How to combine GROUP BY and ROW_NUMBER ( ) OVER












0















I Have



CusID Name Country PhoneNo



1 JOHN USA 555555
1 JOHN USA 555554
2 MIKE CANADA 111111
2 MIKE CANADA 122222
5 JOHN UK 888888
5 JOHN UK 888889



I want to display output like this:



CusID Name Country PhoneNo



1 JOHN USA 555555
555554
2 MIKE CANADA 111111
122222
5 JOHN UK 888888
888889









share







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    0















    I Have



    CusID Name Country PhoneNo



    1 JOHN USA 555555
    1 JOHN USA 555554
    2 MIKE CANADA 111111
    2 MIKE CANADA 122222
    5 JOHN UK 888888
    5 JOHN UK 888889



    I want to display output like this:



    CusID Name Country PhoneNo



    1 JOHN USA 555555
    555554
    2 MIKE CANADA 111111
    122222
    5 JOHN UK 888888
    888889









    share







    New contributor




    user172047 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      0












      0








      0








      I Have



      CusID Name Country PhoneNo



      1 JOHN USA 555555
      1 JOHN USA 555554
      2 MIKE CANADA 111111
      2 MIKE CANADA 122222
      5 JOHN UK 888888
      5 JOHN UK 888889



      I want to display output like this:



      CusID Name Country PhoneNo



      1 JOHN USA 555555
      555554
      2 MIKE CANADA 111111
      122222
      5 JOHN UK 888888
      888889









      share







      New contributor




      user172047 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I Have



      CusID Name Country PhoneNo



      1 JOHN USA 555555
      1 JOHN USA 555554
      2 MIKE CANADA 111111
      2 MIKE CANADA 122222
      5 JOHN UK 888888
      5 JOHN UK 888889



      I want to display output like this:



      CusID Name Country PhoneNo



      1 JOHN USA 555555
      555554
      2 MIKE CANADA 111111
      122222
      5 JOHN UK 888888
      888889







      sql-server





      share







      New contributor




      user172047 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      user172047 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






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      asked 7 mins ago









      user172047user172047

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