Mysql group by multiple combinations
I'm building a chat app in which two people will comunicate on enquiry, I want to fetch conversation between two users on enquiry, table structure is like below:
Table: enquiries
id, name, product, msg
Table: replies
id, enquiry_id(fk), from_user(fk), to_user(fk), msg
+----+--------+-----------+---------+------+
| id | enq_id | from_user | to_user | msg |
+----+--------+-----------+---------+------+
| 1 | 1 | 1 | 2 | msg1 |
+----+--------+-----------+---------+------+
| 2 | 1 | 2 | 1 | msg2 |
+----+--------+-----------+---------+------+
| 3 | 1 | 1 | 2 | msg3 |
+----+--------+-----------+---------+------+
| 4 | 1 | 2 | 1 | msg4 |
+----+--------+-----------+---------+------+
| 5 | 1 | 1 | 3 | msg1 |
+----+--------+-----------+---------+------+
| 6 | 1 | 3 | 1 | msg2 |
+----+--------+-----------+---------+------+
What I'm doing
I'm using using below query to fetch communication between two users on the basis of enquiries but it is giving two seperate records for same users & enquiry.
SELECT
r.enquiry_id,
r.from_user,
r.to_user,
count(1) replies_count
FROM
`replies` r
GROUP BY
r.enquiry_id, r.from_user, r.to_user
ORDER BY
r.id DESC
This is the result of the above query
+--------+-----------+---------+-----+
| enq_id | from_user | to_user | msg |
+--------+-----------+---------+-----+
| 1 | 1 | 2 | 2 |
+--------+-----------+---------+-----+
| 1 | 2 | 1 | 2 |
+--------+-----------+---------+-----+
| 1 | 1 | 3 | 1 |
+--------+-----------+---------+-----+
| 1 | 3 | 1 | 1 |
+--------+-----------+---------+-----+
And my expected result is like
+--------+--------------+--------------+-----+
| enq_id | participant1 | participant2 | msg |
+--------+--------------+--------------+-----+
| 1 | 1 | 2 | 4 |
+--------+--------------+--------------+-----+
| 1 | 1 | 3 | 2 |
+--------+--------------+--------------+-----+
mysql group-by
bumped to the homepage by Community♦ 14 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
I'm building a chat app in which two people will comunicate on enquiry, I want to fetch conversation between two users on enquiry, table structure is like below:
Table: enquiries
id, name, product, msg
Table: replies
id, enquiry_id(fk), from_user(fk), to_user(fk), msg
+----+--------+-----------+---------+------+
| id | enq_id | from_user | to_user | msg |
+----+--------+-----------+---------+------+
| 1 | 1 | 1 | 2 | msg1 |
+----+--------+-----------+---------+------+
| 2 | 1 | 2 | 1 | msg2 |
+----+--------+-----------+---------+------+
| 3 | 1 | 1 | 2 | msg3 |
+----+--------+-----------+---------+------+
| 4 | 1 | 2 | 1 | msg4 |
+----+--------+-----------+---------+------+
| 5 | 1 | 1 | 3 | msg1 |
+----+--------+-----------+---------+------+
| 6 | 1 | 3 | 1 | msg2 |
+----+--------+-----------+---------+------+
What I'm doing
I'm using using below query to fetch communication between two users on the basis of enquiries but it is giving two seperate records for same users & enquiry.
SELECT
r.enquiry_id,
r.from_user,
r.to_user,
count(1) replies_count
FROM
`replies` r
GROUP BY
r.enquiry_id, r.from_user, r.to_user
ORDER BY
r.id DESC
This is the result of the above query
+--------+-----------+---------+-----+
| enq_id | from_user | to_user | msg |
+--------+-----------+---------+-----+
| 1 | 1 | 2 | 2 |
+--------+-----------+---------+-----+
| 1 | 2 | 1 | 2 |
+--------+-----------+---------+-----+
| 1 | 1 | 3 | 1 |
+--------+-----------+---------+-----+
| 1 | 3 | 1 | 1 |
+--------+-----------+---------+-----+
And my expected result is like
+--------+--------------+--------------+-----+
| enq_id | participant1 | participant2 | msg |
+--------+--------------+--------------+-----+
| 1 | 1 | 2 | 4 |
+--------+--------------+--------------+-----+
| 1 | 1 | 3 | 2 |
+--------+--------------+--------------+-----+
mysql group-by
bumped to the homepage by Community♦ 14 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
1
can be more than two distinct users in the conversation?
