is true == 1 and false == 0 in JavaScript?
– adiga
1 hour ago
3
@adiga definitely not a duplicate. While both questions are about type coercion, this one asks which operand get coerced into the other. The other one is about the source of truth when evaluating the coerced types
– molamk
54 mins ago
1
@adiga Its not a dupe. Marked link is checking equality and this post is asking the process of equality. Its like Why 1 == true is true vs How 1 == true is true
– Rajesh
54 mins ago
1
@Rajesh It's a possible duplicate. They are related. It's useful future users (and OP) who come to this question and might want to read the linked question.
– adiga
50 mins ago
2
2
developer.mozilla.org/en-US/docs/Web/JavaScript/…
– VLAZ
1 hour ago
developer.mozilla.org/en-US/docs/Web/JavaScript/…
– VLAZ
1 hour ago
Possible duplicate of Is true == 1 and false == 0 in JavaScript?
– adiga
1 hour ago
Possible duplicate of Is true == 1 and false == 0 in JavaScript?
– adiga
1 hour ago
3
3
@adiga definitely not a duplicate. While both questions are about type coercion, this one asks which operand get coerced into the other. The other one is about the source of truth when evaluating the coerced types
– molamk
54 mins ago
@adiga definitely not a duplicate. While both questions are about type coercion, this one asks which operand get coerced into the other. The other one is about the source of truth when evaluating the coerced types
– molamk
54 mins ago
1
1
@adiga Its not a dupe. Marked link is checking equality and this post is asking the process of equality. Its like Why 1 == true is true vs How 1 == true is true
– Rajesh
54 mins ago
@adiga Its not a dupe. Marked link is checking equality and this post is asking the process of equality. Its like Why 1 == true is true vs How 1 == true is true
– Rajesh
54 mins ago
1
1
@Rajesh It's a possible duplicate. They are related. It's useful future users (and OP) who come to this question and might want to read the linked question.
– adiga
50 mins ago
@Rajesh It's a possible duplicate. They are related. It's useful future users (and OP) who come to this question and might want to read the linked question.
– adiga
50 mins ago
add a comment |
1 Answer
1
active
oldest
votes
The process is described at 7.2.12 Abstract Equality Comparison:
The comparison x == y, where x and y are values, produces true or false. Such a comparison is performed as follows:
If Type(x) is the same as Type(y), then return the result of performing Strict Equality Comparison x === y.
If x is null and y is undefined, return true.
If x is undefined and y is null, return true.
If Type(x) is Number and Type(y) is String, return the result of the comparison x == ToNumber(y).
If Type(x) is String and Type(y) is Number, return the result of the comparison ToNumber(x) == y.
If Type(x) is Boolean, return the result of the comparison ToNumber(x) == y.
If Type(y) is Boolean, return the result of the comparison x == ToNumber(y).
If Type(x) is either String, Number, or Symbol and Type(y) is Object, then return the result of the comparison x == ToPrimitive(y).
If Type(x) is Object and Type(y) is either String, Number, or Symbol, then return the result of the comparison ToPrimitive(x) == y.
Return false.
So rather than coercing one side and then the other, or something like that, it's more that the interpreter goes through that list above until it finds a matching condition, and executes the resulting command, which may involve coercing only the left side, or only the right side (and, rarely, both, in case a recursive command is reached, such as with true == '1', which will fulfill condition 8, turn into 1 == '1', fulfilling condition 6 and turning into 1 == 1, fulfilling condition 3 and resolving to true)
answered 1 hour ago
CertainPerformanceCertainPerformance
85k154169
1
@SalmanA I may read it incorrectly but in 8 couldn't it be both? This algo calls itself right?
– Kaiido
53 mins ago
@Kaiido in 8, y is not coerced. Likewise in 9 (where x is not coerced).
– Salman A
48 mins ago
@SalmanA not yet, but in the next occurence ofthe comparison ToNumber(x) == y.it may be no?.
– Kaiido
47 mins ago
1
@SalmanA 8 calls the==process recursively, so I'm pretty sure it's possible? Considertrue == '1'
– CertainPerformance
47 mins ago
@CertainPerformance yes, your edit makes it clear.
– Salman A
44 mins ago
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The process is described at 7.2.12 Abstract Equality Comparison:
The comparison x == y, where x and y are values, produces true or false. Such a comparison is performed as follows:
If Type(x) is the same as Type(y), then return the result of performing Strict Equality Comparison x === y.
If x is null and y is undefined, return true.
If x is undefined and y is null, return true.
If Type(x) is Number and Type(y) is String, return the result of the comparison x == ToNumber(y).
If Type(x) is String and Type(y) is Number, return the result of the comparison ToNumber(x) == y.
If Type(x) is Boolean, return the result of the comparison ToNumber(x) == y.
If Type(y) is Boolean, return the result of the comparison x == ToNumber(y).
