Count number of li element and addclass
6
I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
javascript html css
asked 1 hour ago
kk kkkk kk
926
add a comment |
6
I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
javascript html css
asked 1 hour ago
kk kkkk kk
926
1
Your$(this)is not pointing to.box2as you expect
– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to.box2, hence not working as expected as there is no.box1after it.
– LGSon
49 mins ago
@Mr.Alien Aconsole.log($(this)shows that$(this)is pointing to.box2. If you reverse the HTML structure ofbox1andbox2and change theJavaScripttoreturn 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start offind.
– Andy Hoffman
44 mins ago
It would be great to add$(document).ready(function(){, around your JQuery operations,
– harish sharma
10 mins ago
add a comment |
6
6
6
I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
javascript html css
asked 1 hour ago
kk kkkk kk
926
I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>javascript html css
javascript html css
asked 1 hour ago
kk kkkk kk
926
asked 1 hour ago
kk kkkk kk
926
asked 1 hour ago
kk kkkk kk
926
asked 1 hour ago
kk kkkk kk
926
asked 1 hour ago
kk kkkk kk
926
926
1
Your$(this)is not pointing to.box2as you expect
– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to.box2, hence not working as expected as there is no.box1after it.
– LGSon
49 mins ago
@Mr.Alien Aconsole.log($(this)shows that$(this)is pointing to.box2. If you reverse the HTML structure ofbox1andbox2and change theJavaScripttoreturn 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start offind.
– Andy Hoffman
44 mins ago
It would be great to add$(document).ready(function(){, around your JQuery operations,
– harish sharma
10 mins ago
add a comment |
1
Your$(this)is not pointing to.box2as you expect
– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to.box2, hence not working as expected as there is no.box1after it.
– LGSon
49 mins ago
@Mr.Alien Aconsole.log($(this)shows that$(this)is pointing to.box2. If you reverse the HTML structure ofbox1andbox2and change theJavaScripttoreturn 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start offind.
– Andy Hoffman
44 mins ago
It would be great to add$(document).ready(function(){, around your JQuery operations,
– harish sharma
10 mins ago
1
1
Your
$(this) is not pointing to .box2 as you expect– Mr. Alien
1 hour ago
Your
$(this) is not pointing to .box2 as you expect– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to
.box2, hence not working as expected as there is no .box1 after it.– LGSon
49 mins ago
@Mr.Alien It is what it actually does, pointing to
.box2, hence not working as expected as there is no .box1 after it.– LGSon
49 mins ago
@Mr.Alien A
console.log($(this) shows that $(this) is pointing to .box2. If you reverse the HTML structure of box1 and box2 and change the JavaScript to return 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start of find.– Andy Hoffman
44 mins ago
@Mr.Alien A
console.log($(this) shows that $(this) is pointing to .box2. If you reverse the HTML structure of box1 and box2 and change the JavaScript to return 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start of find.– Andy Hoffman
44 mins ago
It would be great to add
$(document).ready(function(){, around your JQuery operations,– harish sharma
10 mins ago
It would be great to add
$(document).ready(function(){, around your JQuery operations,– harish sharma
10 mins ago
add a comment |
5 Answers
5
active
oldest
votes
5
Pretty close. box1 comes before box2, so your query beginning at box2, or $(this), would return 0 results as find looks ahead in the DOM.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
Andy HoffmanAndy Hoffman
8,07631538
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
5
Here $(this) is referring to box2 element.Only $('.box1 li').length is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});.list_3 {
color: green;
}<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
brkbrk
28.4k32143
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
4
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass() is invoked and this element does not have .box1 li. Thus find() is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
MamunMamun
29k71831
add a comment |
4
$(this).find will find the li in the div with box2 class which are not present. Instead check this in the div with box1 class and find the li elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
ellipsisellipsis
7,6962929
add a comment |
2
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
Sarabjit SinghSarabjit Singh
1169
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
5
Pretty close. box1 comes before box2, so your query beginning at box2, or $(this), would return 0 results as find looks ahead in the DOM.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
Andy HoffmanAndy Hoffman
8,07631538
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
5
Pretty close. box1 comes before box2, so your query beginning at box2, or $(this), would return 0 results as find looks ahead in the DOM.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
Andy HoffmanAndy Hoffman
8,07631538
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
5
5
5
Pretty close. box1 comes before box2, so your query beginning at box2, or $(this), would return 0 results as find looks ahead in the DOM.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
Andy HoffmanAndy Hoffman
8,07631538
Pretty close. box1 comes before box2, so your query beginning at box2, or $(this), would return 0 results as find looks ahead in the DOM.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