– McNets
Nov 29 '16 at 13:50
There will be single row for two users communicating on same enquiry, I've modified my question please check
– Ramesh Mhetre
Nov 30 '16 at 5:01
add a comment |
I'm building a chat app in which two people will comunicate on enquiry, I want to fetch conversation between two users on enquiry, table structure is like below:
Table: enquiries
id, name, product, msg
Table: replies
id, enquiry_id(fk), from_user(fk), to_user(fk), msg
+----+--------+-----------+---------+------+
| id | enq_id | from_user | to_user | msg |
+----+--------+-----------+---------+------+
| 1 | 1 | 1 | 2 | msg1 |
+----+--------+-----------+---------+------+
| 2 | 1 | 2 | 1 | msg2 |
+----+--------+-----------+---------+------+
| 3 | 1 | 1 | 2 | msg3 |
+----+--------+-----------+---------+------+
| 4 | 1 | 2 | 1 | msg4 |
+----+--------+-----------+---------+------+
| 5 | 1 | 1 | 3 | msg1 |
+----+--------+-----------+---------+------+
| 6 | 1 | 3 | 1 | msg2 |
+----+--------+-----------+---------+------+
What I'm doing
I'm using using below query to fetch communication between two users on the basis of enquiries but it is giving two seperate records for same users & enquiry.
SELECT
r.enquiry_id,
r.from_user,
r.to_user,
count(1) replies_count
FROM
`replies` r
GROUP BY
r.enquiry_id, r.from_user, r.to_user
ORDER BY
r.id DESC
This is the result of the above query
+--------+-----------+---------+-----+
| enq_id | from_user | to_user | msg |
+--------+-----------+---------+-----+
| 1 | 1 | 2 | 2 |
+--------+-----------+---------+-----+
| 1 | 2 | 1 | 2 |
+--------+-----------+---------+-----+
| 1 | 1 | 3 | 1 |
+--------+-----------+---------+-----+
| 1 | 3 | 1 | 1 |
+--------+-----------+---------+-----+
And my expected result is like
+--------+--------------+--------------+-----+
| enq_id | participant1 | participant2 | msg |
+--------+--------------+--------------+-----+
| 1 | 1 | 2 | 4 |
+--------+--------------+--------------+-----+
| 1 | 1 | 3 | 2 |
+--------+--------------+--------------+-----+
mysql group-by
I'm building a chat app in which two people will comunicate on enquiry, I want to fetch conversation between two users on enquiry, table structure is like below:
Table: enquiries
id, name, product, msg
Table: replies
id, enquiry_id(fk), from_user(fk), to_user(fk), msg
+----+--------+-----------+---------+------+
| id | enq_id | from_user | to_user | msg |
+----+--------+-----------+---------+------+
| 1 | 1 | 1 | 2 | msg1 |
+----+--------+-----------+---------+------+
| 2 | 1 | 2 | 1 | msg2 |
+----+--------+-----------+---------+------+
| 3 | 1 | 1 | 2 | msg3 |
+----+--------+-----------+---------+------+
| 4 | 1 | 2 | 1 | msg4 |
+----+--------+-----------+---------+------+
| 5 | 1 | 1 | 3 | msg1 |
+----+--------+-----------+---------+------+
| 6 | 1 | 3 | 1 | msg2 |
+----+--------+-----------+---------+------+
What I'm doing
I'm using using below query to fetch communication between two users on the basis of enquiries but it is giving two seperate records for same users & enquiry.
SELECT
r.enquiry_id,
r.from_user,
r.to_user,
count(1) replies_count
FROM
`replies` r
GROUP BY
r.enquiry_id, r.from_user, r.to_user
ORDER BY
r.id DESC
This is the result of the above query
+--------+-----------+---------+-----+
| enq_id | from_user | to_user | msg |
+--------+-----------+---------+-----+
| 1 | 1 | 2 | 2 |
+--------+-----------+---------+-----+
| 1 | 2 | 1 | 2 |
+--------+-----------+---------+-----+
| 1 | 1 | 3 | 1 |
+--------+-----------+---------+-----+
| 1 | 3 | 1 | 1 |
+--------+-----------+---------+-----+
And my expected result is like
+--------+--------------+--------------+-----+
| enq_id | participant1 | participant2 | msg |
+--------+--------------+--------------+-----+
| 1 | 1 | 2 | 4 |
+--------+--------------+--------------+-----+
| 1 | 1 | 3 | 2 |
+--------+--------------+--------------+-----+
mysql group-by
mysql group-by
edited Nov 30 '16 at 4:56
Ramesh Mhetre
asked Nov 29 '16 at 13:06
Ramesh MhetreRamesh Mhetre
1012
1012
bumped to the homepage by Community♦ 14 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 14 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
1
can be more than two distinct users in the conversation?