If Type(x) is either String, Number, or Symbol and Type(y) is Object, then return the result of the comparison x == ToPrimitive(y).
If Type(x) is Object and Type(y) is either String, Number, or Symbol, then return the result of the comparison ToPrimitive(x) == y.
Return false.
So rather than coercing one side and then the other, or something like that, it's more that the interpreter goes through that list above until it finds a matching condition, and executes the resulting command, which may involve coercing only the left side, or only the right side (and, rarely, both, in case a recursive command is reached, such as with true == '1', which will fulfill condition 8, turn into 1 == '1', fulfilling condition 6 and turning into 1 == 1, fulfilling condition 3 and resolving to true)
answered 1 hour ago
CertainPerformanceCertainPerformance
85k154169
1
@SalmanA I may read it incorrectly but in 8 couldn't it be both? This algo calls itself right?
– Kaiido
53 mins ago
@Kaiido in 8, y is not coerced. Likewise in 9 (where x is not coerced).
– Salman A
48 mins ago
@SalmanA not yet, but in the next occurence ofthe comparison ToNumber(x) == y.it may be no?.
– Kaiido
47 mins ago
1
@SalmanA 8 calls the==process recursively, so I'm pretty sure it's possible? Considertrue == '1'
– CertainPerformance
47 mins ago
@CertainPerformance yes, your edit makes it clear.
– Salman A
44 mins ago
add a comment |
The process is described at 7.2.12 Abstract Equality Comparison:
The comparison x == y, where x and y are values, produces true or false. Such a comparison is performed as follows:
If Type(x) is the same as Type(y), then return the result of performing Strict Equality Comparison x === y.
If x is null and y is undefined, return true.
If x is undefined and y is null, return true.
If Type(x) is Number and Type(y) is String, return the result of the comparison x == ToNumber(y).
If Type(x) is String and Type(y) is Number, return the result of the comparison ToNumber(x) == y.
If Type(x) is Boolean, return the result of the comparison ToNumber(x) == y.
If Type(y) is Boolean, return the result of the comparison x == ToNumber(y).
If Type(x) is either String, Number, or Symbol and Type(y) is Object, then return the result of the comparison x == ToPrimitive(y).
If Type(x) is Object and Type(y) is either String, Number, or Symbol, then return the result of the comparison ToPrimitive(x) == y.
Return false.
So rather than coercing one side and then the other, or something like that, it's more that the interpreter goes through that list above until it finds a matching condition, and executes the resulting command, which may involve coercing only the left side, or only the right side (and, rarely, both, in case a recursive command is reached, such as with true == '1', which will fulfill condition 8, turn into 1 == '1', fulfilling condition 6 and turning into 1 == 1, fulfilling condition 3 and resolving to true)
answered 1 hour ago
CertainPerformanceCertainPerformance
85k154169
1
@SalmanA I may read it incorrectly but in 8 couldn't it be both? This algo calls itself right?
– Kaiido
53 mins ago
@Kaiido in 8, y is not coerced. Likewise in 9 (where x is not coerced).
– Salman A
48 mins ago
@SalmanA not yet, but in the next occurence ofthe comparison ToNumber(x) == y.it may be no?.
– Kaiido
47 mins ago
1
@SalmanA 8 calls the==process recursively, so I'm pretty sure it's possible? Considertrue == '1'
– CertainPerformance
47 mins ago
@CertainPerformance yes, your edit makes it clear.
– Salman A
44 mins ago
add a comment |
The process is described at 7.2.12 Abstract Equality Comparison:
The comparison x == y, where x and y are values, produces true or false. Such a comparison is performed as follows:
If Type(x) is the same as Type(y), then return the result of performing Strict Equality Comparison x === y.
If x is null and y is undefined, return true.
If x is undefined and y is null, return true.
If Type(x) is Number and Type(y) is String, return the result of the comparison x == ToNumber(y).
If Type(x) is String and Type(y) is Number, return the result of the comparison ToNumber(x) == y.
If Type(x) is Boolean, return the result of the comparison ToNumber(x) == y.
If Type(y) is Boolean, return the result of the comparison x == ToNumber(y).
If Type(x) is either String, Number, or Symbol and Type(y) is Object, then return the result of the comparison x == ToPrimitive(y).
If Type(x) is Object and Type(y) is either String, Number, or Symbol, then return the result of the comparison ToPrimitive(x) == y.
Return false.
So rather than coercing one side and then the other, or something like that, it's more that the interpreter goes through that list above until it finds a matching condition, and executes the resulting command, which may involve coercing only the left side, or only the right side (and, rarely, both, in case a recursive command is reached, such as with true == '1', which will fulfill condition 8, turn into 1 == '1', fulfilling condition 6 and turning into 1 == 1, fulfilling condition 3 and resolving to true)
answered 1 hour ago
CertainPerformanceCertainPerformance
85k154169
The process is described at 7.2.12 Abstract Equality Comparison:
The comparison x == y, where x and y are values, produces true or false. Such a comparison is performed as follows:
If Type(x) is the same as Type(y), then return the result of performing Strict Equality Comparison x === y.