Andy HoffmanAndy Hoffman
8,07631538
edited 1 hour ago
answered 1 hour ago
Andy HoffmanAndy Hoffman
8,07631538
answered 1 hour ago
Andy HoffmanAndy Hoffman
8,07631538
answered 1 hour ago
Andy HoffmanAndy Hoffman
8,07631538
8,07631538
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
thank you for your answer :)
– kk kk
1 hour ago
thank you for your answer :)
– kk kk
1 hour ago
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
5
Here $(this) is referring to box2 element.Only $('.box1 li').length is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});.list_3 {
color: green;
}<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
brkbrk
28.4k32143
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
5
Here $(this) is referring to box2 element.Only $('.box1 li').length is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});.list_3 {
color: green;
}<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
brkbrk
28.4k32143
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
5
5
5
Here $(this) is referring to box2 element.Only $('.box1 li').length is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});.list_3 {
color: green;
}<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
brkbrk
28.4k32143
Here $(this) is referring to box2 element.Only $('.box1 li').length is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});.list_3 {
color: green;
}<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});.list_3 {
color: green;
}<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});.list_3 {
color: green;
}<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
brkbrk
28.4k32143
edited 1 hour ago
answered 1 hour ago
brkbrk
28.4k32143
answered 1 hour ago
brkbrk
28.4k32143
answered 1 hour ago
brkbrk
28.4k32143
28.4k32143
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
thank you this works perfectly
– kk kk
1 hour ago
thank you this works perfectly
– kk kk
1 hour ago
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
4
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass() is invoked and this element does not have .box1 li. Thus find() is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
MamunMamun
29k71831
add a comment |
4
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass() is invoked and this element does not have .box1 li. Thus find() is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
MamunMamun
29k71831
add a comment |
4
4
4
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass() is invoked and this element does not have .box1 li. Thus find() is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
MamunMamun
29k71831
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass() is invoked and this element does not have .box1 li. Thus find() is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
MamunMamun
29k71831
edited 54 mins ago
answered 1 hour ago
MamunMamun
29k71831
answered 1 hour ago
MamunMamun
29k71831
answered 1 hour ago
MamunMamun
29k71831
29k71831
add a comment |
add a comment |
4
$(this).find will find the li in the div with box2 class which are not present. Instead check this in the div with box1 class and find the li elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
ellipsisellipsis
7,6962929
add a comment |
4
$(this).find will find the li in the div with box2 class which are not present. Instead check this in the div with box1 class and find the li elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
ellipsisellipsis
7,6962929
add a comment |
4
4
4
$(this).find will find the li in the div with box2 class which are not present. Instead check this in the div with box1 class and find the li elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
ellipsisellipsis
7,6962929
$(this).find will find the li in the div with box2 class which are not present. Instead check this in the div with box1 class and find the li elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
ellipsisellipsis
7,6962929
edited 21 mins ago
answered 1 hour ago
ellipsisellipsis
7,6962929
answered 1 hour ago
ellipsisellipsis
7,6962929
answered 1 hour ago
ellipsisellipsis
7,6962929
7,6962929
add a comment |
add a comment |
2
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
Sarabjit SinghSarabjit Singh
1169
add a comment |
2
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
Sarabjit SinghSarabjit Singh
1169
add a comment |
2
2
2
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
Sarabjit SinghSarabjit Singh
1169
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>$('.box2').addClass('list' + $('.box1 li').length);<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>$('.box2').addClass('list' + $('.box1 li').length);<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>answered 1 hour ago
Sarabjit SinghSarabjit Singh
1169
answered 1 hour ago
Sarabjit SinghSarabjit Singh
1169
answered 1 hour ago
Sarabjit SinghSarabjit Singh
1169
answered 1 hour ago
Sarabjit SinghSarabjit Singh
1169
1169
add a comment |
add a comment |
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1
Your
$(this)is not pointing to.box2as you expect– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to
.box2, hence not working as expected as there is no.box1after it.– LGSon
49 mins ago
@Mr.Alien A
console.log($(this)shows that$(this)is pointing to.box2. If you reverse the HTML structure ofbox1andbox2and change theJavaScripttoreturn 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start offind.– Andy Hoffman
44 mins ago
It would be great to add
$(document).ready(function(){, around your JQuery operations,– harish sharma
10 mins ago