– McNets
Nov 29 '16 at 13:50
There will be single row for two users communicating on same enquiry, I've modified my question please check
– Ramesh Mhetre
Nov 30 '16 at 5:01
add a comment |
1
can be more than two distinct users in the conversation?
– McNets
Nov 29 '16 at 13:50
There will be single row for two users communicating on same enquiry, I've modified my question please check
– Ramesh Mhetre
Nov 30 '16 at 5:01
1
1
can be more than two distinct users in the conversation?
– McNets
Nov 29 '16 at 13:50
can be more than two distinct users in the conversation?
– McNets
Nov 29 '16 at 13:50
There will be single row for two users communicating on same enquiry, I've modified my question please check
– Ramesh Mhetre
Nov 30 '16 at 5:01
There will be single row for two users communicating on same enquiry, I've modified my question please check
– Ramesh Mhetre
Nov 30 '16 at 5:01
add a comment |
1 Answer
1
active
oldest
votes
check it here if it is what you're asking for: http://rextester.com/TVOKS20933
select enquiry_id, from_user, to_user, count(1) msg
from replies
group by enquiry_id, from_user, to_user
order by id;
+----+--------+-----------+---------+------+
| id | enq_id | from_user | to_user | msg |
+----+--------+-----------+---------+------+
| 1 | 1 | 1 | 2 | msg1 |
+----+--------+-----------+---------+------+
| 2 | 1 | 2 | 1 | msg2 |
+----+--------+-----------+---------+------+
| 3 | 1 | 1 | 2 | msg3 |
+----+--------+-----------+---------+------+
| 4 | 1 | 2 | 1 | msg4 |
+----+--------+-----------+---------+------+
| 5 | 1 | 1 | 3 | msg1 |
+----+--------+-----------+---------+------+
| 6 | 1 | 3 | 1 | msg2 |
+----+--------+-----------+---------+------+
+--------+-----------+---------+-----+
| enq_id | from_user | to_user | msg |
+--------+-----------+---------+-----+
| 1 | 1 | 2 | 2 |
+--------+-----------+---------+-----+
| 1 | 2 | 1 | 2 |
+--------+-----------+---------+-----+
| 1 | 1 | 3 | 1 |
+--------+-----------+---------+-----+
| 1 | 3 | 1 | 1 |
+--------+-----------+---------+-----+
This what is I'm doing right now, I want only one row for communication between two users. I have modified my question, please check
– Ramesh Mhetre
Nov 30 '16 at 5:00
add a comment |
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "182"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f156655%2fmysql-group-by-multiple-combinations%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
check it here if it is what you're asking for: http://rextester.com/TVOKS20933
select enquiry_id, from_user, to_user, count(1) msg
from replies
group by enquiry_id, from_user, to_user
order by id;
+----+--------+-----------+---------+------+
| id | enq_id | from_user | to_user | msg |
+----+--------+-----------+---------+------+
| 1 | 1 | 1 | 2 | msg1 |
+----+--------+-----------+---------+------+
| 2 | 1 | 2 | 1 | msg2 |
+----+--------+-----------+---------+------+
| 3 | 1 | 1 | 2 | msg3 |
+----+--------+-----------+---------+------+
| 4 | 1 | 2 | 1 | msg4 |
+----+--------+-----------+---------+------+
| 5 | 1 | 1 | 3 | msg1 |
+----+--------+-----------+---------+------+
| 6 | 1 | 3 | 1 | msg2 |
+----+--------+-----------+---------+------+
+--------+-----------+---------+-----+
| enq_id | from_user | to_user | msg |
+--------+-----------+---------+-----+
| 1 | 1 | 2 | 2 |
+--------+-----------+---------+-----+
| 1 | 2 | 1 | 2 |
+--------+-----------+---------+-----+
| 1 | 1 | 3 | 1 |
+--------+-----------+---------+-----+
| 1 | 3 | 1 | 1 |
+--------+-----------+---------+-----+
This what is I'm doing right now, I want only one row for communication between two users. I have modified my question, please check
– Ramesh Mhetre
Nov 30 '16 at 5:00
add a comment |
check it here if it is what you're asking for: http://rextester.com/TVOKS20933
select enquiry_id, from_user, to_user, count(1) msg
from replies
group by enquiry_id, from_user, to_user
order by id;
+----+--------+-----------+---------+------+
| id | enq_id | from_user | to_user | msg |
+----+--------+-----------+---------+------+
| 1 | 1 | 1 | 2 | msg1 |
+----+--------+-----------+---------+------+
| 2 | 1 | 2 | 1 | msg2 |
+----+--------+-----------+---------+------+
| 3 | 1 | 1 | 2 | msg3 |