If x is null and y is undefined, return true.
If x is undefined and y is null, return true.
If Type(x) is Number and Type(y) is String, return the result of the comparison x == ToNumber(y).
If Type(x) is String and Type(y) is Number, return the result of the comparison ToNumber(x) == y.
If Type(x) is Boolean, return the result of the comparison ToNumber(x) == y.
If Type(y) is Boolean, return the result of the comparison x == ToNumber(y).
If Type(x) is either String, Number, or Symbol and Type(y) is Object, then return the result of the comparison x == ToPrimitive(y).
If Type(x) is Object and Type(y) is either String, Number, or Symbol, then return the result of the comparison ToPrimitive(x) == y.
Return false.
So rather than coercing one side and then the other, or something like that, it's more that the interpreter goes through that list above until it finds a matching condition, and executes the resulting command, which may involve coercing only the left side, or only the right side (and, rarely, both, in case a recursive command is reached, such as with true == '1', which will fulfill condition 8, turn into 1 == '1', fulfilling condition 6 and turning into 1 == 1, fulfilling condition 3 and resolving to true)
answered 1 hour ago
CertainPerformanceCertainPerformance
85k154169
edited 48 mins ago
answered 1 hour ago
CertainPerformanceCertainPerformance
85k154169
answered 1 hour ago
CertainPerformanceCertainPerformance
85k154169
answered 1 hour ago
CertainPerformanceCertainPerformance
85k154169
85k154169
1
@SalmanA I may read it incorrectly but in 8 couldn't it be both? This algo calls itself right?
– Kaiido
53 mins ago
@Kaiido in 8, y is not coerced. Likewise in 9 (where x is not coerced).
– Salman A
48 mins ago
@SalmanA not yet, but in the next occurence ofthe comparison ToNumber(x) == y.it may be no?.
– Kaiido
47 mins ago
1
@SalmanA 8 calls the==process recursively, so I'm pretty sure it's possible? Considertrue == '1'
– CertainPerformance
47 mins ago
@CertainPerformance yes, your edit makes it clear.
– Salman A
44 mins ago
add a comment |
1
@SalmanA I may read it incorrectly but in 8 couldn't it be both? This algo calls itself right?
– Kaiido
53 mins ago
@Kaiido in 8, y is not coerced. Likewise in 9 (where x is not coerced).
– Salman A
48 mins ago
@SalmanA not yet, but in the next occurence ofthe comparison ToNumber(x) == y.it may be no?.
– Kaiido
47 mins ago
1
@SalmanA 8 calls the==process recursively, so I'm pretty sure it's possible? Considertrue == '1'
– CertainPerformance
47 mins ago
@CertainPerformance yes, your edit makes it clear.
– Salman A
44 mins ago
1
1
@SalmanA I may read it incorrectly but in 8 couldn't it be both? This algo calls itself right?
– Kaiido
53 mins ago
@SalmanA I may read it incorrectly but in 8 couldn't it be both? This algo calls itself right?
– Kaiido
53 mins ago
@Kaiido in 8, y is not coerced. Likewise in 9 (where x is not coerced).
– Salman A
48 mins ago
@Kaiido in 8, y is not coerced. Likewise in 9 (where x is not coerced).
– Salman A
48 mins ago
@SalmanA not yet, but in the next occurence of
the comparison ToNumber(x) == y. it may be no?.– Kaiido
47 mins ago
@SalmanA not yet, but in the next occurence of
the comparison ToNumber(x) == y. it may be no?.– Kaiido
47 mins ago
1
1
@SalmanA 8 calls the
== process recursively, so I'm pretty sure it's possible? Consider true == '1'– CertainPerformance
47 mins ago
@SalmanA 8 calls the
== process recursively, so I'm pretty sure it's possible? Consider true == '1'– CertainPerformance
47 mins ago
@CertainPerformance yes, your edit makes it clear.
– Salman A
44 mins ago
@CertainPerformance yes, your edit makes it clear.
– Salman A
44 mins ago
add a comment |
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2
developer.mozilla.org/en-US/docs/Web/JavaScript/…
– VLAZ
1 hour ago
Possible duplicate of Is true == 1 and false == 0 in JavaScript?
– adiga
1 hour ago
3
@adiga definitely not a duplicate. While both questions are about type coercion, this one asks which operand get coerced into the other. The other one is about the source of truth when evaluating the coerced types
– molamk
54 mins ago
1
@adiga Its not a dupe. Marked link is checking equality and this post is asking the process of equality. Its like Why 1 == true is true vs How 1 == true is true
– Rajesh
54 mins ago
1
@Rajesh It's a possible duplicate. They are related. It's useful future users (and OP) who come to this question and might want to read the linked question.
– adiga
50 mins ago