Help with optimizing Oracle Query - nested with count
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I have 2 tables
Students and Cellphone
Columns in Students: StudentID, FNAME, PHONEID
Columns in Cellphone: PhoneID, Phonename
I want to create this
• Run a query to show the most popular phone used by students
My answer is
select D.phoneid, c.phonename, d.numberp
from
(select * from
(SELECT m.phoneid,
COUNT(*) AS numberp
FROM students m
GROUP BY m.phoneid
ORDER BY numberp DESC)
where rownum = 1) D, cellphone c
where d.phoneid = c.phoneid
Can this be optimized or a simpler way of achieving this?
May be using TOP ? or HAVING ? JOINS ?
join query count
asked 7 mins ago
Sneha AgrawalSneha Agrawal
1
New contributor
Sneha Agrawal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
0
I have 2 tables
Students and Cellphone
Columns in Students: StudentID, FNAME, PHONEID
Columns in Cellphone: PhoneID, Phonename
I want to create this
• Run a query to show the most popular phone used by students
My answer is
select D.phoneid, c.phonename, d.numberp
from
(select * from
(SELECT m.phoneid,
COUNT(*) AS numberp
FROM students m
GROUP BY m.phoneid
ORDER BY numberp DESC)
where rownum = 1) D, cellphone c
where d.phoneid = c.phoneid
Can this be optimized or a simpler way of achieving this?
May be using TOP ? or HAVING ? JOINS ?
join query count
asked 7 mins ago
Sneha AgrawalSneha Agrawal
1
New contributor
Sneha Agrawal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
0
0
0
I have 2 tables
Students and Cellphone
Columns in Students: StudentID, FNAME, PHONEID
Columns in Cellphone: PhoneID, Phonename
I want to create this
• Run a query to show the most popular phone used by students
My answer is
select D.phoneid, c.phonename, d.numberp
from
(select * from
(SELECT m.phoneid,
COUNT(*) AS numberp
FROM students m
GROUP BY m.phoneid
ORDER BY numberp DESC)
where rownum = 1) D, cellphone c
where d.phoneid = c.phoneid
Can this be optimized or a simpler way of achieving this?
May be using TOP ? or HAVING ? JOINS ?
join query count
asked 7 mins ago
Sneha AgrawalSneha Agrawal
1
New contributor
Sneha Agrawal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have 2 tables
Students and Cellphone
Columns in Students: StudentID, FNAME, PHONEID
Columns in Cellphone: PhoneID, Phonename
I want to create this
• Run a query to show the most popular phone used by students
My answer is
select D.phoneid, c.phonename, d.numberp
from
(select * from
(SELECT m.phoneid,
COUNT(*) AS numberp
FROM students m
GROUP BY m.phoneid
ORDER BY numberp DESC)
where rownum = 1) D, cellphone c
where d.phoneid = c.phoneid
Can this be optimized or a simpler way of achieving this?
May be using TOP ? or HAVING ? JOINS ?
join query count
join query count
asked 7 mins ago
Sneha AgrawalSneha Agrawal
1
New contributor
Sneha Agrawal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 7 mins ago
Sneha AgrawalSneha Agrawal
1
New contributor
Sneha Agrawal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 7 mins ago
Sneha AgrawalSneha Agrawal
1
New contributor
Sneha Agrawal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 7 mins ago
Sneha AgrawalSneha Agrawal
1
asked 7 mins ago
Sneha AgrawalSneha Agrawal
1
1
New contributor
Sneha Agrawal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Sneha Agrawal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Sneha Agrawal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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