+----+--------+-----------+---------+------+
| 4 | 1 | 2 | 1 | msg4 |
+----+--------+-----------+---------+------+
| 5 | 1 | 1 | 3 | msg1 |
+----+--------+-----------+---------+------+
| 6 | 1 | 3 | 1 | msg2 |
+----+--------+-----------+---------+------+
+--------+-----------+---------+-----+
| enq_id | from_user | to_user | msg |
+--------+-----------+---------+-----+
| 1 | 1 | 2 | 2 |
+--------+-----------+---------+-----+
| 1 | 2 | 1 | 2 |
+--------+-----------+---------+-----+
| 1 | 1 | 3 | 1 |
+--------+-----------+---------+-----+
| 1 | 3 | 1 | 1 |
+--------+-----------+---------+-----+
This what is I'm doing right now, I want only one row for communication between two users. I have modified my question, please check
– Ramesh Mhetre
Nov 30 '16 at 5:00
add a comment |
check it here if it is what you're asking for: http://rextester.com/TVOKS20933
select enquiry_id, from_user, to_user, count(1) msg
from replies
group by enquiry_id, from_user, to_user
order by id;
+----+--------+-----------+---------+------+
| id | enq_id | from_user | to_user | msg |
+----+--------+-----------+---------+------+
| 1 | 1 | 1 | 2 | msg1 |
+----+--------+-----------+---------+------+
| 2 | 1 | 2 | 1 | msg2 |
+----+--------+-----------+---------+------+
| 3 | 1 | 1 | 2 | msg3 |
+----+--------+-----------+---------+------+
| 4 | 1 | 2 | 1 | msg4 |
+----+--------+-----------+---------+------+
| 5 | 1 | 1 | 3 | msg1 |
+----+--------+-----------+---------+------+
| 6 | 1 | 3 | 1 | msg2 |
+----+--------+-----------+---------+------+
+--------+-----------+---------+-----+
| enq_id | from_user | to_user | msg |
+--------+-----------+---------+-----+
| 1 | 1 | 2 | 2 |
+--------+-----------+---------+-----+
| 1 | 2 | 1 | 2 |
+--------+-----------+---------+-----+
| 1 | 1 | 3 | 1 |
+--------+-----------+---------+-----+
| 1 | 3 | 1 | 1 |
+--------+-----------+---------+-----+
check it here if it is what you're asking for: http://rextester.com/TVOKS20933
select enquiry_id, from_user, to_user, count(1) msg
from replies
group by enquiry_id, from_user, to_user
order by id;
+----+--------+-----------+---------+------+
| id | enq_id | from_user | to_user | msg |
+----+--------+-----------+---------+------+
| 1 | 1 | 1 | 2 | msg1 |
+----+--------+-----------+---------+------+
| 2 | 1 | 2 | 1 | msg2 |
+----+--------+-----------+---------+------+
| 3 | 1 | 1 | 2 | msg3 |
+----+--------+-----------+---------+------+
| 4 | 1 | 2 | 1 | msg4 |
+----+--------+-----------+---------+------+
| 5 | 1 | 1 | 3 | msg1 |
+----+--------+-----------+---------+------+
| 6 | 1 | 3 | 1 | msg2 |
+----+--------+-----------+---------+------+
+--------+-----------+---------+-----+
| enq_id | from_user | to_user | msg |
+--------+-----------+---------+-----+
| 1 | 1 | 2 | 2 |
+--------+-----------+---------+-----+
| 1 | 2 | 1 | 2 |
+--------+-----------+---------+-----+
| 1 | 1 | 3 | 1 |
+--------+-----------+---------+-----+
| 1 | 3 | 1 | 1 |
+--------+-----------+---------+-----+
edited Nov 29 '16 at 14:22
answered Nov 29 '16 at 14:14
McNetsMcNets
16.3k42161
16.3k42161
This what is I'm doing right now, I want only one row for communication between two users. I have modified my question, please check
– Ramesh Mhetre
Nov 30 '16 at 5:00
add a comment |
This what is I'm doing right now, I want only one row for communication between two users. I have modified my question, please check
– Ramesh Mhetre
Nov 30 '16 at 5:00
This what is I'm doing right now, I want only one row for communication between two users. I have modified my question, please check
– Ramesh Mhetre
Nov 30 '16 at 5:00
This what is I'm doing right now, I want only one row for communication between two users. I have modified my question, please check
– Ramesh Mhetre
Nov 30 '16 at 5:00
add a comment |
Thanks for contributing an answer to Database Administrators Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f156655%2fmysql-group-by-multiple-combinations%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown

1
can be more than two distinct users in the conversation?
– McNets
Nov 29 '16 at 13:50
There will be single row for two users communicating on same enquiry, I've modified my question please check
– Ramesh Mhetre
Nov 30 '16 at 5:01